Mock Test 2 Flashcards
4, 5, 7, 11, 19
33 27 37 35 40 41
35 The difference is doubled each time 5-7=2 2x2=4 7+4=11
Nigel left home at 12:10pm and walked to the shop. He walked 95m per minute. He arrived at 12:25pm. What is the distance between his house and the shop?
1245m 1300m 1425m 1200m 1400m 1500m
1425m
1210hours - 1225hours =15 minutes
15x95m/min=1425m
Which is the odd one out?
7 12 3 11 5 13
12
12 is an even number the rest are odd
50, 60, 55, 65, 70, 80…
65 75 85 90 100 105
75
+10 -5 +10 +5 +10 -5
Ryan left the museum and drive south. Gabrielle left 3 hours later driving 42km/h faster. After 2 hours Gabrielle finally caught up. Find Ryan’s average speed.
20km/h 17km/h 28km/h 10km/h 19km/h 26km/h
28km/h R + 42=G speed T-3= G travel time If she caught up after 2 hours that means T-3=speed x time R x t = (r+42)(t-3) 5R= 2(R+42) Expand the brackets and simplify RxT=(R+42)(t-3) 5R=2R+84 5R-2R=84 3R=84 R=84/3 R=28
1,10,3,30,5,50,6…
60 55 45 40 8 7
60
Ali drove from town A to town B at 60kmph. He took 1 hour 20 minutes to reach town B. If he were to increase his speed by 20% how much time would he save?
12mins 20mins 11mins 1hour 25mins 10mins
12mins Total distance 80km 60 x 0.2 (get 20%) = 12 60+12= 72kmph -new average speed 80/72= 1.1 hours 1.333-1.111=0.222 0.222 to mins = 13.333 minutes saved or simplified 1.3-1.1= 0.2 0.2x60=12mins
2,5,11,23,47…
80 90 95 92 101
95
Pattern is x2 +1
Lucy took 30mins to cycle from school to home Stan average speed of 12kmph. If she wanted to reach home 10minutes early. What must her average speed be?
15kmph 30kmph 20kmph 18kmph 10kmph 11kmph
18kmph
Total distance: 12km /2= 6km
New time of 20minutes-this is 1/3 of an hour.
Total distance (6km) x 3(20mins goes into 60min 3 times) =18kmph
Which is the odd one out?
109 112 140 136 108 118
109
109 is odd
A submarine left Hawaii two hours before an aircraft carrier. The vessels travelled in the opposite directions. The aircraft carrier travelled 26kmph for nine hours. After this time the vessels were 280kms apart.
5kmph
AC Tdistance= 25kmph x 9 hours=225km
Submarine total distance=280km -225km=55km
Submarine total time traveled = 2 hours + 9 hours = 11hours
Submarines speed= 55km/11hours =5kmph
69,72,75,78,81,84…
90 89 88 87 86 85
87
+3
Which is the odd one out?
- 10
- 01
- 26
- 32
- 48
- 12
- 10
1. 10 has 1 decimal place, the rest have 2
Chelsea left the White House and travelled toward the capital at a speed of 34kmph. Jasmine left at the same time and travelled in the opposite direction with a speed of 65kmph. Find the number of hours jasmine needs to travel before they are 59.4km apart?
0.9
0.6
1
0.5
1.5
0.4
0.6 hours Distance =speed x time Speed of Chelsea (SC) = 34 Speed of Jas (SJ)= 65 T=hours D=59.4 (after T) (Sc x T) 34t + (Sj x t) 65t = (D) 59.4 99t = 59.4 T=59.4/99 (round up so 60/100) T=0.6
98, 16, 96, 18, 94, 20, 92…
18 22 2 88 90 94
22evedy second number is +2 and the others are -2