Mendelian Genetics II & Hardy Weinberg Flashcards
Baby boy is born with a ventricular septal defect … Can be part of a genetic syndrome or not
Genetic Counseling impacts what two things?
Genetic Counseling Example
Baby boy is born with a ventricular septal defect … Can be part of a genetic syndrome or not
Impacts medical management & recurrence risk
1. Features of baby
2. Family history & pedigree
3. Can both be explained by a syndrome?
22q11.2 Deletion Syndrome
Velocardiofacial (VCF) syndrome or DiGeorge syndrome
Contiguous gene deletion syndrome on chromosome 22q11.2
what type of inheritance?
Penetrance is complete but effects range from mild to severe =? Variable Expression
22q11.2 Deletion Syndrome
Velocardiofacial (VCF) syndrome or DiGeorge syndrome
Contiguous gene deletion syndrome on chromosome 22q11.2 AD inheritance
Penetrance is complete but effects range from mild to severe Variable Expression
74% have CHD; 69% have palatal abnormalities; ~70% learning disabilities; ~77% immune deficiency
Pleiotropy
after confirming 22q11.2 Deletion Syndrome diagnosis with genetic testing….
Next steps
Confirm dx with genetic testing
Baby at risk for other multisystem problems (growth, immunodeficiency, VPI, feeding, psych)
Explains mom and uncle’s histories; test and coordinate care
Future children of mom or uncle at 50% risk
Future children of baby at 50% risk May be more or less severe
Prenatal diagnosis available
Help with adaptation, resources, referrals and support
note
note
- Marfan syndrome is a dominant genetic syndrome only caused by FBN1 gene mutations. All who have the gene mutation show some symptoms. Symptoms involve ocular, skeletal and/or cardiovascular systems.
Which of the following factors are observed?
A. Pleiotropy & Variable expressivity
B. Genetic heterogeneity & Pleiotropy
C. Incomplete penetrance & Genetic heterogeneity
D. A&C
A
- Marfan syndrome is a dominant genetic syndrome only caused by FBN1 gene mutations. All who have the gene mutation show some symptoms. Symptoms involve ocular, skeletal and/or cardiovascular systems.
Which of the following factors are observed?
Does the 4yo patient have Marfan syndrome?
A. No B. Yes C. More information is needed to confirm or exclude a diagnosis
More information is needed to confirm or exclude a diagnosis
Example and Clicker Questions:
2. John and Amy have a baby who is diagnosed with Cystic Fibrosis. Neither of them have any family history of cystic fibrosis. Neither of them have had genetic testing.
We expect that:
A. Either John or Amy must have subclinical CF
B. The baby must have two spontaneous CFTR mutations
C. Both parents are carriers of CF
c : recessive conditions parents are obligate carriers
blank note
We expect that:
A. Either John or Amy must have subclinical CF
B. The baby must have two spontaneous CFTR mutations
C. Both parents are carriers of CF
John and Amy have a baby who is diagnosed with Cystic Fibrosis. Neither of them have any family history of cystic fibrosis. Neither of them have had genetic testing.
John and Amy have carrier testing and both are carriers. What is the risk for their next child to have CF?
A. 1 in 4 (25%) B. 1 in 3 (33%) C. 1 in 2 (50%) D. 3 in 4 (75%)
A. 1 in 4 (25%)
Advanced Mendelian Genetics Outline
2/3 carrier risk for unaffected sibs in AR disease
New mutation in X‐LR lethal disorders (the second 2/3
rule)
Carrier risk ‐ when to use the pedigree, and what about when the family history is “negative?”
Hardy‐Weinberg Equilibrium
• Assumptions
• Forces that alter HWE
• Genotype calculations in AR disease
Examples
Advanced Mendelian Genetics Outline
2/3 carrier risk for unaffected sibs in AR disease
New mutation in X‐LR lethal disorders (the second 2/3
rule)
Carrier risk ‐ when to use the pedigree, and what about when the family history is “negative?”
Hardy‐Weinberg Equilibrium
• Assumptions
• Forces that alter HWE
• Genotype calculations in AR disease
Examples
explain Autosomal Recessive ____Rule
Autosomal Recessive 2/3 Rule
Unaffected sibling of someone with AR disease has a 2/3 carrier risk
X‐Linked Recessive _____ Rule
X‐Linked Recessive 2/3 Rule
In a population at equilibrium for a sex‐linked lethal trait (reproductively limiting), 1/3 of the mutations must arise anew each generation
1/3 of cases occur due to new mutations and 2/3 are inherited
**Assign 2/3 carrier risk to the mother
of the proband, if the only case in the family.
Bayesian Derived Rule
Bayesian Derived Rule
AKA Conditional Probability
Uses phenotypic information in pedigree to assess relative probability of two or more alternative genotypic possibilities (carrier vs. non‐carrier)
μ= new mutation rate Extremely small
Female Carrier Rate (Rare X‐linked recessive)
2μ + 1⁄2(2μ) + 1⁄4(2μ) + 1/8(2μ) + 1/16(2μ) +… = 4μ
This accounts for chance that the female had a new mutation on either X chromosome plus the chance that she inherited a mutation from anyone in the female lineage (as females are unaffected carriers)
A priori chance to be a non‐carrier, given negative family history = 1‐ 4μ= ~1
General population (non)carrier risk
Changed by having affected son
μ=
μ= new mutation rate Extremely small
General population (non)carrier risk
General population (non)carrier risk
Prior probability (Female at birth): carrier vs Non-Carrier Conditional Probability (Son is affected): carrier vs Non-Carrier Joint Probability: carrier vs Non-Carrier
Posterior Probability: carrier vs Non-Carrier
Prior probability (Female at birth): carrier vs Non-Carrier 4μ 1-(4μ ) = 1 Conditional Probability (Son is affected) 1/2 μ (new mutation in son) Joint Probability 2μ μ Posterior Probability 2/3 1/3
XLR scenarios where mom IS a carrier
XLR scenarios where mom IS a carrier
???
Pedigree vs. Population Data
Pedigree vs. Population Data
• Use pedigree data when informative to find genotype probabilities
• e.g. to find carrier risk when positive family history
• Use population genetics rules or given information to find genotype probabilities when pedigree information is not informative (negative).
• e.g. to find carrier risk when there’s no family history of the disorder
Hardy‐Weinberg Equilibrium
Hardy‐Weinberg Equilibrium Population genetics law
Independently formulated by English mathematician (Hardy) & German physician (Weinberg) in 1908
Apply to Recessive disorders to:
Calculate genotype frequencies from allele frequencies
Estimate heterozygote frequency (carrier rate) in a population
based on disease incidence
Estimate a person’s carrier risk or probability of disease occurrence when family history is negative
Hardy‐Weinberg Law- assumptions
Hardy‐Weinberg Law
The Hardy‐Weinberg Law states that under conditions assumed to exist in large human populations …
The frequencies of homozygous dominant AA, heterozygous Aa and homozygous recessive aa genotypes remain stable from generation to generation
Where p represents the allele frequency of A, q represents the allele frequency of a and
***p+q=1
Assumptions of the Hardy‐Weinberg Law For such “genetic equilibrium” to exist
Assumptions of the Hardy‐Weinberg Law For such “genetic equilibrium” to exist
Mating must be random i.e., mate selection should not be influenced by genotype
New mutation should be rare enough to ignore
All genotypes should be equally fit to contribute to the gene pool (reproduce)
Forces that Alter the Equilibrium of Alleles
Forces that Alter the Equilibrium of Alleles (so i think we assume for hardy that none of these exists)
● Preferential mating: mate selection on the basis of particular phenotypic attributes
● Mutations
● Mortality
● Infertility
● Immigration and emigration
● Genetic drift: random fluctuation of frequencies in small populations
● Founder effect (e.g. Amish, Ashkenazi Jewish)
● Heterozygote Advantage (e.g. sickle cell trait and malaria)
HWE Genotype & Phenotype Frequencies
HWE Genotype & Phenotype Frequencies
• The frequency of the three genotypes AA, Aa and aa is given by the terms of the binomial expansion of (p + q)2
• (p+q)x(p+q)=(p2)+(2pq)+(q2)
• The sum of all alleles in the population = 100%, and sum of all genotypes in the population = 100%
• p+q=1
• (p2)+(2pq)+(q2)=1
*q2 is what you can see & count; affected, observable phenotype (q2 = disease incidence) Genotype vs HWE term AA: p^2 Aa :2pq aa: q^2
Hardy Weinberg Equilibrium
p + q = 1 (“the sum of all alleles in the population =
Hardy Weinberg Equilibrium
p + q = 1 (“the sum of all alleles in the population = 100%”)
p2 + 2pq + q2 = 1 (“the sum of all genotypes in the population = 100%”)
Remember, a genotype is the combination of 2 alleles Using HWE
1. Identify which term the question asks you to solve for (e.g. a question asking for a carrier rate is asking you to solve for the 2pq term using given information)
2. Identify which terms are given (e.g. a disease incidence gives you q2)
3. Identify which terms you can solve for based on given information (e.g. you can find q if you know q2, you can find p if you know q…)