Notes15 Flashcards

(41 cards)

1
Q

drawbacks of sn1 reactions

A

1) can form expected products
2) connectivities can change (alkyl/hydride shift)
3) can undergo elimination reactions

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2
Q

stabilizes tertiary carbocations

A

hyperconjugation

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3
Q

two major types of sn1 and e1 substrates

A

1) secondary and tertiary alkyl halides

2) secondary and tertiary alcohols

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4
Q

base is like…

A

a girl looking for a guy. Strong bases are the overly attached gf. Weak base is like a hookup

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5
Q

when there is a positive charge on carbon…

A

neighboring protons become highly acidic

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6
Q

saytzeffs rule

A

in elimination reactions, the product alkene with the most alkyl group connections wins out. MOST STABLE

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7
Q

relative stabilities of alkenes measured by

A

heat of hydrogenation. relationship inverse. the more heat, the greater potential energy stored

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8
Q

source of stability in trans

A

due to no steric effects

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9
Q

saytzeffs rule practical usage

A

count number of non-H bonds attached to vinylic carbon

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10
Q

dehydrohalogenation reaction

A

lose hydrogen and halogen in reaction

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11
Q

E2 mechanism

A

anti H (to halogen) is taken by strong base, electrons left over. New bond releases halogen

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12
Q

regioselective

A

produce one constitutional isomer predominantly

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13
Q

favors Zaitsev product

A

small bases

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14
Q

favors Hoffman product

A

large bases

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15
Q

difference between constitutional and structural isomers

A

isomers - same formula and weight
constitutional - DIFFERENT connectivities
stereoisomers - same connectivities, different3D orientation
diastereomers - cis/trans (sp2)
enantiomers - chirality (sp3)

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16
Q

key pattern of elimination reaction

A

1) break 2 adjacent sigma bonds

2) form new pi bond

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17
Q

sn2 stereochemistry

A

100% inversion

18
Q

sn2 substrate

A

less steric hinderance. nucleophile needs to get close in

19
Q

sn2 nucleophile

A

needs strong, small nucleophile

20
Q

sn2 solvent

A

aprotic polar. (transition state is apolar)

21
Q

sn1 stereochemistry

22
Q

sn1 substrate

A

tertiary>2>1 because carbocation stabilization

23
Q

sn1 solvent

A

polar protic. why? stabilizes leaving group and polar transition states

24
Q

e2 stereochemistry

A

C-H and C-X bonds must be anti

25
e2 substrate
less steric hindrance the better. for primary need hindered base to prevent reaction with protons
26
e2 base
need strong base
27
e2 solvent
polar protic or aprotic
28
e1 stereochemistry
mixture of E and Z
29
e1 substrate
steric hinderce good. wants a stable carbocation
30
e1 base
generally weak
31
e1 solvent
polar protic
32
e2 clues
1) rate law | 2) stereochemisty - anti needed
33
e1 mechanism
1) leaving group leaves and forms carbocation | 2) H is removed to form alkene
34
cis isomerism on rings
axial/equatorial if bonds between them are odd
35
charge nucleophiles/bases prefer rxn
prefer "2" reactions
36
sn1 vs sn2 transition states
sn1: two transition states-carbocation and bond formation sn2: only one transition states
37
molecularity
number of species colliding in the rate determining step
38
factors that influence nucleophilic substitution reactions
1. steric accessiblity 2. stability of sn1 carbocation 3. nature of nucleophile 4. type of solvent used 5. nature of the leaving group
39
secondary carbons... sn1 vs sn2
these are a little tricky, as they can do both. look for resonance stabilized carbocations and other substitution reactions
40
neutral nucleophiles in sn2 rxns
only conjugate base will be attached. lose proton
41
solvolysis
in sn1 rxns, dissociation of organic compounds into ions