mse 200 exam 2 Flashcards

1
Q

Shear stress

A

σ = F / Ao

stress horizonally rather than vertically (tensile strength)

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1
Q

Tensile strength

A

σ = F/Ao

tensile strength = force / cross sectional area

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2
Q

Elastic deformation

A

Non permanent and reversable

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3
Q

yield strength

A

stress at which noticable plasic deformation has occured

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4
Q

plastic deformation

A

process in which the object due to applied force changes its size or shape in a way that is not reversible

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5
Q

Slip

A

Movement of dislocations in materials under applied stress and causes deformation

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6
Q

What affects slip

A
  • crystal structure of material
  • temperature of material
  • presence of barriers (grain boudnaries, point defects, impurities
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7
Q

what does introducing slip barriers do

A

strengthen material

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8
Q

Comparison of discolations and crystal sturctures

A

FCC: many close-packed planes/directions
HCP: only 1 plane, 3 directions
BCC: None

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9
Q

HCP has fewer slip planes and are more ____

A

brittle

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10
Q

Ductility

A

amount of plastic deformation at failure

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11
Q

ductility percent elongation

A

%EL = (lf-l0)/lo X 100

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12
Q

ductility percent reduction in area

A

%RA = (Ao-Af)/Ao x 100

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13
Q

resilience

A

ability of a material to absorb energy during elastic deformation

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14
Q

linear stress-strain curve formula

A

Ur = 1/2(σy)(ey)

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15
Q

Toughness

A

amount of energy absorbed before fracture

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16
Q

how to measure toughness

A

approximate area under the stress-strain cruve at fracture point

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17
Q

hardness

A

measure of resistnace to surface plastic deformation - dent or scratch

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18
Q

safety factor

A

σw = σy/N
σw = working stress: F/A
σy = yield strength

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19
Q

dislocation density

A

total dislocation length/unit volume

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20
Q

edge dislocation motion

A

dislocation line moves in the same direction as force, perpendicular to t

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21
Q

screw dislocation motion

A

perpendicular to force
if force is -> screw spins clockwise

22
Q

FCC slip system

A

slip plane: {111}
slip direction: (110)
number of slip systems: 12

23
Q

BCC slip system

A

slip plane: {110}
slip direction: (111)
number of slip systems: 12/24

24
Q

more active slip systems means

A

more ductile material

25
Q

required tensile strength to cause yielding

A

σy = Tcrss/Tr

Tr = σcosλcosΦ

26
Q

resolved shear stress

A

Tr = σcosλcosΦ

27
Q

if resolved shear stress < critical resolved shear stress..

A

no yielding

28
Q

what are the 3 primary strengthening mechanics

A

grain size reduction, solid solution strengthening, cold working

29
Q

as %CW increases..

A

yield strength ( σy) increases
tensile strength increases
ductility decreaes

30
Q

heating(annealing)

A

removes effects of cold working

31
Q

3 annealing stages

A

Recovery, recrysallization, grain growth

32
Q

annealing causes tensile strength to ____ and ductility to _____

A

decrease. increase

33
Q

3 types of failure

A

fracture, fatigue, creep

33
Q

fracture: brittle vs ductile

A

brittle: little or no plastic deformation, rapid crack propagation, fails without warning
ductile: significant plastic deformation, slow crack propagation, fails with warning

34
Q

stress at crack tip formula

A

σm = 2σo(a/Pt)^(1/2)
σm = stress at crack tip
σo = applied stress
a = length of crack
Pt = radius of curvature

35
Q

a value for internal crack and external crack

A

2a and a

36
Q

fracture toughness formula

A

Kc = Yσcsqrt(pia)
kc = fracture toughness
Y = dimensionless parameter
σc = critical stress
a = crack length

37
Q

fatigue failure

A

failure under lengthy period of repeated stress or strain cycling

38
Q

3 general tecniques to improve fatigue life

A
  1. reduce magnitude of mean stress
  2. surface treatments
  3. design changes
39
Q

creep

A

measure deformation vs time at constant stress

40
Q

3 stages of creep

A
  1. primary creep
  2. secondary creep
  3. tertiary creep
41
Q

primary creep slope ____ with time

A

decreases

42
Q

secondary creep slope ____

A

constant with time

43
Q

tertiary creep slope ____ with time

A

increases

44
Q

time to rupture

A

T(C+logtr)=m

T = temperature
C = constant, normally 20
tr = time to failure (rupture(
m = function of applied stress

45
Q

eutectic

A

liquid transforms into 2 solids

46
Q

eutectoid

A

one solid phase transforms into 2 other solid phases

47
Q

peritectic

A

liquid and one solid phase transform to a second solid phase

48
Q

austenite (y) to pearlite

A

slow cool

49
Q

austenite (y) to bainite

A

moderate cool

50
Q

austenite (y) to martensite

A

rapid quench

51
Q

martensite to tempered martensite

A

reheat