Medicinal Chemistry of Opioid Analgesics 3; Development of Morphine Analogues Flashcards

1
Q

What strategies are used to develop new analogues from the parent morphine molecule?

A
  • Vary substituents
  • Extend molecular structure
  • Simplify
  • Conformational/rotational restrictions
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2
Q

What did varying substituents (via phenolic alkylations) yield?

A

Alkylating the phenolic -OH led to poor/inactive compounds; the phenol is essential for activity (but the -OH at ‘6/on C-ring isn’t; glucuronidation in the body gives better analgesic)

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3
Q

What does extending molecular structure entail and why might it be beneficial?

A

Molecule is ‘extended’ by addition of potential extra binding groups; exploring receptor space outside of the parts that bind to the OG ligand.

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4
Q

Which position in morphine is it easiest to add substituents/what must be done first in order for this to occur?

A
  • Nitrogen atom

- N-demethylation required first; methyl group needs to be removed to leave secondary amine

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5
Q

What is semi-synthesis and why is it used when developing morphine analogues (when extending molecular structure)?

A
  • Using the OG compound extracted from natural sources as a starting point
  • Used when parent compound too complex/expensive to completely synthesise (morphine requires 20 steps which results in poor yield anyway)
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6
Q

What is the rough outline of steps to achieve N-alkylated morphine from morphine?

A
  • Reaction with chloroformate to make N into quaternary salt
  • Resulting Cl- nucleophile attacks the methyl and removes it
  • Treatment with methanol to cleave unwanted carbonate from earlier chloroformate yielding Normorphine
  • Acylate with acid chloride yields N-acylated morphine
  • Final reduction (removes ketone) gives N-alkylated morphine
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7
Q

How does agonist activity of the N-alkylmorphine increase with the size of the N-alkyl side chain?

A
  • Methyl, Ethyl, Propyl = decreasing agonism
  • Butyl = zero activity
  • Pentyl, Hexyl = increasing agonist activity
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8
Q

Which N-alkyl group conveyed 14x activity of morphine and why is this so?

A

Phenethyl; binding to a new unrecognised hydrophobic binding pocket (van der Waals), extending the pharmacophore.

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9
Q

What was observed when an allyl (or cyclopropylmethyl) group was added for the N-alkyl? What other reactions were required to turn it into an antagonist?

A
  • Very weak analgesic activity
  • Oxidation of the 6-OH (superfluous) and reduction of the C7-8 double bond led to NALOXONE
    »> No analgesic activity; pure antagonist.
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10
Q

What is the explanation for Naloxone’s antagonist activity?

A
  • Naloxone stabilises the inactive receptor conformation, decreasing signal transduction hence unproductive G-protein coupling
  • The allyl group is able to sit in the hydrophobic binding region when its in its inactive conformation; hydrophobic pocket is closed and closer to the allyl group as a result when receptor inactive; π electrons are able to interact wth it.
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11
Q

How does the N-phenethyl morphine analogue stabilise the active conformation of the receptor?

A
  • The extra phenethyl group is able to sit comfortably in the open hydrophobic binding region observed when the receptor is in its active conformation; stabilising it and shifting the equilibrium towards the active conformation, increasing signal transduction.
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12
Q

What does Simplification occur when trying to find new morphine analogues and how might it be beneficial?

A
  • Is entire molecular scaffold required?

- Lesser complexity = greater ease of synthesis

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13
Q

What does removal of the ‘E’ piperidine (N-containing) ring entail for analgesic activity?

A

Complete loss of activity (N essential)

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14
Q

What does removal of the ‘D’ ring (removal of cyclic ether/furan ring) entail for analgesic activity and what does it make?

A
  • Creates MORPHINANS

- Possess analgesic activity; therefore ether bridge is not strictly essential

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15
Q

How do morphinans compare with OG morphine and what differs stereochemically?

A
  • Morphinans display higher toxicity
  • Comparable dependence profile
  • Has 3 chiral centres instead of 5
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16
Q

How does N-methylmorphinan differ from morphine and why does it only have 20% morphine activity?

A
  • No ether bridge (obv)
  • Reduced C7-8 double bond
  • Missing phenolic -OH; hence reduced activity
17
Q

How does the morphinan Levorphanol compare to morphine and what is structurally different?

A
  • 5x potency and longer half life
  • Has phenolic -OH hence activity
  • No ether bridge (obv)
  • Reduced C7-8 double bond
18
Q

What is the name of the + isomer of levorphanol and what desirable properties does it present? How is it modified to a useful form?

A
  • Dextrophan
  • Insignificant analgesia
  • BUT antitussive properties
  • Methyl ether form = DEXTROMETHORPHAN
19
Q

Drug extension recap; what does an allyl on nitrogen/a phenethyl group convey?

A
  • Allyl = antagonist

- Phenethyl = greater activity

20
Q

What is formed via the removal of rings C (of ‘6 -OH) and D (ether bridge) and what is their activity?

A
  • Benzomorphans

- Retain analgesic activity (like morphinans) even with removal of 2 ring structures

21
Q

Though Metazocine displays the same potency as morphine, why is it not used?

A
  • Displays activity at kappa & sigma as well as mu

responsible for hallucinogenic effects

22
Q

Pentazocine has 2 methyls on an allyl at N-methyl; what activity does this confer?

A
  • Twin methyl groups decrease activity (akin to extending molecular structure with N-alkyls)
  • 33% activity of morphine, short duration and low risk of addiction (high clearance)