Notes15 Flashcards

1
Q

drawbacks of sn1 reactions

A

1) can form expected products
2) connectivities can change (alkyl/hydride shift)
3) can undergo elimination reactions

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2
Q

stabilizes tertiary carbocations

A

hyperconjugation

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3
Q

two major types of sn1 and e1 substrates

A

1) secondary and tertiary alkyl halides

2) secondary and tertiary alcohols

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4
Q

base is like…

A

a girl looking for a guy. Strong bases are the overly attached gf. Weak base is like a hookup

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5
Q

when there is a positive charge on carbon…

A

neighboring protons become highly acidic

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6
Q

saytzeffs rule

A

in elimination reactions, the product alkene with the most alkyl group connections wins out. MOST STABLE

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7
Q

relative stabilities of alkenes measured by

A

heat of hydrogenation. relationship inverse. the more heat, the greater potential energy stored

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8
Q

source of stability in trans

A

due to no steric effects

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9
Q

saytzeffs rule practical usage

A

count number of non-H bonds attached to vinylic carbon

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10
Q

dehydrohalogenation reaction

A

lose hydrogen and halogen in reaction

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11
Q

E2 mechanism

A

anti H (to halogen) is taken by strong base, electrons left over. New bond releases halogen

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12
Q

regioselective

A

produce one constitutional isomer predominantly

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13
Q

favors Zaitsev product

A

small bases

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14
Q

favors Hoffman product

A

large bases

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15
Q

difference between constitutional and structural isomers

A

isomers - same formula and weight
constitutional - DIFFERENT connectivities
stereoisomers - same connectivities, different3D orientation
diastereomers - cis/trans (sp2)
enantiomers - chirality (sp3)

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16
Q

key pattern of elimination reaction

A

1) break 2 adjacent sigma bonds

2) form new pi bond

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17
Q

sn2 stereochemistry

A

100% inversion

18
Q

sn2 substrate

A

less steric hinderance. nucleophile needs to get close in

19
Q

sn2 nucleophile

A

needs strong, small nucleophile

20
Q

sn2 solvent

A

aprotic polar. (transition state is apolar)

21
Q

sn1 stereochemistry

A

racemization

22
Q

sn1 substrate

A

tertiary>2>1 because carbocation stabilization

23
Q

sn1 solvent

A

polar protic. why? stabilizes leaving group and polar transition states

24
Q

e2 stereochemistry

A

C-H and C-X bonds must be anti

25
Q

e2 substrate

A

less steric hindrance the better. for primary need hindered base to prevent reaction with protons

26
Q

e2 base

A

need strong base

27
Q

e2 solvent

A

polar protic or aprotic

28
Q

e1 stereochemistry

A

mixture of E and Z

29
Q

e1 substrate

A

steric hinderce good. wants a stable carbocation

30
Q

e1 base

A

generally weak

31
Q

e1 solvent

A

polar protic

32
Q

e2 clues

A

1) rate law

2) stereochemisty - anti needed

33
Q

e1 mechanism

A

1) leaving group leaves and forms carbocation

2) H is removed to form alkene

34
Q

cis isomerism on rings

A

axial/equatorial if bonds between them are odd

35
Q

charge nucleophiles/bases prefer rxn

A

prefer “2” reactions

36
Q

sn1 vs sn2 transition states

A

sn1: two transition states-carbocation and bond formation
sn2: only one transition states

37
Q

molecularity

A

number of species colliding in the rate determining step

38
Q

factors that influence nucleophilic substitution reactions

A
  1. steric accessiblity
  2. stability of sn1 carbocation
  3. nature of nucleophile
  4. type of solvent used
  5. nature of the leaving group
39
Q

secondary carbons… sn1 vs sn2

A

these are a little tricky, as they can do both. look for resonance stabilized carbocations and other substitution reactions

40
Q

neutral nucleophiles in sn2 rxns

A

only conjugate base will be attached. lose proton

41
Q

solvolysis

A

in sn1 rxns, dissociation of organic compounds into ions