Module 3: C7 - Laws Of Motion And Momentum Flashcards

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1
Q

What is Momentum

A

Momentum is a property of objects with mass and velocity.

It is a vector quantity with the same direction as the velocity of the object.

The units are kgms–1. (This can also be expressed as Ns).

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2
Q

Equation for Momentum

A

Momentum = Mass x Velocity

p = mv

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3
Q

What is the rate of change of momentum proportional to

A

The rate of change of momentum of an object is proportional to the resultant force acting on the object.

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4
Q

Equation for Force with constant Masses

A

F = mΔv / t

F = ma

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5
Q

Equation for Change in Momentum

A

Δp = mv-mu

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6
Q

Example Question:

A rugby ball of mass 0.5 kg is kicked from stationary to a velocity of 8 m/s. The kicker’s foot is in contact with ball for 0.1 seconds. What force does the kicker use?

A

Ft = mv-mu

0.1F = (0.5x8) - (0.5x0)
0.1F = 4
F = 40N

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7
Q

Example Question:

A tennis ball of mass 250g strikes a surface with a velocity of 15m/s. It rebounds directly backwards with a velocity of 7m/s. What is the change in momentum of the ball?

A

(0.25x15) - - (0.25x7) 5.5kgms^-1

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8
Q

What is the Principle of Conservation of Linear Momentum?

A

The total linear momentum of a system of interacting bodies is constant, providing no external forces act.

This applies to collisions, where objects move together and hit one other, and to explosions, where objects fly apart from one another after initially being at rest.

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9
Q

How does the idea of the Conservation of Momentum work?

A

If two objects collide or interact, the forces acting on each one will be the same size but in opposite directions. The same is true for the change in momentum of each object.

This means that the momentum lost by one of the objects will be gained by the other object. Therefore, whenever two objects collide or interact, momentum is conserved.

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10
Q

Example Question:

Consider the nuclear decay of Americium-241:
If the new neptunium atom (of mass 237) moves away at a speed of 5x105 ms-1 what was the velocity of the alpha particle?

A

0 = 237 x 5x10^5 - 4V
4v = 237x5x10^5
v = -29625000
v = -3x10^7

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11
Q

What happens in Perfectly Elastic collisions

A

In this type of collision the objects separate after the collision.

  • Momentum is conserved i.e. the momentum before the collision is equal to the momentum after.
  • Total energy in the collision is conserved
  • Kinetic energy is conserved i.e. the kinetic energy before the collision is equal to the kinetic energy after
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12
Q

What happens in Inelastic collisions

A

In this type of collision the objects stick together after the collision.

  • Momentum is conserved i.e. the momentum before the collision is equal to the momentum after.
  • Total energy in the collision is conserved
  • Kinetic energy is not conserved however.
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13
Q

What is Newton’s First Law of Motion

A

An object will remain at rest or continue to move with constant velocity unless acted upon by a resultant force.

If an object’s velocity changes, then you know a resultant force must be acting on the object. Remember that velocity is a vector quantity, so an object’s velocity changes if it’s speed and/or direction changes.

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14
Q

What is Newton’s Third Law of Motion

A

When two objects interact, they exert equal and opposite forces on each other.

When two objects interact, the pair of forces produced will always be equal and opposite. The forces acting on the interacting objects are always the same type.

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15
Q

How could you Investigate Momentum

A

There are several ways to investigate momentum in the laboratory.

A linear air track is ideal because a cushion of air minimises the friction between the gliders and track, but trolleys and a horizontal runway would also work. The velocity of each object is determined with a motion sensor and a laptop, light gates, and a digital timer (or a stopwatch) to measure the time taken over a known distance.

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16
Q

What is Newton’s Second Law of Motion

A

The net (resultant) force acting in an object is directly proportional to the rate of change of its momentum, and is in the same direction.

17
Q

What equation can you make out of Newton’s Second Law

A

Net Force ∝ Rate of Change of Momentum

F ∝ Δp/Δt

F = kΔp/Δt

(The value of k can be made equal to 1, as the newton is the force required to give 1kg of mass an acceleration of 1ms^-2)

Therefore, Newton’s Second Law can be written as:

F = Δp / Δt

18
Q

Worked Example: Crash Dummy Test

In a crash test at 14ms^-1, a 4.5kg dummy head hits the steering wheel and comes to rest in 9.1ms. Calculate the net force acting on the head in the impact.

A

Step 1: Write down all the quantities in SI units, and select the equation needed.

u = 14, v = 0, t = 9.1x10^-3, m = 4.5kg

F = Δp / Δt

Step 2: Determine the change in momentum p.

Δp = final momentum - initial momentum
Δp = (4.5x0) - (4.5x14) = - (4.5x14)

Step 3: Substitute the values above in the equation to calculate F.

F = Δp / Δt = -(4.5x14) / (9.1x10^-3) = -6.9x10^3N

19
Q

What is the Area under a Force-Time graph

A

The area under a force-time graph is the Impulse

20
Q

What is Impulse?

A

Impulse is a vector quantity with the same direction as the force. It is measured in newton seconds (Ns).

Impulse is also equal to the change in momentum of an object.

Impulse = Change in Momentum

21
Q

How is the damage reduced in car crashes

A

In a car crash, force and therefore damage is reduced by increasing the amount of time over which a collision occurs.

Measures such as seat belts can help with this. The seat belt stretches slightly to prolong the passenger’s impact with it.

Crumple zones also increase the time over which the collision takes place, due to the time it takes them to crumple (as do airbags).

22
Q

Worked Example: Snooker Balls

A 160g white ball travelling at 4.0ms^-1 hits a stationary 170g black ball. After the impact, the balls move apart at approximately 90° to each other, with the white ball travelling at 2.5ms^-1. Calculate the magnitude of the final velocity of the black ball.

A

Step 1:
Select the equation you need and calculate the momentum of each ball.

p = mv
Initial momentum of white ball = 160x10^-3 x 4.0 = 0.64kgms^-1
Initial momentum of black ball = 0
Final momentum of white ball after impact = 160 x 10^-3 x 2.5 = 0.40kgms^-1.

Step 2: Draw a vector triangle for the moments after the impact. These must add up to the initial momentum of 0.64kgms^-1.

Step 3: Use Pythagoras’ theorem to determine the final momentum p of the black ball.

p^2 = 0.64^2 - 0.40^2 = 0.25
p = 0.50kgms^-1

Step 4: Use the equation p=mv to calculate the velocity of the black ball.

0.50 = 0.170 x v
v = 0.50/0.170 = 2.9ms^-1

The magnitude of the final velocity on the black ball is 2.9ms^-1.

23
Q

How is Momentum Conserved in the x and y direction?

A

X Direction:

Total Initial Momentum = Total Final Momentum
m1v0 = m1v1cosΘ1 + m2v2cosΘ2

Y Direction:

Total Initial Momentum = Total Final Momentum
0 = m1v1sinΘ1 + m2v2sinΘ2