Module 2 Flashcards

1
Q

Mammals cannot synthesize all coenzymes from scratch
A tightly bound metal or coenzyme is a ________
An apoenzyme plus a prosthetic group is a ________ .

A

prosthetic group

holoenzyme

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2
Q
ΔGo =  \_\_\_\_\_\_\_\_\_\_\_\_\_\_
ΔG'o = \_\_\_\_\_\_\_\_\_\_\_\_\_\_
A

standard free energy change (298 K, 1 atm, 1 M)

biochemical standard free energy change (pH 7)

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3
Q

Enzymes do not alter the equilibrium between Sand P only the _________ __ ___ _________

A

rate of the reaction

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4
Q

Just because ΔG’ois negative does not mean that the reaction will take place at a detectable rate

Even though ΔG’ois very negative sucrose is very stable

Catalysts enhance reaction rates by lowering _______ _______

A

activation energies

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5
Q

______ ______:any species along a reaction pathway with finite chemical lifetime(longer than a molecular vibration ~10-13seconds)

A

Reaction intermediates

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6
Q

Reaction equilibria are linked to ____ (standard free energy change)
Reaction rates are linked to ΔG‡ (activation energy)

A

ΔG’o

ΔG‡

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7
Q

K’eq = [P]/[S]

ΔG’o= -RT ln K’eq
R, 8.315 J/mol•K
T, absolute temp in K

A

Keq and ΔG’o relationship

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8
Q

First order reaction: __ = __ * __

Second order reacion: __ = __ __ __

A

V=k[S]

V=k[S1]{S2}

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9
Q

How do enzymes speed up the rate of reactions?

A
  1. formation of covalent interactions with amino acid side chains or bound metals or cofactors
  2. non-covalent interactions (formation of EScomplex)
    binding energy, ΔGB,is a major source of free energy used by enzymes to lower the activation energy of reactions
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10
Q

Enzyme active sites are complimentary to the ______ ______ of the reaction

A

transition state

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11
Q

Stronger/additional interactions with the transition state as compared to the ground state lower the ______ ______

A

activation barrier

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12
Q

Physical and thermodynamic factors contributing to ΔG‡:
1. ________________________

  1. ________________________
  2. ________________________
  3. ________________________
A
  1. reduction in entropy (less free motion)
  2. solvation shell of hydrogen-bonded water around Sand P
  3. distortion of substrates (like stickasedid)
  4. need for proper alignment of catalytic functional groups
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13
Q

______ _____ are the most common biochemical reactions

A

Proton transfers

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14
Q

In enzyme kinetics ____ ____ must be short so that [S] does not change much

A

Reaction times

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15
Q

___ is the substrate concentration at ½ Vmax

A

Km

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16
Q

enzyme is saturated with substrate at __

A

Vmax

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17
Q
  1. binding of substrate to enzyme

equilibrium is normally reached within microseconds

as [S] increases eventually the enzyme becomes saturated

  1. reaction and release of product

this is the slow step and limits the rate of the whole reaction

Reactions kinetics are dictated by a rapid, concentration-dependent binding of substrate to the enzyme followed by a slower generation of released product

A

Steady State Kinetics

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18
Q

Steady State Kinetics

  1. binding of substrate to enzyme

_____________________________

_____________________________

  1. reaction and release of product

_____________________________

_______ ______ are dictated by a rapid, concentration-dependent binding of substrate to the enzyme followed by a slower generation of released product

A
  1. equilibrium is normally reached within microseconds

as [S] increases eventually the enzyme becomes saturated

  1. this is the slow step and limits the rate of the whole reaction

Reactions kinetics

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19
Q

The ____-____ equation was based on a specific kinetic model but many enzymes that use different (complex) mechanisms yield a similar hyperbolic V vs [S]curve and the Vmax and Km’s determined are valuable parameters.

A

Michaelis-Menten

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20
Q

The turnover number, ___

A

kcat

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21
Q

If the rate limiting step is binding of substrate: kcat= ___

A

k1

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22
Q

If the rate limiting step is release of product: kcat = __

A

k3

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23
Q

If there are several slow steps kcat is a _______ function

A

complex

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24
Q

In all cases ____ is a first order rate constant (1/sec) and is equal to the number of substrate molecules converted to product in a given unit of time on a single enzyme molecule when the enzyme is saturated with substrate

A

kcat

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25
Q

parallel lines indicate a___-___ (double-displacement) pathway
Km for S1increases as [S2] increases

A

Ping-Pong

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26
Q

Inhibitor blocks binding of substrate
Vmaxis not affected by inhibitor, but the apparent Kmis raised
Usually inhibitor is not metabolized by the enzyme it blocks
Methanol is converted by alcohol dehydrogenase to toxic formaldehyde
Ethanol is like a competitive inhibitor (converted to acetaldehyde)

