Network Location Problems Flashcards
Eccentricity eG(v)
The maximum distance of a vertex from v. That is, e(v) is the distance from v to a vertex furthest from V.
Radius rad(G)
Minimum eccentricity amoung vertices of G
Diameter diam(G)
Maximum eccentricity
Central vertex
Vertex whose eccentricity is equal to the radius
Peripheral vertex
Vertex whose eccentricity is equal to the diameter
Theorem 6.1
For every connected, unweighted graph G satisfying the triangle inequality it holds that rad(G)<=diam(G) <=2rad(G)
Theorem 6.3
Let T be an unweighted tree of order p>=3 and let T’ be the tree formed by pruning away all the leaves of T. Then C(T) = C(T’)
Algorithm 6.1 (Centre of unweighted tree)
All leaves of 1st layer. If no more leaves left - - done If more leaves, repeat Left with 1 or 2 vertices c(G) =
Classical median M(G)
The subgraph of G induced by all vertices v in V(G) which achieve a minimum value for the sum total of the distance from themselves to all other vertices.
General Centre
A vertex location in the graph at which a facility may be placed to supply some service to any point on an edge/ arc of the graph if the objective is to minimise the maximal potential distance that a user of the facility will have to travel in order to make use of the facility
General centre
Not done😅
F-point
The point on the arc (u, v) /edge (uv) at a distance fw(u,v) from the vertex u and at a distance (1-f)w(u,v) from the vertex v, for any f from 0 to 1
Vertex to edge distance d~(i, uv)
Distance from a vertex i to an f-point on the edge uv
(d(i, u) +d(i, v) +w(uv)) /2
Vertex-to-arc distance d~(i, (u, v))
d~(i, (u, v)) =d(i, u) +w(u, v)
Absolute centre
Arbitrary point location on any edge/ arc of the graph at which a facility may be placed to supply some service to any vertex of the graph so that the maximum distance from the supply point to a demand vertex is minimised