Nucleophilic Addition to Carbonyls (Aldehydes & Ketones) Flashcards
typical nucelophilic addition to carbonyl reaction scheme
- nucleophilic addition to carbonyl group
2. protonation of resulting anion
carbonyl electrostatics
large dipole
based on electrostatic attraction alone we’d expect electron rich nucleophile to attack the ∂+ C of C=O
carbonyl bonding
C and O are sp2 hybridised
thus O l.p.s are perpendicular to π system and reside in sp2 HAOs
largest coefficient in π* is on the C
so strongest interaction w/ nucleophile is with carbon
carbonyl angle of attack
typically observed ~107°
- ideal attack angle = >90° to C=O giving maximum orbital overlap as π* is slightly splayed out
- REPULSION between filled π bonding orbital electron density and Nu electron density forces Nu to attack at even more obtuse angle
carbonyl reactions to memorise
Hydride - NaBH4
Organometallics - C-metal
Water/Alcohols –> hydrates, hemiacetals and acetals
carbonyl + hydride theory
what is source of hydride and why?
while H- exists in NaH (sodium hydride), 1s and π* = rubbish orbital match:
- v. small
- high charge density
so H- only ever acts as BASE: 1s and σ* of H-X much better interaction
so best (& mildest) source of hydride = SODIUM BOROHYDRIDE (B-Hσ much better matched to π* than 1s)
carbonyl + hydride theory
what protonates anion?
what happens to BH3?
protonation: HX is usually a reaction solvent molecule e.g. MeOH
BH3: sp2 hybridised v. electron deficient has empty p orbital thus Lewis acid:
reacts w/ oxyanion just created or a molecule of solvent
–> tetravalent boron anion which can transfer a second hydride to another starting carbonyl molecule
THUS CAN USE <1 EQUIV. BOROHYDRIDE FOR REACTION TO TAKE PLACE (technically 1/4 moles of NaBH4 but painstaking and inefficient and NaBH4 inexpensive so rarely minimise amount used)
organometallics discussed in IA
C-metal bond is…
why are carbonyl+organometallics successful?
organomagnesium compounds (Grignard reagents) organolithium compounds
…covalent with ionic character
Li and Mg much less electronegative than C
∂- R-Li ∂+
∂- R-MgBr ∂+
so source of C-
Grignard synthesis
alkyl, aryl or vinyl (attached to double bond) halides (Br, Cl or I) with magnesium TURNINGS
- MAGNESIUM INSERTION into C-Hal bond
CH3-Br ——(Mg, Et2O)—–> CH3-MgBr
Et2O = diethyl ether = commonly called ether = non-reactive solvent
organolithium compound synthesis
alkyl, aryl or vinyl (attached to double bond) halides (Br, Cl or I) with 2 EQUIV. LITHIUM —> 1 EQUIV. organolithium + 1 EQUIV. LiHalide salt
e.g. CH3-Br —–(2xLi, ether(solvent))—-> CH3-Li + LiBr
aka LITHIUM HALOGEN EXCHANGE (Li-Hal exchange)
alkynyl organometallic synthesis
- using ALKYL organolithium/grignard
- using STRONG NITROGEN BASE, commonly sodium amide to make —≡≡≡(-)Na(+) + NH3(g)
commonly made by 2Na + 2NH3 —> 2NaNH2 + H2
reactions of organometallic key things to remember
organometallic are INCOMPATIBLE with water so done in 2 steps for carbonyl nucleophilic addition e.g.:
1. MeMgBr, 2. H2O
not all aldehydes and ketones form significant amounts of hydrate…
significant [ ]s of hydrate usually only formed from ALDEHYDES:
as we increase size of R group attached to C=O, hydrate becomes harder to form:
- moving from 120° to 109.5°
- larger R group = more STERIC CLASH in product than reactant so harder to form hydrate
- RING STRAIN FACTORS: hydrate formation favourable when ring strain is released (with DECREASED BOND ANGLE)
- electronic effects (beyond IA)
kinetic arguments (difficult initial attack as H2O = more statically hindered w/ R size, if R = EWG, faster C=O attack and increased ∂+ on C) can’t be used as we are discussing an equilibrium (thermodynamic result)
carbonyls+alcohols catalysis
- acid catalysts make carbonyl more electrophilic
- base catalysts make nucleophile more nucleophilic
increases rate of eqbm, not position of eqbm
acetal formation
every step of acetal formation is reversible
to push acetal through to completion, use excess alcohol and/or remove H2O byproduct from reaction mixture e.g. by distillation
CAN ONLY BE CATALYSED BY ACID - OH needs to be good leaving group for this reaction which can’t happen under basic conditions
protonation of hemiacetal makes OH a good leaving group