Midterm 1 Flashcards
Linear Equation
○ a1x1 + a2x2 + … + anxn = b
organization of coefficients and variables with a solution ‘b’
System of linear equations
collection of multiple linear equations
solution of a system
list of numbers that make each equation true when values are substituted in for the corresponding ‘x’ variables
solution set
set of all possible solutions of a linear system
equivalent linear systems
systems with the same solution set
Consistent System
there is at least one solution (1 or infinite many)
Inconsistent System
there is no solution to the system for a specific input
they have EMPTY solution sets
existence and uniqueness questions
existence: does the solution/something exist?
uniqueness: if the solution exists, is there more than one solution (infinite many)?
How many solutions can a linear system have
none, one, or infinite many
size of a matrix
m x n
m: number of rows
n: number of columns
Row reduction operations
- take a multiple of one row and ADD that to another (used to eliminate entries)
- scale a row by a scalar not equal to zero (usually done to make a leading entry = 1)
- interchange rows
non-zero row/column
at least ONE of the entries has to be nonzero
leading entry
leftmost nonzero entry in a row
Conditions of Echelon Form
- leading entries of the next row are right of the leading entries in previous row above it
- everything in the column below a leading entry is all 0
- all zero rows are at the bottom
Row Reduced Echelon Form and Conditions!
represents a potential solution set for a linear system
EACH MATRIX ONLY HAS ONE RREF - row equivalent to just ONE
- all leading entries are 1s
- there are 0s ABOVE and BELOW each leading 1
if matrix is not echelon or RREF that means MORE row reductions must be done
pivot position and pivot columns
pivots are the locations in a matrix that correspond with leading 1s of RREF
pivot columns are the columns that have pivot positions
Basic/Leading Variables
variables that correspond with a pivot
basic variables have an EXACT value for a solution set
Free variables
don’t correspond to any pivots or pivot columns
can be assigned ANY value for a consistent linear system
Overdetermined System
More rows than columns
more equations than variables
- can be consistent
- can have a unique solution
– doesn’t necessarily have to be?
Underdetermined System
more columns than rows
more variables than equations
there will always be a free variable SO cannot have a unique solution
if consistent: infinite!
if inconsistent: no solution
Existence and Uniqueness Theorem
a linear system is consistent if and only if there is NOT a pivot in the last augmented column (rightmost column of augmented matrix)
● [0 0 0 0 0 | b] with b non-zero
if linear system is consistent:
1 solution (no free variables)
infinite (at least 1 free variable)
R^n
dimension we are in
n is the number of rows or entries in a vector
R is the collection of all lists if n real numbers
example:
○ R2 vector: 2 rows
○ R3 vector: 3 rows
vectors in R2 are a line to a point in 2D space
vectors in R3 are a line to a point in 3D space
Linear Combinations
Linear combinations is y = c1v1 + c2v2 + … + cpvp
where vs are a set of vectors in R^n and cs are weights or SCALARS
Y is a linear combination!
Span{v1 …vp}
Span is the set of all possible linear combinations of those sets of vectors
c1v1 + c2v2 + … + cpvp
Algebraic Properties of Rn (8 total)
○ For all u, v, w in Rn and all scalars c & d:
i. u + v = v + u v. c (u + v) = cu + cv
ii. (u + v) + w = u + (v + w) vi. (c + d) u = cu + du
iii. u + 0 = 0 + u = u vii. c (du) = (cd) u
iv. u + (-u) = -u + u = 0 viii. 1u = u
VECTOR EQUATIONS
vector equation: x1a1 + x2a2 + … + xnan = b where a and b are vectors
- has the same solution set as the linear system whose augmented matrix is [a1 a2 .. an | b]
- b can only be generated if there exists a solutions (weights ‘x’s) to the linear system with the matrix!
More about SPAN and connection to vector equation
If v1….vp are in Rn, then the set of all linear combinations of v1…vp is denoted by Span{v1…vp} this is called the subset of Rn spanned by v1….vp
is vector b in Span{v1…vp} is the same as asking x1v1+….+xpvp = b??
- solve the augmented matrix!
- is every b of Rn a linear combination of the vectors in {v1…vp}? == is there a pivot in every row
Identity Matrix
output the same input