Numerical Flashcards

1
Q

You invest $100 in a risky asset with an expected rate of return of 10% and a standard deviation of 18% and a T-bill with a rate of return of 4%. The slope of the Capital Allocation Line formed with the risky asset and the risk-free asset is equal to _______

A

ERP / StdDev

For the Capital Allocation Line the risk free rate (T-bill at 4%).

To calculate the slope of the CAL, the numerator is:

E(r) of the risky asset (10%) minus the risk free rate (4%).

The denominator is the standard deviation of the risky asset (18%).

The resulting slope calculation is (10% - 4%) / 18% = .33

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2
Q

You invest $100 in a T-bill that pays 4% and a risky portfolio, P, with an expected return of 10% and a standard deviation of 18%. If you want to form a portfolio with a standard deviation of 13.5%, what percentages of your money must be invested in P and the T-bill, respectively?

A

The standard deviation of a portfolio comprising of y% in risky portfolio P and the remaining in the risk free asset:

New StdDev = StDev*(y)

  1. 5% = 18%*(y) Solving: y = 13.5% / 18% = 75%.
    * 75% of your money must be invested in the risky portfolio, and 25% in the T-bill.*
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3
Q

Suppose you buy 100 shares of Anushka.com at the beginning of year 1 for $42.

The stock price at the end of the year 1 is $46, the price is $54 at the end of year 2, the price is $62 at the end of year 3, and the price is $59 at the end of year 4.

If Anushka.com pays no dividends, what is the geometric mean return (annual) during the four-year period?

A

Calculate the return for each period (end - beg)/beg:

Year 1: (46-42)/42 = 9.52% +1 = 1.0952

Year 2: (54-46)/46 = 17.39% +1 = 1.1739

Year 3: (62-54)/54 = 14.81% +1 = 1.1481

Year 4: (59-62)/62 = -4.84% +1 = .9516

To calculate the Geometric Mean: Calculate the product of all of the returns –

1.0952*1.1739*1.1481*.9516 = 1.4047

Raise this result to the ¼ power, as there are four observations. Then subtract 1. This gives a result of 8.87%

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4
Q

Assume that all five portfolios below lie on the investment opportunity set of Two-risky assets (stock and bond), and one among them is the optimal portfolio.

PORTFOLOIO - Expected Return (%) Standard Deviation (%)

Portfolio A - 11.0 14.20

Portfolio B 9.5 11.70

Portfolio C 8.5 11.56

Portfolio D 10.0 12.25

Portfolio E 10.5 12.10

If the risk free rate is 5%, identify the optimal portfolio

A

For each portfolio, calculate the Sharpe ratio.

The portfolio with the highest Sharpe ratio is the optimal portfolio. Sharpe Ratio = (Expected Portfolio return – risk free rate) / Standard Deviation of the Portfolio

Portfolio E has the highest Sharpe Ratio: (10.5% - 5%) / 12.1% = .4545

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5
Q

Consider a portfolio that offers an expected return of 10% and a standard deviation of 16%. T-bills offer a risk-free 7% rate of return. Describe the entire range of A for which the risky portfolio is still preferred to bills. You may assume the common form of utility function: U = E(R) – (0.5*A*σ^2). Investors are risk averse.

A

The utility of the risk free rate is 7%.

Therefore, the utility acceptable with the risky portfolio needs to exceed 7%. To find the A value, we set U=7%.

Then, the equation is as follows:

rf = Er - (.5* A * StDv^2))

.07 = .1 – (.5*A*(.16^2))

–>

Solve for A –> A = .03 / .0128 = 2.34

–>

A value of A > 2.34 would cause the Utility of risky portfolio to be lower than 7%.

Therefore, the value of A < 2.34.

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6
Q

Consider two risky assets (A & B) that are perfectly negatively correlated. A has an expected rate of return of 10% and a standard deviation of 18%. B has an expected rate of return of 8% and a standard deviation of 24%. The weights of A and B in the minimum variance portfolio are _____ and _____, respectively.

A

The minimum variance that is possible when two risky assets are perfectly negatively correlated is zero. The standard deviation of the portfolio in this scenario is:

Standard Deviation of A* w1 - Standard Deviation of B * (1-w1) = 0

Substituting -

18*X - 24*(1-X) = 0

–>

18*X - 24 + 24X = 0

–>

42X = 24

–>

X=.57

The weight of A is .57. The weight of B is .43.

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