A

Reversible Competitive Inibition

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27
Q

Inhibitor interacts with ES at a site distinct from the active site and slows the reaction
Vmaxand apparent Kmare lowered by the inhibitor

A

Reversible Uncompetitive Inhibition

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28
Q

Inhibitor interacts with E or ES at a site distinct from the active site and slows the reaction
Vmaxis lowered and apparent Kmraised (shown above) or lowered by the inhibitor

A

Reversible Mixed Inhibition

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29
Q

Inhibitors that bind covalently or very strongly and destroy a required functional group are ________

A

Irreversible

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30
Q

_______ inhibitors bind to the enzyme, make it part way through the reaction mechanism then block subsequent steps
These make good drugs

A

Suicide

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31
Q

Enzyme activity depends on __

A

pH

32
Q

1.Identification of substrates, cofactors, products, regulators
2.Sequence of formation of enzyme bound reaction intermediates
3.Structure of each intermediate and transition state
4.Rates of interconversion between intermediates
5.Energy contributed by all reacting and interacting groups to intermediates and transition states
How many enzymes are understood at this level?
____

However, many details of the function of Chymotrypsin, Hexokinase, Enolase, and Lysozyme are known

A

What you need to know to fully understand a mechanism:

1.
2.
3.
4.
5.

None

33
Q

________ specific for peptide bonds next to Trp, Phe,Tyr
Transition state stabilization, acid base catalysis

109fold stimulation of hydrolysis of peptide bond without using water

25 kDa protein cut in 2 places to produce 3 chains

A

Protease

34
Q

Relative electronegativities
(attraction of electrons)

P N F O H S C

Nucleophile ______ ______
Electrophile ______ ______

A

F > O > N > C = S > P = H

(nucleus lover)

(electron lover)

35
Q

What is important about the ___________ mechanism?

  1. Chymotrypsin is a serine protease that cleaves polypeptide backbone following F, Y or W residues because of hydrophobic pocket
  2. Activated by proteolytic cleavage
  3. Has a catalytic triad (Ser, His, Asp) in active site (D works through H to activate S)
  4. Uses acid base catalysis; general (Ser 195) and specific (H20)
  5. Uses covalent catalysis with N terminal portion of polypeptide attached
  6. Oxyanion hole stabilizes intermediates
  7. Pre-steady state kinetics gave evidence of a two step mechanism
A

chymotrypsin

36
Q

You can fool hexokinase (kind of)

Xylose binds to hexokinase, but in a way that it can’t be phosphorylated

However, xylose increases the rate of hydrolysis of ATP

Xylose causes the hexokinase to enter it’s active conformation and tricks hexokinase into using water to hydrolyze the ATP

A

You can fool hexokinase (kind of)

Xylose binds to hexokinase, but in a way that it can’t be phosphorylated

However, xylose increases the rate of hydrolysis of ATP

Xylose causes the hexokinase to enter it’s active conformation and tricks hexokinase into using water to hydrolyze the ATP

37
Q

Tools for examination of transition state complementarity

A
  1. Structure activity correlations
  2. Transition-state analogs
  3. Catalytic antibodies
38
Q
  1. Structure activity correlations
A

If enzyme stabilizes the transition state then there must be interactions between substrate and the enzyme only in the transition state (this would not affect initial binding of substrate

39
Q

2.Transition-state analogs

A

Compounds that mimic the structure thought to be present in the transition state
Because the enzyme usually aims to strain the substrate toward the transition state (to reduce activation energy) the binding of the analog is stronger than that of the substrate (100 to 1,000,000 times stronger)
Drugs such as those that inhibit
the HIV protease mimic the
transition state, but trap the
enzyme in an unproductive state

40
Q

3.Catalytic antibodies

A

Antibodies are proteins that bind to specific structures
An antibody raised against a transition state analog might bind to a substrate and strain it to the transition state
Antibodies to phosphonate or phosphate esters act as enzymes to speed up hydrolysis of the ester or carbonate by 1000 to 10,000 fold

41
Q

________ _______ needed to control complex pathways
usually the first enzyme of a pathway or branch point
Some enzymes are controlled by covalent modification (phosphorylation, adenylation etc.)

