mditerms Flashcards

1
Q

Various theories exist which can be used to determine aerodynamic
characteristics of airfoils in various shapes along a supersonic flow. The
simplest of these is known as____________

a linearized, first order
theory based on sweeping assumptions

A

Ackeret Theory

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2
Q

Ackeret theory gives good results provided that the

A

Mach number is not too low and the airfoil section is not too thick

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3
Q

the drag calculated using these theories are
confined only to the estimation of

A

the wave drag

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4
Q

Characteristics of Supersonic Airfoil Sections

A

thinness
Sharp Leading Edge
Maximum thickness at half chord
Symmetry

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5
Q

ex thinness

A

To minimize flow deviations due to thick airfoil sections which bring
about shock losses, a supersonic airfoil should be of thin cross
sections. However, this should be subject to the structural
requirements of the aircraft

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6
Q

_____is necessary to keep an attached bow shock
wave on the airfoil section and to avoid losses due to a normal,
detached shockwave. This can be done by employing low thickness
to chord ratio to create a small leading edge angle which is
necessary to ensure shockwave attachment at low supersonic
speeds.

A

sharp leading edge

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7
Q

ensures expansion behind the
maximum thickness point which is similar in value to the
compressions ahead of it and to illustrate that this is conducive to
low values of drag

A

Maximum Thickness at Half Chord

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8
Q

The best wing section in theory for a supersonic flow is an

A

infinitely thin flat plate

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9
Q

For a given thickness to chord ratio, minimum wave drag is achieved using
the

A

double wedge or diamond airfoil

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10
Q

upper and
lower surfaces are formed by equal circular arcs

A

biconvex airfoils

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11
Q

ackeret theory formula for coefficient of pressure

A

cpu = -2 thetha_net/ sqrt(M^2 - 1)
cpl = -2 thetha_net/ sqrt(M^2 - 1)

where expansion is positive and compression is negative

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12
Q

Normal force coefficient formula

A

CN = 4 a/sqrt(M^2 - 1)

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13
Q

cl formula

A

CL = CN for small angle of attack
cl = 4 a/sqrt(M^2 - 1)

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14
Q

cd formula

A

Cd = 4a^2/sqrt(M^2 - 1)

= 1/4sqrt(M^2 - 1) (cl^2)

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15
Q

lift to weight ratio

A

1/a

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16
Q

Airfoil at Zero Degree Angle of Attack

A

𝐢𝑃1 = 𝐢𝑃2 = βˆ’ βˆ’2𝛿/βˆšπ‘€βˆž^2 βˆ’ 1
𝐢𝑃1 = 𝐢𝑃2 =2𝛿/βˆšπ‘€βˆž^2 βˆ’ 1
𝐢𝑃3 = 𝐢𝑃4 = βˆ’2𝛿/π‘€βˆž^2 βˆ’ 1

17
Q

Airfoil at Angle of attack 𝒂 < 𝛿
Consider the same double wedge ai

A

𝐢𝑃1 =2(𝛿 βˆ’ π‘Ž)/βˆšπ‘€βˆž^2 βˆ’ 1
𝐢𝑃2 =2(𝛿 + π‘Ž)/βˆšπ‘€βˆž^2 βˆ’ 1
𝐢𝑃3 = βˆ’2(𝛿 + π‘Ž)/βˆšπ‘€βˆž^2 βˆ’ 1
𝐢𝑃4 = βˆ’2(𝛿 βˆ’ π‘Ž)/βˆšπ‘€βˆž^2 βˆ’ 1

-++-

18
Q

Airfoil at Angle of attack 𝒂 = delta

A

cp1 = 0
cp2 = 4a/βˆšπ‘€βˆž^2 βˆ’ 1
cp3 = -4a/βˆšπ‘€βˆž^2 βˆ’ 1
cp4 = 0

19
Q

Airfoil at Angle of attack 𝒂 > 𝛿