Семестр Nо 2 В -2 Flashcards
1
Q
CuCoNi2S4 -> Cu2O3, [Ni(NH3)6] I2
A
CuCoNi2S4 + O2 -> Cu2O + NiO + Co3O4 + SO2
2
Q
Получение CuI
A
1) Cu2O + NH4OH (конц) = Cu(NH3)4(H2O)22
2) [Cu(NH3)4(H2O)2] (OH)2 + HCl = CuCl2 + NH4Cl + H2O
3) CuCl2 + NaOH = Cu(OH)2 + NaCl
4) Cu(OH)2 + OHCH2-(CH)n-COH = OHCH2-(CH)n-COOH + Cu2O + H2O
5) Cu2O + HI = CuI
3
Q
Разделение Co3O4 и NiO
A
Co3O4 + HCl = CoCl2 + Cl2 + H2O
NiO + HCl = NiCl2 + H2O
CoCl2 + NaOH (изб)= [Co(NH3)4]Cl2 + NaCl
NaCl
NiCl2 + NaOH(изб)= Ni(OH)2 (осадок) + NaCl
4
Q
Ni(OH)2 -> [Ni(NH3)6]I2
A
Ni(OH)2+H2O+HI= [Ni(H2O)6]I2
[Ni(H2O)6]I2 + NH4OH (изб) = [Ni(NH3)6]I2 + H2O