Midterm Review Flashcards
Vector Addition
For x = [x1, x2] and y = [y1, y2]; x + y = [x1+y1, x2+y2]
Scalar Multiplication
If t is a real # (scalar), then tx = [tx1, tx2]
Linear Combination
Given any # of vectors, a lin. comb. is sum of scalar multiples of the given vectors. Any vector x = [x1, x2] can be written as x = x1[1, 0] + x2[0, 1]
Zero Vector
[0, 0] , denoted 0 with length but no direction
Vector Equation of a Line Through 0
x = td, teR. The set {td : teR} can be used to describe points on the line.
Vector Equation of a Line not Through 0
Find/Use a point on the line and get a vector p whose head is at that point, and add p to any td with teR.
Equation: x = p + td, teR.
Find the Equation of a Line through (0, 0) parallel to Existing Line?
Use the same direction vector td.
x = td, teR
Parametric Equation
If x = [x1, x2] = [4, -3] + t[3, -1] then the following is the pe
x1 = 4 +3t
x2 = -3 -t
Scalar Equation
From parametric equ solve all equations for the scalar (eg. t) and equate then solve for the form ax1 + bx2 +… = d
Directed Line Segments
Free vectors which are allowed to be translated parallel to themselves.
Parallel Vectors
u and v are said to be parallel if they are scalar multiples of each other. 0 = 0u but u isn’t a sm of 0 yet 0 and u are parallel.
Properties of Vectors in R^n
For any x, y, w eRn and s, t eR: x + y eRn x + y = y + x (x + y) + w = x + (y + w) tx eRn (st)x = s(tx) (s + t)x = sx + tx t(x + y) = tx + ty
Subspaces
A subspace is a non empty subset (say s) of Rn such that for any x ,y eS and teR: x + y eS (closed under addition) and tx eS (closed under scalar multipllication). Note: 0 is always in any subspace.
Proving Subspaces
Closed under addition, closed under scalar multiplication, and non empty. In other wods, check if 0 is eR, if the sum of 2 vectors (which are eS) is also eS, and if the product of a scalar t and a vector (eS) is also eS.
Closed under addition
Let [x1, x2] and [y, y2] be from S. Then [x1, x2] [y1, y2] = [x1+x2, x2+y2]. Then x2 + y2 = (2x1) + (2y1) = 2(x1+y1) Therefore S is closed under addition.
Closed Under Scalar Multiplicaton
Let teR and [x1, x2]eS. Then t[x1, x2] = [tx1, tx2]. Now tx2 = t(2x1) = 2(tx1) therefore S is closed under sm
Non Empty
0 = [0, 0]. As 2(0) = 0, we get 0eS. Therefore S is non empty.
Relation Between Subspces and Subsets
Every subspace is a subset but not every subset is a subspace.