midterm 1

Question 1

&= bitwise and

Answer 1

this is equivalent to an intersection (set.intersect()) which keeps only what is common between the source and what you’re comparing it to

Bit 1 Bit 2 Bitwise AND (&)
0 0 0
0 1 0
1 0 0
1 1 1
my_keys &= set(d.keys())

Question 2

in re

Answer 2

is the or expression, you can seperate different patterns that you want to match using |

Question 3

dictionary.get()

Answer 3

searches for the key and returns the optional value if it’s not found

keyname Required. The keyname of the item you want to return the value from
value Optional. A value to return if the specified key does not exist.
Default value None

Question 4

NESTED list comprehension

Answer 4

[expression for outer_loop_variable in outer_sequence for inner_loop_variable in inner_sequence]

Question 5

.split()

Answer 5

can specify a separator. default is any whitespace