Module 2 Flashcards
How do you write the rate law for the following reaction? a A + b B → c C + d D
Can use any reactant to write the rate law.
- 1 d [A]
———
a dt
What is the unit for rate law?
Concentration/time - usually mol L-1 s-1
What does the rate law describe?
How the rate depends on the concentration. (rate constant multiplied by the concentration of acid and/or base reactants) - rate = k [A]x [B]y
What will the rate law be for the general reaction of
a A + b B → c C + d D
rate = k [A]x [B]y
x and y are exponents.
x is the order with respect to A.
y is the order with respect to B.
x + y is the overall order of the reaction.
How can the values of the orders in the rate law be obtained?
They can only be obtained experimentally, they can not be obtained from the stoichiometry of the reaction.
What does the order of the reactant(s) tell us?
The speed at which is reacts and forms into the product
How could be tell if the rate order of a reactant is 0?
If we varied the concentration of the reactant, the rate would stay the same (as anything to the power of 0 = 1, so rate law = k).
How could we tell if the rate order of a reactant is 1?
If we doubled the concentration of the reactant, the rate would also double, and if we halved the concentration of the reactant, the rate would also be halved.
How could we tell if the rate order of a reactant is 2?
The rate is equal to the square of the concentration, so if the rate were to equal 4x10-3 at a concentration of 0.2, if the concentration were doubled to 0.4, the rate would be the the concentration to the power of 2, hence 16x10-3.
When trying to out the reaction order for a reactant, why measure the initial reaction rate?
Because if the reaction order of the reactant of being investigated, is non-zero, the reaction rate will decrease over time. (as if the order = 0 it is a linear rate).
What are the 3 factors that affect the rate at which molecules react?
- collision rate
- collision effectiveness
- collision orientation
What factors affect collision rate?
- higher concentrations (more particles available to react).
- Greater speed (kinetic energy - from heat) = more collisions
What is collision effectiveness?
Collisions must have enough energy to break bonds or form bonds. This energy threshold is called the activation energy (Ea).
How can we improve the collision effectiveness?
Increase the temperature, giving molecules more force, as an increase in temperature gives molecules more energy meaning the energy of the molecules can exceed activation energy.
What is collision orientation?
Molecules must collide in the correct orientation, for a successful collision.