Module 7 Reactivity of Benzene Flashcards

1
Q

Why can’t benzene undergo addition reactions?

A

Aromatic rings are remarkably stable

Aromatic rings are stable enough that they do not undergo such reactions

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Structure of Benzene

A
  • Resonance (bonds aren’t as electron rich)
  • every carbon is sp2 hybridized
  • all carbons have overlapping p-orbitals
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

What is Aromaticity?

A

Aromatic (fragrant) is the term used to molecules that exhibit this type of stability.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Aromatic compound must meet two criteria:

A

1) A fully conjugated ring with overlapping p-orbitals (all carbons are sp2)
2) Have an ODD number of e- pairs or 4n+2 total π electrons where n=0, 1, 2, 3, 4, etc.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Do all fully conjugated rings have aromatic stability?

A

No!

Some fully conjugated cyclic compounds react like normal alkenes

Not all the p-orbitals overlap,

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Aromatice Heterocycles?

A

Rings with heteroatoms (atoms other than C or H) can be aromatic. The heteroatoms are sp2-hybridized so that a lone pair can be placed in the remaining p orbital, which forms a molecular orbital with the p orbitals of the other atoms.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

If the lone pair is necessary for aromaticity, then the lone pair will not be ______.

A

basic

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

when a benzene ring is named as a substituent it is called a ______ group. If the benzene ring is attached to a CH2, the entire group is a _____ group.

A

phenyl and benzyl.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

Cations and anions on the benzylic carbon can be stabilized by ____

A

resonance.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Reactions at the Benzylic Position (Na2CR2O7, H2SO4, H2O) or (KMnO4, H2O heat)

A

Benzylic positions are readily oxidized by chromic acid.

the benzylic position needs at least one proton attached to undergo oxidation.

-the proton is replaced with carboxylic acid.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Can Aromatic rings and alkyl groups be oxidized the same way? (benzylic position)

A

No. Oxidation of the benzylic position is very specific to that position and needs at least one H to be oxidized.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Two other reactions at the benzylic position.

A

SN1/SN2

E1/E2

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

Why can’t benzene react like alkenes in an addition reaction?

A

Pi electrons in the benzene ring are not as nucleophilic, it is aromation and electrons are delocalized.

Benzene can react with a super-duper electrophile, something so electron defficient that even delocalized electrons of the aromatic benzene rings will attack.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Super-Duper Electrophile

A

In the presence of a super-duper electrophile a benzene double bond can attack it.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

EAS Mechanism

A

1) Generate super-duper electrophile
2) Double Bond attacks the electrophile
3) Generation of a carbocation
4) Base deprotonates the carbon bonded to the electrophile
5) double bond reforms

This reaction is favoured because it regenerates the extra stable aromatic ring.

We substitiute the hydrogen for the electrophile.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Halogentation (Br2, FeBr3)

A

-FeBr3 activates the Br2 (LAC) making it even more electron poor.

Lewis acids are an electron pair acceptor, the electron pairs of bromine will attack the lewis acid forming a new intermediate with an electron deficient bromine, that pulls electron densitry away from the adjacent bromine.

generating the bromine electrophile.

17
Q

Halogentation (Br2, AlBr3)

A

The mechanism of bromination would be the same as when FeBr3 is used

18
Q

Halogenation (Cl2, AlCl3)

A

Very Similar Reaction to bromine.

19
Q

Halogenation (Cl2, AlCl3)

A

Very Similar Reaction to bromine.

20
Q

Sulfonation (Fuming H2SO4 contains SO3 gas)

A

Reversible, allows us some control if we want add multiple groups on.

Equilibrium in sulfuric acid where one acts as a base and the other as an acid, the protonated SO4, has a good leaving group, H2O leaves forming the SO3 electrophile.

21
Q

Nitration (HNO3, H2SO4)

A

It is believed a nitronium ion is the active electrophile.

Nitric acid acts as a base and deprotonates sulfuric acid, generating a good leaving group, when the water leaves we get our electrophile.

22
Q

Making Amines

A

A nitro group can be reduced to form an amine

1) Fe or Zn, HCL
2) NaOH

23
Q

Friedle-Crafts Alkylation (Alkyl Halide, AlCl3)

A

Chlorine is electron withdrawing (very deficient).

this generates a carbocation in an alkyl group.

The halide leaving group must be attached to an sp3 hybridized carbon

24
Q

We can also alkylate using an alkene and _ _ _ _

A

H3PO4

Phosphoric acid protonated the alkene to generate a carbocation which acts as the electrophile.

Carbocation rearrangements will occur.

25
Q

Friedel-Crafts Acylation (AlCl3, Acyl group)

A

Acylation and alkylation both form a new carbon-carbon bond

The active electrophile is an acylium ion

Acylium ions are resonance stabilized, and not subject to rearrangement: