Methods 4 Flashcards
Regular Singular Point
For a general linear second-order differential equation for w(z), of the form w”(z) + p(z)w’(z) + q(z)w(z) = 0
A point z=z0 is a regular singular point of it is not an ordinary point, but both (z-z₀)p(z) and (z-z₀)²q(z) are analytic at z₀
Ordinary Point
For a general linear second-order differential equation for w(z), of the form w”(z) + p(z)w’(z) + q(z)w(z) = 0
A point z=z₀ is an OP if both p(z) and q(z) are analytic at z₀
Periodic Sturm Liouville Systems
Periodic Boundary Conditions
y(a) = y(b) y'(a) = y'(b)
Where y(x) is a periodic function defined on a
Regular Sturm Liouville
P(x) and Q(x) singular at x = +- 1
D’Alembert’s Ratio Test
Radius of convergence - property for Legendre polynomials
If regular singular points at x=+-1 - the radius of convergence if likely to be UNITY
Confirm using D’Alembert’s Ratio test
-Diverge for |z|>1 : D’Alembert’s ratio test indicates divergence
Lim|(bk+1Z^2k+2)/bkZ^2k)>1 or lim|bk/bk+1| as k tends to infinity
Eigwnvalue are real
Define the eigenvalue and eigenfunction solutions to the problem as:
Lyk = -λk yk
- = = -λk
- = = = complex conjugate of
Comparing 1 and 2: clear λk = conjugate λk
So λk are real
Eigenfunctions Yj(x) Yk(x) corresponding to eigenvalues λj, λk are orthogonal with respect to inner product
Let λj, λk be distinct eigenvalues, L is self-adjoint, λj ≠ λk
- w = w = -λj w
- w = w = w = -λk as λk are real
Subtracting 2 from 1:
Adjoint
The operator A is said to be self joint if: A’ = A
Legendre Equation
(1-x²)y” -xy’ +λy = 0 where λ = v(v+1)
- index up
- use naive
- Eigenvalues: λk =k²
- Eigenfunctions: Tk(x)
Weight function: use integrating factor
1/√(1-x²)
Bessel Equation
x²w” +xw’ +(x²-v²)w = 0
W(z) =
AJv(z) + BJ-v(x) v>0
AJ0(z) +BY0(z) v=0
AJm(z) + BYm(z) v=m
Indicial: c²-v²
Recurrence: odd terms = 0
Make a2k into bk