Module 2 Foundations in Chemistry Flashcards
The mass of an electron
1/1836 the mass of a proton
Isotopes
Atoms of the SAME element with the same number of protons but a DIFFERENT number of neutrons
Relative Isotopic Mass
The mass of an isotope relative to 1/12th the mass of an atom of carbon-12
Relative Atomic Mass
The weighted mean mass of an atom of an element relative to 1/12th of the mass of an atom of carbon-12
1 mole (mol)
The amount of substance containing 6.02 x 10^23 number of particles
Equation for the amount of substance
Moles (n) = mass (m)/Mr (M)
Number of particles (Av Constant)
Number of particles = Na (Avogardro’s constant) x moles
The empirical formula
The simplest whole number ratio of atoms of each element present in a compound
The complete combustion equation
CxHy + O2 —> 1/2yH2O + XCO2
Molecular formula
The actual number of atoms of each element in a molecule
Stoichiometry
Ratios former by the balancing number to determine the number of moles
Concentration
This gives an accurate indication of the amount, in moles, of a solute that is dissolved in a volume of the solvent
Standard solution
Solution of known concentration
How do you convert between g dm-3 to mol dm-3
Divide by the Mr
Which equation do we use to find the concentration of a solution when the volume contains a dm3 unit
Amount (n) = C x V
State the equation used when calculating the moles of a solution when our volume of solution value is in cm3
Amount (n) = C x V/1000
State what 1cm3 is equal to
1ml
State what 1dm3 is equal to
1 litre
How do we convert between cm3 and dm3
Divide by 1000
Solution
In a solution, a solute is dissolved into a solvent
Concentrated solutions contain…
A large amount of solute in 1dm3
Dilute solutions contain…
A small amount of solute in 1dm3
Formula for atom economy
Mr of desired product/Total Mr of all products x 100