Mock exams mistakes Flashcards
Give an equation, showing structural formulas, for the conversion of chloroethene into poly(chlorothene)
H Cl —> [ H Cl ]
n C=C —> [C - C ]
H H —> [ H H ] n
State what you would observe if bromine water was added to poly(chloroethene). Explain this observation.
No reaction.
Polymer contains no double bonds / polymer is saturated.
Give the meaning of the term relative atomic mass.
The average / mean mass number of an atom (of an element) compared to 1/12 mass of one atom of C12
The sample of chromium is analysed in a TOF mass spectrometer.
Give two reasons why it is necessary to ionise the isotopes of chromium before they can be analysed in a TOF mass spectrometer.
- Ions will be accelerated by an electric field.
- Ions create a current when hitting the detector.
A 53Cr+ ion travels along a flight tube of length 1.25m. The ion has a constant kinetic energy of 1.102 x 10-13 J.
m = mass of ion / kg
V = speed of ion / m s-1.
Calculate the time, in s, for the 53Cr+ ion to travel down the flight tube to reach the detector.
The Avogadro constant, L = 6.022 x 10 23 mol-1. (5)
1 mass of ion = 8.8 x 10-26 Kg
(53 / (6.022 x10 23) ) / 1000
/1000 to get from g to Kg
2 v2 = 2KE / m
3 v = √2KE / m
v = √2 x 1.102 x 10-13 / 8.8 x 10-26 = 1.58 x 10 6 (ms-1)
4 v = d/t
5 t = 7.9 x 10-7
Magnesium is used in one of the stages in the extraction of titanium.
Give an equation for the reaction between titanium (IV) chloride and magnesium. State the role of magensium in this reaction.
titanium (IV) shows that it has a +4 charge.
EQUATION
TiCl4 + 2Mg -> 2MgCl2 + Ti
ROLE OF MAGNESIUM
Reducing agent (of Ti).
A mixture of magnesium oxide and magnesium hydroxide has a mass of 3200mg.
This mixture is reacted with carbon dioxide to form magnesium carbonate and water. The mass of water produced is 210mg.
Calculate the percentage by mass of magnesium oxide in this mixture.
x1000
->
g to mg
<-
/1000
1 moles of water in 210mg
210mg/1000 = 0.210g
mass / mr = 0.210 / 18
=0.0117 mol
equals to moles of MgOH produced in stage 1.
2 mass of Mg(OH)2
0.0117 x 58.3 = 0.680g
3 mass of MgO = 3.2 - 0.68
= 2.52g
3200mg/1000 = 3.2g
State the meaning of the term standard enthalpy of combustion.
The enthalpy change when one mole of a substance burns completely in oxygen 1
with all substances in their standard states (stated temp and 100kPa) 2
A student does an experiment to determine the enthalpy of combustion of propan-1-ol (CH3CH2CH2OH, Mr = 60.0)
Combustion of 0.497g of propan-1-ol increases the temperature of 150g of water from 21.2°C to 35.1°C.
Calculate a value, in kJ mol-1, for the enthalpy of combustion of propan-1-ol in this experiment. Specific heat capcaity of water is 4.18 JK-1 g-1.
1 q = m c ∆T
q = 150 x 4.18 x 13.9
q = 8715.3 J / 1000
q = 8.7153 kJ
2 n(propan-1-ol) = mass / mr
n = 0.497 / 60.0
n = 0.00828 mol
3
∆H = - (8.7153 / 0.00828)
∆H = - 1050 kJ mol-1
The enthalpy of combustion determined experimentally is less exothermic is less exothermic than that calculated using enthalpies of formation.
Give on possible reason for this, other than heat loss.
Incomplete combustion.
Propene reacts with concentrated sulfuric acid to form two isomers, E and F. Structure of E is shown.
CH3 CH CH3
|
O
|
O=S = O
|
OH
Name and outline a mechanism for the formation of E in this reaction.
NAME
1 electrophillic addition.
MECHANISM
2 arrow from double bond towards H atom of the H2SO4 molecule.
3 show breaking of the H-O bond in H2SO4.
4 structure of correct carbocation.
5 Show arrow from the lp of e- on negatively charged oxygen of HSO4- towards positively charged atom of their carbocation
State why the student should use sodium hydroxide solution rather than water for the final rinse of the burette.
The use of water would dilute NaOH.
Use your answer to part c (0.63%) to find the mass, in mg, of citric acid dissolved in 250cm3 of the solution.
RMM (Mr) of citric acid is 192.0.
1 moles of NaOH
23.95/1000 x 0.0500 = 0.001198
2 moles of acid in flask
m1 / 3 x 10 = 0.003992
(divide by 3 as there are 3NaOH)
3 mass acid =
0.003992 x 192.0 = 0.766g
0.766 x 1000 = 766mg
The total uncertainty when using the burette is ±0.15 cm3. This is the combination of uncertainties in the start reading, final reading and the determination of the end point.
Use your answer to part (c) to calculate the percentage uncertainty for the use of the burette in this experiment.
part c = 23.95
(uncertantity / mean titre) x 100
(0.15 / 23.95) x 100 = 0.63%
Calculate the percentage purity of this sample of citric acid.
The student dissolved 784mg of impure citric acid in water to prepare 250cm3 of solution in a volumetric flask.
(766 / 784) x 100 = 97.7 or 97.8 %