A

Regulatory enzymes

42
Q

Most regulatory enzymes are _______ proteins

A

multimeric

43
Q

_______ enzymes –conversion between active and inactive conformations controlled by reversible, noncovalent binding of regulatory compounds (allosteric modulators or effectors)

A

Allosteric

44
Q

__________ __________
used in an early step in biosynthesis of pyrimidine nucleotides
12 subunits (6 regulatory, 6 catalytic)

Inactive in the _ state
Active in the _ state

A

Aspartate transcarbamoylase

T tensed

R relaxed

45
Q

________ _______
(example: conversion of threonineto isolucine)

5 step pathway uses 5 enzymes

only E1 is regulated allosterically

Isoleucine binds to and inhibits E1
(end product inhibition)

E2-5 are not allosterically controlled by Isoleucine

controlling the first enzyme in a pathway ensures that potentially toxic intermediates don’t build up

_______ ______allows the level of the final product to control flux through the entire pathway so that a relatively constant steady state level of the final product is maintained

A

Feedback inhibition

46
Q

Allosteric enzymes have a ______ curve instead of a hyperbolic curve found in Michaelis-Menten kinetics

A

Sigoidal

47
Q

_______ curve results from cooperative interaction between subunits (like hemoglobin)

(a K0.5value replaces the Kmdesignation)

usually Vmaxis constant and K0.5is changed by effector

A

sigmoidal

48
Q

Regulation by covalent modification

1. Functional group modifications:
-
-
-
-
2. Large molecule modifications:
-
-
3. Protein modification:
-
-
A

Phosphorylation
Acetylation
Adenylylation
Methylation

Myristoylation
ADP ribosylation

Ubiquitination
Sumolation

49
Q

_______ ______ enzymes that phosphorylate proteins and

A

protein kinasesare

50
Q

_______ _______remove the phosphate without regenerating ATP

A

protein phosphatases

51
Q

_______-simple sugars (sakcharon -greek for sugar)

A

Monosaccharides

52
Q

_______-2 monosaccharides connected by glycosidic bonds

A

Disaccharides

53
Q

_______-short chains from 2 to 20 monosaccharides

A

Oligosaccharide

54
Q

_______- polymer containing more than 20 monosaccharides

A

Polysaccharides

55
Q

______ differ by configuration at only one chiral center

A

epimers

56
Q

_______ interconversion of two hemiacetal forms

A

Mutarotation

57
Q

Change in ______ requires breaking of covalent bond

A

configuration

58
Q

Change in _______ requires breaking of covalent bond

A

conformation

59
Q

Polysaccharides (glycans)

Most carbohydrates in nature are found in ________

Used as fuel storage (glycogen, starch)

Structural element (cellulose and chitin extracellular matrix)

Not usually of defined molecular weight like proteins

Characterized by type of monomer, length of chain, types of glycosidic bonds, degree of branching

A

polymers

60
Q

Characterized by type of ____, ____ __ ____, ____ __ ____ ____, _____ __ ____.

A

monomer
length of chain
types of glycosidic bonds
degree of branching

61
Q

Used as fuel storage (glycogen, starch)

Structural element (cellulose and chitin extracellular matrix)

Not usually of defined molecular weight like proteins

Characterized by type of monomer, length of chain, types of glycosidic bonds, degree of branching

A

Polysaccharides (glycans)

62
Q

amylose

A

a form of starch

long, unbranched chains of D-glucose residues

63
Q

amylopectin

A

another form of starch

branch every 24-30 residues

64
Q

Which end are residues removed from when energy is needed?

A

Nonreducing end

65
Q

____ is a multi-branched polysaccharide of glucose

A

Glycogen

66
Q

glucose is stored with same linkages as that found in ______

A

amylopectin

67
Q

_____ branching is more extensive (every 8-12 residues) 1,000,000 Mw

A

glycogen (glucose)

68
Q

_____ is 7% of wet weight of liver and also found in skeletal muscle

A

glycogen (glucose)

69
Q

each molecule of ____ has one reducing end and many non-reducing ends

enzymes remove glucose monomers from the non-reducing ends

A

glycogen (glucose)

70
Q

________ store glucose in glycogen chains to reduce the osmolarity (otherwise there would be 0.4 M glucose)

A

Hepatocytes

71
Q

Also it would be difficult to transport _____ into a liver cell up a gradient from 5 mM in the blood to 400 mM in the liver cell

A

glucose

72
Q

_____ are bacterial and yeast polysaccharides

(α1 -> 6) linkage with (α1 -> 3) linkage at branch points

Dental plaque is ____ deposited by bacteria growing on teeth

A

dextrans

73
Q

______ is found in stalks and stems and trunks -cotton is almost 100% ______
linear, unbranched homopolysaccharide 10,000 to 15,000 glucose units
Unlike amylose, amylopectin and glycogen _____ has βconfiguration
Most animals can’t digest cellulose (bacteria, fungi, and termites can)

A

cellulose

74
Q

Hydrogen boning networks between stands of _____ provide fiber strength

A

cellulose

75
Q

Fungi have ____

A

cellulase

76
Q

_______ is a linear homopolysaccharide with N-acetylglucosamine (β linkage)

A

chitin