Motion Flashcards

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1
Q

State the word equation for average speed

A
  • average speed = distance travelled / time taken
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2
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3
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4
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5
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6
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7
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8
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9
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10
Q

State the symbol equation for average speed

A
  • v = delta x / delta t
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11
Q
A
  • Graphs of distance against time are used to represent the motto of objects
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12
Q
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13
Q
A
  • Distance is plotted on the y-axis
  • Time is plotted on the x-axis
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14
Q
A
  • In a d-t graph, a stationary object is represented by a horizontal straight line
  • An object moving at a constant speed is represented by a straight, sloping line
  • The gradient of that line is equal to the the speed of the object
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15
Q

Define instantaneous speed

A
  • The speed of the car over a very short interval of time
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16
Q

How is the instantaneous speed of a particular time found?

A
  • By drawing the tangent to a d-t graph then determining the gradient of the tangent
  • The greater the gradient, the greater the instantaneous speed
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17
Q

What is the direction of instantaneous velocity?

A
  • Tangential to the path
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18
Q

Describe displacement

A
  • vector quantity with magnifier and direction
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19
Q

Describe distance

A
  • Scalar quantity,
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20
Q

How is speed calculated

A
  • Speed is scalar quantity calculated from distance
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21
Q
A
  • Velocity is a vector quantity calcuetd from displacvtemtn
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22
Q

State the word equation for average velocity

A
  • average velocity = change in displacement / time taken
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23
Q

State the symbol equation for average velocity

A

v = delta s / delta t

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24
Q
A
  • graphs of displacement against time are used to represent the motion of objects
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25
Q
A
  • Displacement is plotted on the y axis
  • Time is plotted on the x axis
26
Q
A
  • If a car is travelling at a constant velocity, the line is sloping upwards
  • For the displacement of the car remains constant, it is horizontal, therefore the car must be stationary
    If there is a negative slow, the displacement of the car is getting smaller with time, car must be retiring to a constantly velocity
27
Q
A
  • You can determine the velocity of an object from the gradient
  • If not a straight line draw a tangent to determine instant velocity
28
Q

Define acceleration

A
  • Rate of change of velocity
29
Q

State the word equation for acceleration

A
  • acceleration = change in velocity / change in time
30
Q

State the symbol equation for acceleration

A
  • a = delta v / delta t
31
Q

State the unit of acceleration

A

ms-2

32
Q

What is a negative acceleration often called?

A
  • deceleration
33
Q

Is acceleration a scalar or vector quantity?

A
  • Determined from velocity, therefore vector
  • Has magnitude and direction
34
Q
A
  • in a velocity time graph - y axis represents velocity
35
Q
A
  • acceleration = gradient of velocity time graph
36
Q
A
  • A straight line of constant positive gradient = constant acceleration
  • straight line of zero gradient= constant velocity or zero acceleration
  • a straight line of constant negative gradient : constant deceleration
  • curve with a changing gradient : accerleration is changing
37
Q
A
  • Tachographs record the speed and distance travelled by a vehicle
38
Q
A
  • change in displacement to equal to area under the graph
39
Q
A
  • when acceleration is constant, displacement is easy to calculate because the areas can be broken down into rectangles and right angle triangles
40
Q
A
  • for non linear velocity time graphs you cam determine the area under the graph by counting squares
41
Q
A
  • need four equations to calculate quantities involving motion in a straight line at a constant acceleration (SUVAT)
42
Q

velocity time graph equations from the graph

A

Gradient = (v-u)/t
Area = 1/2 x (v-u) x t - rectangular area
area = u x t - triangular area

43
Q

state

A

v = u + at

44
Q

equation without v
substitute v-u = at into area of a triangle expression

A

s = ut +1/2at^2

45
Q

equation without a
if u treat area under graph as area of trapezium and use u and v as parallel side of trapezium and t as perpendicular separation

A

s = 1/2 (u+v)t

46
Q

equation without t

A

v2 = u2 + 2as

47
Q

how do u get v2 = u2 +2as

A

t = v-u / a
s = 1/2 (u+v) x (v-u) /a

48
Q

Define stopping distance

A
  • The total distance travelled from when the driver first sees a reason to stop, to when the vehicle stops
49
Q

State the two components of stopping distances

A
  • Thinking distance
  • Braking distance
50
Q

Define thinking distance

A
  • The distance travelled between the moment when you first see a reason to stop, the moment when you use the brake
51
Q

Define braking distance

A
  • The distance travelled from the time the brake is applied until the vehicle stops
52
Q

State some factors that influence stopping distance

A
  • Speed of vehicle
  • The condition of brakes, tyres and roads
  • Weather conditions
  • Alertness of drivers
53
Q

State the word equation for thinking distance

A
  • thinking distance = speed x reaction time
54
Q
A
  • The greater the speed or reaction time, the further a vehicle will travel before its drivers applies the brakes
55
Q
A
  • Assuming a constant the reaction time of 0.67s the thinking distance will be about 21m
    uk national speed limit of 70mph
56
Q
A

in the uk Highway Code the braking distance at 30mph is shown as 14m
if you assume constant deceleration from 14.3 to 0 ms-1 you can use one of the equations of motion to determine the magnitude of the deceleration

57
Q
A

58
Q

3.7

A
59
Q

3.8

A
60
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A
61
Q
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62
Q
A