Mildenhall Ch 4: Measuring Risk with Quantiles, VaR and TVaR Flashcards
Define quantile
Suppose F(x) = p then q(p) = x is known as the p-quantile.
When used as a risk measure, it is known as Value at Risk (VaR).
Identify 2 main issues when defining quantiles. Provide an example and a way to address each issue.
- The equation F(x) = p might not have a unique solution if F is not strictly increasing.
Ex: F might have a flat spot
Solution: Any of those x would be considered p-quantiles. However, it is most natural to select either first x value (lower quantile) or last x value (upper quantile) along the flat spot. - The equation F(x) = p may have no solution if F is not continuous.
Ex: F jumps from below p to above p in discrete distribution
Solution: define p-quantile such that P(X<x) =< p =< P(X =< x)
Summarize the 3 steps to compute quantiles
- Determine where a horizontal line at height p intersects graph of distribution function, including vertical segments.
- If there is a unique solution, it is the unique p-quantile.
- If there is an interval of intersection (flat spot), then:
a. Smallest value is lower p-quantile
b. Largest value is upper p-quantile
c. Any value in between is also p-quantile
Briefly describe how we can use quantile functions to simulate values of X (how is the method called)
- Randomly draw value w from uniform r.v. U
- Assume we have quantile function q- describing quantiles of X, we can simulate a value X s.t. x = q-(w)
- If we do this thousands of time, we can effectively simulate distribution of X
This simulation method is known as the inversion method.
Define Value at Risk (VaR)
The p-VaR of a loss r.v. X equals the lower p-quantile q-(p)
VaRp(X) is the smallest loss such that P(X=< VaRp(X)) >=p
State 4 advantages of VaR
- Simple to explain
- Can be estimated robustly
- Always finite
- Widely used by regulators, rating agencies & companies in their internal risk management.
State a disadvantage of VaR
It does not always recognize diversification (i.e. not always sub-additive)
Briefly explain how VaR can be expressed in terms of return period
Assuming X represents aggregate losses over 1y, a loss size VaRp(X) is expected to occur once every 1/(1-p) years.
Waiting time has geometric distribution with parameter p.
Average waiting time is 1/(1-p)
Define PML
PML estimates the largest loss that a building is likely to suffer from single fire if all protection systems function as expected
Define Maximum Foreseeable Loss (MFL)
MFL is the largest loss a building is likely to suffer from a single fire if protection system fails.
Assume CAT events follow Poisson Process, calculate the prob of 1 or more events causing a loss X or more.
1 - exp(-lambda * S(x))
Contrast n-year Occurrence PML and Aggregate PML
n-year Occurrence PML is the smallest loss X s.t. prob of one or more events causing a loss x or more in a year is at most 1/n.
Aggregate PML is the same as aggregate VaR.
Aggregate PML can be approximated using n-year occ-type PML if X is thick-tailed and n is large.
Calcuate occurrence PML
PML
= q_x * (1 - log(n/(n-1))/lambda)
= VaR_1 - log(n/(n-1))/lambda (X)
since p = 1 - 1/n
= q_x * (1 + log(p)/lambda)
= VaR_1 + log(p)/lambda (X)
1 + log(p)/lambda is known as the adjusted probability level
Calculate Agg PML
Agg Losses (A) follow Compound Poisson Process
Agg PML
= VaR(A)
can be approx as:
= VaR_1-(1-p)/lambda (X)
When X0 is thin-tailed and X1 is thick-tailed, calculate VaRp(X0+X1)
VaRp(X0+X1)
= VaRp(X)
= E(X0) + VaRp(X1)
Define thin-tailed random variable
- Log-concave distribution
OR - Bounded distribution
Define thick-tailed random variable
Subexponential distribution (aka log-convex distribution)
S(x) = k*x^alpha for some constant k
In which case is the approx for Agg PML adequate
Agg VaR approx is excellent for larger return periods
error = estimated/true - 1 decreases as n increases (thus p = 1-1/n increases as well)
True or False?
Occ PML is always larger than Agg PML.
Explain.
True since it uses larger adjusted probability.
Complete the statement:
As lambda (frequency) increases, the difference between Occ PML and Agg PML …
Explain
Increases as well because adjusted probability p increases.
Complete the statement:
As means severity increases, Occ PML… and Agg PML…
As severity increases, both Occ PML and Agg PML increase