midterm 2 Flashcards
if vector b is in the span of v vectors
when in augmented form it is consistent
if the span of vectors can produce any vector in Rm
there must be a pivot in every row
if the span of vectors can not produce all vectors in Rm
there must not be a pivot in every row
if the the span of vectors can produce all vectors in Rm in infinitely many ways
there must be a pivot in every row but not a pivot in every column
if the vectors are linearly independent
the vectors have a pivot in every column
If T(x) = Ax is onto
A has a pivot in every row
If T(x) = Ax is 1-to-1
A has a pivot in every column (lin indep)
A (nxn) is invertible
A can be transformed into Identity matrix
Why would an mxn matrix where m>n be not onto
There is not a pivot in every row
Why would an mxn matrix where m<n not be one to one
there are fewer pivots than columns
If A is a square one to one and onto then
A is invertible
If we transform from R2 to R5 and it is not onto
2 columns with 5 rows: fewer pivots than rows
Why is it that if A is invertible it is onto
pivot in every row (A can be reduced to identity matrix)
If the vectors in A are not lin indep, why is it not 1-to-1
if lin dep, there is not a pivot in every column
If Ax = b always has a solution is it onto or one-to-one
onto (not always 1-to-1)