Nuclear Flashcards

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1
Q

Binding energy

A

The amount of energy required to split a nucleus into all its separate constituent nucleons. It is equivalent to the mass defect.
(Or the energy required to bind together the nucleons, where nuclei with higher binding energy per nucleon are more stable as more energy needed for separation)

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2
Q

Closest approach

A

A method of estimating a nuclear radius by firing an alpha particle at it. It involves calculating the distance at which all the alpha particle’s kinetic energy is converted to electric potential energy.

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3
Q

Contamination

A

The introduction of radioactive material to another object. The object is consequently radioactive.

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4
Q

Control rods

A

Rods found in nuclear reactors to absorb neutrons and control the rate of reaction. They can be raised or lowered depending on the rate required.

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5
Q

Critical mass

A

The smallest mass of fissile material required in a fission reactor for a chain reaction to be sustained.

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6
Q

Electron capture

A

A process that occurs in proton-heavy nuclei, in which an electron is drawn into the nucleus, causing a proton to transition into a neutron. An electron neutrino is also produced.

Z= 82. Z= 81
²⁰⁵Pb + e– → ²⁰⁵Tl + v(e)

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7
Q

Irridation

A

The exposure of an object to radiation. The exposed object does not become radioactive

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8
Q

Mass defect

A

The difference in mass between a nucleus and the sum of the masses of its constituent nucleons

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9
Q

Decay constant

A

The probability that a particular nucleus will decay per time (s^-1)
The fraction of the total number of nuclei that decay per second.

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10
Q

Rutherford conclusions

A

1) most alpha particles passed through undeflected → most atoms must be empty space.
2) many were deflected → must be part of an atom that’s positively charged.
3) very few were deflected backwards → the charged nucleus must be very small compared to the size of the atom.

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11
Q

Electron diffraction

A

• High speed electrons are fired at a thin sheet of material
• as they pass through the atoms they diffract, concentric circles is formed on a screen behind the material.
(More accurate)
Sintheta = (1.22lambda)/2R

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12
Q

1Bq

A

1 decay per second

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13
Q

Intensity unit

A

Wm^-2

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14
Q

Radioactive decay equations

A

N = Noe^-(lambda)t
Nuclei number
Activity
Mass
Count rate

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15
Q

Nuclear waste treatment

A

1) should be cooled in cooling ponds to reduce temps to safe levels
2) stored in thick (several metres) concrete containers deep underground for hundreds of years/vitrified
3) all handling should be done remotely

95% spent fuel rods (3% vol)
4% sludges and resins (7% vol)
1% clothes worn etc (90% vol)

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16
Q

Below iron
Above iron

A

Fusion
Fission

17
Q

Why does fusion release more energy

A

Due to the larger nucleus having a larger binding energy per nucleon.

18
Q

Density of a nucleus

A

P =m/v
m = 3Au (mass number x atomic unit)
V=4/3πr
R=RoA^⅓

Therefore density = 3Au/4π(RoA^⅓)³
=3u/4πRo³

Therefore density is independent of radius and a constant. As Ro = 1.05x10^-15. should always be x10^17 magnitude.

19
Q

Why is inverse square law not always accurate

A

1) dead time
2) may not be pure gamma, could have beta in it

20
Q

Explain why there is an imbalance in the number of neutrons and protons in a larger nucleus

A

More neutrons are needed to hold the nucleus together to add to binding force, to reduce repulsion between protons and therefore reduce instability

21
Q

Why are gamma rays useful for medical diagnosis

A

Low half life therefore doesn’t remain in body too long after medical diagnosis
High penetration therefore can leave body
Weakly ionising therefore less damage to body

22
Q

What provides evidence for the existence of:
Electrons
Energy levels in nuclei

A

1) existence of X-ray line spectra
2) existence of gamma radiation

23
Q

How to use R = RoA⅓

A

Ro is a constant and therefore can be worked out.
Or proportionality (R1/A⅓) = (R2/A⅓)
Therefore R1 = (A1/A2)⅓ x R2

24
Q

Benefits of nuclear power?

A

1) less pollution
2) little Co2 produced (not pollution)
3) high energy density

25
Q

Purpose of a moderator

A

To slow down fast neutrons produced during nuclear reactions. By slowing down these neutrons, the probability of their interaction with fissile material (like uranium-235 or plutonium-239) increases. This enhanced interaction improves the efficiency of the nuclear reaction, allowing sustained and controlled energy production. .

26
Q

Why does the number of collisions needed depend on the nucleon number of the moderator atoms?

A

Collisions are elastic
More nucleons = larger mass
Therefore less KE transferred to nucleus therefore more collisions are needed