Non-Wolsey Study Flashcards

1
Q

Atomic mass is the

A

weighted average mass of an atom compared to C-12 (having 12 units)

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2
Q

Molecular mass is

A

the mass of a molecule compared to C-12 which has 12 units on the scale

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3
Q

Formula mass is

A

the mass of one formula unit of a compound compared to C-12 having 12 units on the scale

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4
Q

Isotopic mass

A

Mass of a particular isotope of an element compared to C-12 having 12 units on the scale

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5
Q

Define the term “Mole”

A

The amount of substance that has the same number of particles as there are atoms in exactly 12g of carbon-12 isotope.

1 Mole (mol) has exactly 6.02x10/\23 particles.

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6
Q

What is Avogadro’s constant

A

The number of atoms, ions, molecules or electrons in a Mole = 6.02x10/\23

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7
Q

Define “Empirical Formula”

A

gives the simplest ratio of different atoms present in a molecule

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8
Q

Define “Molecular Formula”

A

gives actual numbers of each type of atoms in a molecule

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9
Q

What is the triangle formula involving Mass, Molar Mass and Moles

A

M=m/n

Molar mass = Mass/Number of Moles

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10
Q

How do you calculate the volume of a gas at room temp.?

A

Moles x 24

At room temperature

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11
Q

What is the unit of volume of gas

A

dm/\3

1000cm/\3 = 1dm/\3

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12
Q

Triangle formula for concentration

A

C=n/V

Concentration = Number of Moles/Volume

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13
Q

Unit of concentration

A

mol dm/-3

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14
Q

What is this unit for: mol dm/-3

A

Concentration

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15
Q

Steps to calculate relative atomic mass from isotpoic mass and abundance

A
  1. Multiply each isotopic mass with its abundance %
  2. Add all the figures together
  3. Divide by 100
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16
Q

The formula for __ ______ compound is always its empirical formula

A

an ionic

17
Q

The molecular formula for simple inorganic compounds are often…

A

the same

18
Q

Organic molecules often have ________ empirical and molecular formulae

A

different

19
Q

Organic compounds must be very ____ for combustion to calculate _______ ________

A

very pure, to calculate empirical formula

20
Q

Steps for Empirical formula of magnesium oxide- compositional mass (0.486g)

A
  1. Burn known mass of Mg in excess oxygen (0.486g)
  2. Record the mass of Mg oxide formed (0.806g)
  3. Calculate the mass of the oxygen (0.806g - 0.486g) = 0.320g
  4. Calculate the mole ratio of Mg to O
    Moles of Mg = 0.486/24.3 mol/-1 = 0.0200
    Moles of O = 0.320/16.0 mol/-1 = 0.0200

Simplest ratio is 1:1 - Therefore empirical formula is MgO

21
Q

Steps for empirical formula - combustion

A
  1. Note the mass of each element.
  2. Divide by atomic masses.
  3. Divide both by lowest figure.
  4. Empirical formula is the lowest whole number ratio.
22
Q

What are spectator ions

A

Ions in an ionic reaction that do not interact - they are not included in ionic equations.

23
Q

Balancing/writing ionic equations - Steps

A
  1. Write the full balanced equation
  2. Write down the ions present. (Any compounds are broken down into each element, and their charges are found by looking at the periodic table. Grp 1 = +, Grp 2 = 2+, Grp 6 = 2-, Grp 7 = -.
  3. Cancel out ions that appear the same on each side of equation (spectator ions)
  4. Re-write equation without the spectator ions
24
Q

Steps for calculating concentration when given mass in g and volume in cm/\3.

A
  1. Change g to mol (g/Mr)
  2. Change cm3 to dm3 (cm/1000)
  3. Calculate concentration:

Number of moles in solute (mol)
——————————————- = concentration (mol dm3)
Volume of solution (dm-3)

25
Q

Steps for calculating mass from concentration

A
  1. Re-arrange concentration equation to find number of moles (mol)
    n (mol) = concentration (mol dm-3) x volume (dm3)
  2. Multiply moles of solute by its molar mass
    m of solute (g) = n (mol) x M (g mol-1)
26
Q

Calculate mole ratio

A

mass/atomic mass

Divide both answers by the smallest answer and that is the mole ration.

Usually like them both to be whole numbers