Module 4.1 Balancing Equations Flashcards

1
Q

C₄H₁₀ + O₂———> CO₂ + H₂O

A

First put coefficient (numbers) in front of each formula (if there is no coefficient written it is a 1)

To balance take the coefficient and * by the subscript on the left and balance on the right side
C₄H₁₀ + O₂———> CO₂ + H₂O
becomes
C₄H₁₀ + O₂———> 4CO₂ + H₂O (add a 4 in front of the C on the right side)

C₄H₁₀ + 6.5O₂———> 4CO₂ + 5H₂O (can not have a fraction (6 1/2 ) so take the denominator (2) and * by all the coefficients
becomes
2C₄H₁₀ + 13O₂———> 8CO₂ + 10H₂O

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2
Q

Left side ———> right side

What does the left side , arrow , & right side of the equation stand for

A

Lefts side = Reactants (putting the materials together to form the products on the right side)

Arrow = yield

Right Side = Products

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3
Q

FeS + O₂———> Fe₂O₃ + SO₂

A

First put coefficient (numbers) in front of each formula (if there is no coefficient written it is a 1)

To balance take the coefficient and * by the subscript on the left and balance on the right side
FeS + O₂———> Fe₂O₃ + SO₂
becomes
2FeS + 3 1/2O₂———> Fe₂O₃ + 2SO₂ (can not have a fraction (6 1/2 ) so take the denominator (2) and * by all the coefficients
becomes
4FeS + 7O₂———> 2Fe₂O₃ + 4SO₂

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4
Q

Al(OH)₃ + H₂SO₄———> Al₂(SO₄)₃ + H₂O

A

First put coefficient (numbers) in front of each formula (if there is no coefficient written it is a 1)

To balance take the coefficient and * by the subscript on the left and balance on the right side
Al(OH)₃ + H₂SO₄———> Al₂(SO₄)₃ + H₂O
becomes
2Al(OH)₃ + 3H₂SO₄———> Al₂(SO₄)₃ + 6H₂O

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