mole concept Flashcards
chapter 1
1 amu =
1/6 x 10^ 23 = 1.67 x 10^-24 g
no. of moles =
given wt/ molar mass
no of moles of atom=
atomicity x m/mr
% in terms of moles =
no. of c atoms/ total no. of atoms x 100
% in terms of mass=
mass of c/mr x 100
density=
m/v
vapour density=
d of comp/d of h2= compound mass/ h2 mass
for 1 mole vd =
mr/2
stp , ntp
22.4L , 22.7L
no of moles =
given volume(L)/22.4
mole fraction X =
na/na+nb
1L of h2o =
55.5 moles
Molarity (M)=
moles of solute/vol of sol
(no. of moles of solute in 1 L of solution)
molarity (m)=
moles of solute/mass of solvent(kg)
(no. of mole of solute in 1 kg of solution)
pv=
nRT
R=
1/12
PM=
density x R x T
2P(VD)=
density x R x T
emperical formula
% for each element is isnt mass out of 100
find moles for each
divide all values by smallest value
and write your final ans.
limiting reagent
divide no. of moles of each element/compound by the number before it in the balanced reaction. the smaller value is the limiting reagent. further calc can be done accordingly
