Motion Graphs Flashcards

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1
Q

A speed is a ‘scalar quantity.’ What does this mean?

A

A speed has a magnitude (a number and unit) but no direction.

So ‘4 m/s’ is a speed.

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2
Q

Which of the following is a speed?

A. 0.8 m/s to the right

B. 15 seconds

C. 10 m/s² downwards

D. 3.2 m/s

A

Only D is a speed.

(A is a velocity, B is a time, C is an acceleration)

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3
Q

A velocity is a ‘vector quantity.’ What does this mean?

A

A velocity has a magnitude AND a direction.

  • So ‘4 m/s to the left’ is a velocity.*
  • The magnitude is 4 m/s, the direction is ‘to the left.’*
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4
Q

Which of the following is a velocity?

A. 10 m/s² downwards

B. 15 seconds

C. 3.2 m/s

D. 0.8 m/s to the right

A

Only D could be a velocity.

(A is an acceleration, B is a time, C is a speed)

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5
Q

What are the units of acceleration?

A

The units of acceleration are m/s²

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6
Q

Which of the following is an acceleration?

A. 15 seconds

B. 10 m/s² downwards

C. 3.2 m/s

D. 0.8 m/s to the right

A

Only B is an acceleration.

(A is a time, C is a speed, D is a velocity)

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7
Q

The distance-time graph for a car is shown here.

What does the graph tell you about the car’s motion?

A

The car is not moving

OR

The car’s speed is zero.

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8
Q

The distance-time graph for a horse is shown here.

What does the graph tell you about the horse’s motion?

A

The horse is moving at a constant speed.

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9
Q

The distance-time graphs for two kittens are shown here.

Which kitten has the higher speed, A or B?

A

Kitten A is moving with a higher speed.

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10
Q

What feature of a distance-time graph indicates an object’s speed?

A

The gradient

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11
Q

The distance-time graphs for two kittens are shown below.

Explain how you can tell that kitten A is moving faster than B.

A

Graph A is steeper than B.

Graph A has a bigger gradient than B.

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12
Q

The distance-time graphs for two mice are shown below.

Which has the higher speed, mouse A or mouse B, and how can you tell?

A

Mouse B has the higher speed,

since the gradient of graph B is greater than graph A

OR

since graph B is steeper than graph A

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13
Q

This is the velocity-time graph for a camel.

Describe the motion of the camel.

A

The camel’s speed is increasing

OR

The camel is accelerating

OR

The camel’s velocity is increasing

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14
Q

This is the velocity-time graph for a camel.

What feature of the velocity-time graph could be used to calculate the camel’s acceleration?

A

The gradient

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15
Q

Describe the motion of a shark, whose velocity-time graph is shown here.

A

The shark is moving with constant velocity

OR

The shark is moving with zero acceleration

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16
Q

A buzzard’s velocity-time graph is shown here.

Describe the buzzard’s motion.

A

The buzzard is decelerating

OR

The buzzard is slowing down

OR

The buzzard’s speed/velocity is decreasing

17
Q

Here are the velocity-time graphs for two unicycling clowns, A and B.

Describe the motion of the two clowns. [2 marks]

A

The clowns are moving at a constant velocity. [1 mark]

Clown A is moving faster/with greater velocity than clown B. [1 mark]

18
Q

The distance time graphs for two goldfish are shown below.

How does the motion of goldfish A compare to the motion of goldfish B?

A

Goldfish A has a greater acceleration (than goldfish B)

19
Q

The velocity-time graphs for two snails are shown below.

Which snail has the greater acceleration, and how can you tell? [2 marks]

A

Snail B has the greater acceleration [1 mark]

Since the gradient of graph B is greater than A [1 mark]

OR

Since the graph B is steeper than A [1 mark]

20
Q

What feature of this velocity-time graph shows the distance travelled?

A

The area under the graph shows the distance travelled.

21
Q

What feature of this velocity-time graph shows the distance travelled?

A

The area under the graph shows the distance travelled.

22
Q

This is the velocity-time graph for a mongoose.

Calculate the mongoose’s acceleration.

A

Acceleration = change in velocity ÷ change in time

OR a = Δv ÷Δt

so a = 15 ÷ 3

= 5 m/s²

23
Q

This is the velocity-time graph for a tugboat.

Calculate the tugboat’s acceleration.

A

Acceleration = change in velocity ÷ change in time

OR a = Δv ÷Δt

so a = -6 ÷ 3

= -2 m/s²