Optics Flashcards

1
Q

What is the basic law of reflection?

A

The angle of incidence is equal to the angle of reflection (within the same medium).

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2
Q

When a light ray changes mediums from n1 to n2, how does it’s velocity and angle change when n1 < n2 and when n1>n2?

A

For n1<n2;
velocity decreases and the angle bends toward the normal

For n1>n2;
velocity increases and the angle bends away from the normal

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3
Q

What is a refractive index?

A

It is a measured factor of how light’s speed decreases in different mediums

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4
Q

What is a critical angle?

A

It is the incident angle at which a light ray at a boundary bends along the surface between two mediums. (Note: n2 < n1// initial n must be greater than the other)

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5
Q

What if the angle of incidence is greater than the critical angle?

A

The light undergoes total internal reflection and not refraction

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6
Q

Where is the focal point for a concave mirror and for a convex mirror?

A

For a concave mirror, it is in front of the mirror. (f is +’ve)
For a convex mirror it is behind the mirror. (f is -‘ve)

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7
Q

Where is the image if the object distance from a concave mirror is equal to the focal length?

A

The image is at infinity, it can’t be observed.

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8
Q

Where is the focal point on a converging lens?

A

The focal point is always opposite of where the rays enter the lens. (f is +ve)

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9
Q

In the Lensmaker’s equation, how does the radius of curvatures sign change depending on the face shape (concave or convex) and type (lens or mirror)?

A

For convex lens faces and concave mirror faces, the radius of curvature is positive.

For concave lens faces and convex mirror faces, the radius of curvature is negative.

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10
Q

What are spherical aberrations and what are solutions to them?

A

Spherical aberrations occur when a mirror can’t converge all the rays to focal point with precision. So parabolic mirrors or Schmidt corrector plates are used to fix the issue.

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11
Q

Why do chromatic aberrations occur and how can they be fixed?

A

Chromatic aberrations occur with white light being refracted. The various colours in have different refractive indexes so they bend at different angles. So a achromat, a pair of lenses with different dispersions, must be used to correct this.

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12
Q

What is a near point?

A

This is the closest distance our eyes can see an object clearly. Our eyes change curvature to see closer or further.

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13
Q

What’s the difference between Myopia and Hyperopia?

A

Myopia - seeing distant objects is difficult and blurry. Diverging lenses correct this issue.

Hyperopia - seeing close objects is difficult so converging lens is needed to correct it.

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14
Q

Describe a refracting telescope.

A

This is a lens system of two converging lens placed so focal points meet and form an observable image smaller than the object

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15
Q

Describe a reflecting telescope.

A

A spherical mirror bends light entering the telescope inward and has a plane mirror direct the light to an eye.

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