Module 4 Wave Particle Duality Flashcards

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1
Q

What are electrons?

A

fundamental particles

negative charge of -e

mass in databook (if not travelling close to speed of light)

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2
Q

What is the elementary charge e?

A

the fixed charge e of one electron or proton (1.60x10^-19 Coulomb)

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3
Q

What is the evidence of particle behaviour for electrons?

A

they can gain KE by accelerating

they can be deflected by electric or magnetic fields

they have a fixed mass and charge

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4
Q

What is the De Broglie wavelength?

A

wavelength of a moving particle equal to the ratio of Plancks constant to its momentum (mass x velocity)

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5
Q

What is wave particle duality?

A

some behaviour of electrons is explained using a particle model , some behaviour is explained using a wave model

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6
Q

What is rest mass?

A

the mass of a particle when it is travelling well below the speed of light

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7
Q

Explain how the particle properties/behaviour of electrons can be demonstrated using electron diffraction tube equipment

A

Particle behaviour:
Negative electrons are accelerated through a vacuum to a positive anode at high voltage

Electrons pass through the hole in the anode and produce a beam of electrons with high KE and, momentum and speed

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8
Q

Explain how the wave properties/behaviour of electrons can be demonstrated using electron diffraction tube equipment

A

Wave behaviour:

The beam passes through graphite crystals and diffracts as the De Broglie wavelength is around 1x10^-10m, similar to spacing of carbon atoms in the crystal

The fluorescent screen shows diffraction rings by glowing where the electrons strike the screen (if the De Broglie wavelength is similar to the atomic spacing in the graphite then a lot of diffraction occurs and the rings have a large diameter

This is also an example of interference as the rings show points of minimum and maximum brightness for destructive and constructive interference

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9
Q

Why are electrons accelerated by the anode?

A

electrons have a negative charge, an anode has a positive charge, opposite charges attract

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10
Q

What happens if the voltage of an electron is increased, explain

A
  1. they travel faster due to the following
  2. W=QV where W is work done in J, Q is Coulombs in C and V is voltage
  3. Work done in J = the KE gain of the electrons
  4. Therefore if KE is increased in the formula KE=1/2mV^2 — velocity must increase as mass is fixed and momentum p=mv increases
  5. De Broglie wavelength =h/p so will decrease and smaller diffraction rings produced
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11
Q

What is an electronvolt?

A

is the energy gained by a single electron travelling through a potential difference of 1 Volt

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12
Q

Why is the electronvolt used?

A

in atomic or quantum physics, values of energy are much smaller than joules. The energy gained in electronvolts is numerically equal to the Voltage V

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13
Q

Explain and show how to convert 27eV into Joules

A
  1. W=QV (W in joules, Q in coulombs, V in volts)
  2. When V =1V and Q = 1.60x10^-19 C then W = 1.60x10^-19 J. This is 1 eV in Joules and is given in the formula book
  3. Then 27eV = 4.32x10^-18J
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14
Q

What does P.D. stand for?

A

potential difference in volts

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15
Q

Why can the electronvolt be used for protons?

A

they have the same magnitude of charge e = 1.60x10^-19 C

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16
Q

Describe and explain the effect of doubling the voltage of an electron? (electron diffraction)

A

Doubling the voltage doubles the KE as W=QV, W and KE are both in joules (V here is voltage)

KE=1/2mv^2

v speed is increased by √2

λ=h/mv so λ will decrease by 1/√2

in diffraction rings, increasing speed of electron decreases diameter of rings

17
Q

What is the De Broglie wavelength of a person of mass 60kg moving at 1 m/s

A

De Broglie wavelength=6.63x10^-34/ 1x60
=1.105x10-35m
This is too small to detect diffraction effects

18
Q

What is the significance of the de Broglie wavelength for large mass objects in terms of wave behaviour?

A

De Broglie wavelength is extremely small compared to size of apertures large mass objects can pass through

Large mass objects do not show wave behaviour as diffraction requires wavelength and aperture to be of a similar magnitude therefore they do not diffract