molecular recognition Flashcards

1
Q

what is the affinity of a ligand for its receptor

A

equilibrium between unbound ligand protein complex and unbound ligand and protein/equilibrium measurement equal to the free energy difference (∆G=-RTlnKa)

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2
Q

explain the things in ∆G=-RTlnKa

A

∆G=free energy
R=gas constant (8.315 j/k/mol)
T=temperature in k
Ka=[complex]/[ligand][receptor]

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3
Q

what is the equation for Ka

A

[complex]/[ligand][receptor]

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4
Q

what is the equation for Kd

A

1/Ka

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5
Q

what is the equation for ∆G when using Kd

A

∆G=RTlnKd

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6
Q

what is Kd

A

inhibition constant=Ki

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7
Q

what is IC50 and what does it depend on

A

IC50=concentration of an inhibitor required to displace 50% of another ligand

-depends on the affinity of the displaced ligand to the receptor

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8
Q

what is the equation for Ki that relates to IC50

A

Ki=IC50/(1+[L]/Kd)

[L]=ligand being displaced

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9
Q

in ∆G = ∆H – T∆S what would a more negative ∆G mean

A

higher affinity, smaller Ki

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10
Q

what is Kon and Koff

A

rates going in and out of the bound state

(Ka and Kd are the ratio of these rates)

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11
Q

how to calculate Ka and Kd from Kon and Koff

A

Ka=Kon/Koff

Kd=Koff/Kon

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12
Q

what does a higher and lower Koff mean

A

higher=faster unbinding so it doesnt bind as tightly

lower=slower unbinding, stronger binding, reaches higher saturation

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13
Q

half life equation

A

t/2 or ln(2)k

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14
Q

what are the main components of partitioning of ∆G when splitting the free energy difference and whats the equation

A

main components=electrostatic interactions, lipophilicity/hydrophobicity, shape complementarity

∆G=∆G (trans+rot) + ∆G (conf) +∆G (polar) +∆G (hydrophob) + ∆G (vdw)

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15
Q

explain ∆G (trans+rot)

-describe the movement of ligands in unbound and bound states

A

-in free unbound state, both receptor and ligand are able to rotate and translate freely, free movement reduced/inhibited when binding

-loss of freedom unfavourable, ∆S lowered, ∆G increased

-∆G trans+rot always present, cant be reduced by ligand design

-entropic cost of binding only counts once in drugs with multiple binding sites in receptor (multivalent avidity) (?)

-if drug has multiple binding sites to multiple sites in receptor then the entropic cost of binding only counts once

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16
Q

explain ∆G (conf)

-what is it, describe the rotations/conformations of a ligand, how to avoid large conformational penalties on binding

A

∆G (conf)=conformational changes of ligand and receptors

-ligands are flexible and constantly change conformation by rotations around a single bond, rotations are frozen when binding

-possible to design ligand to reduce energy costs (1-6 kj/mol/rotation) by reducing flexibility eg, replace single bonds by double bonds)

-rearrangement of ligand from global energy minimum conformation to its bioactive conformation (?)

-to avoid large conformational penalties on binding, make the ligand rigid

-conformation rearrangements in ligands also have to occur in receptor

17
Q

explain ∆G polar

-what is the free energy due to

A

-free energy due to interactions of polar side chain atoms, of C=O and NH backbone atoms and indirect interactions mediated by water

-electrostatic interactions and hydrogen bonding

strength of any electrostatic interaction:

Epolar=q1 q2 / ε r0

q1 and q2= ion-ion interactions or partial charges
ε= dielectric constant
r0= distance between the charges

-hydrogen bond is also electrostatic interaction between a H atom bound to an electronegative atom and an electronegative hydrogen bnod acceptor atom (X-H-A), hydrogen bonds are highly orientation dependent, max 180 degrees

-a ligand that hydrogen bonds the water but does not hydrogen bond to the protein when buried is unfavourable, an unpaired hydrogen bond for a neutral substituent costs around 4 kJ/mol, and around 16 kJ/mol for a charged one

-successful H-bonding in the cavity contributes between 2 and 6.5 kJ/mol for a neutral substituent, and 10 to 20 kJ/mol for a charge assisted bond or salt bridge

+ve atom will interact favourably at aromatic parts, delocalised electrons can interact with other pi electrons in other rings (pi pi interactions)

18
Q

how to calculate the strength of any electrostatic interaction

A

Epolar=q1 q2 / ε r0

q1 and q2= ion-ion interactions or partial charges
ε= dielectric constant
r0= distance between the charges

19
Q

explain ∆G hydrophob

-what is the hydrophobic effect, what happens when lipophilic compound interacts with water

A

-the hydrophobic effect=tendency of nonpolar compounds to transfer from water to an organic phase

-when lipophilic compound interacts with water an interface is created around compound and water at this interface is more ordered, this decreases entropy/increases enthalpy

-formation of complex displaces both water from around ligand and from binding site, its now free, increased entropy and decreases enthalpy and increased affinity

20
Q

explain ∆G vdw

-equation, what happens if a methyl group is introduced

A

-non polar interactions between atoms can be calculatd by

EvdW = A/r^12 – B/r^6

r=distance between atoms
A and B=atom specific repulsive and attractive terms

-introduction of a methyl group may be expected to increase affinity due to hydrophobic effect but only if it fits

-if methyl group doesnt fit then VDW repulsion can decrease affinity

-adding methyl group at various positions may be a useful strategy to map out the size of the binding pocket