Семестр Nо 2 В -2 Flashcards

1
Q

CuCoNi2S4 -> Cu2O3, [Ni(NH3)6] I2

A

CuCoNi2S4 + O2 -> Cu2O + NiO + Co3O4 + SO2

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2
Q

Получение CuI

A

1) Cu2O + NH4OH (конц) = Cu(NH3)4(H2O)22

2) [Cu(NH3)4(H2O)2] (OH)2 + HCl = CuCl2 + NH4Cl + H2O

3) CuCl2 + NaOH = Cu(OH)2 + NaCl

4) Cu(OH)2 + OHCH2-(CH)n-COH = OHCH2-(CH)n-COOH + Cu2O + H2O

5) Cu2O + HI = CuI

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3
Q

Разделение Co3O4 и NiO

A

Co3O4 + HCl = CoCl2 + Cl2 + H2O

NiO + HCl = NiCl2 + H2O

CoCl2 + NaOH (изб)= [Co(NH3)4]Cl2 + NaCl

NaCl
NiCl2 + NaOH(изб)= Ni(OH)2 (осадок) + NaCl

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4
Q

Ni(OH)2 -> [Ni(NH3)6]I2

A

Ni(OH)2+H2O+HI= [Ni(H2O)6]I2

[Ni(H2O)6]I2 + NH4OH (изб) = [Ni(NH3)6]I2 + H2O

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