Matrices Flashcards

1
Q

in terms of column vectors, Ax=b becomes

A

x1v1+x2v2+…+xnvn=b

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2
Q

for a 2x2 matrix, A, det(A) is

A

A11A22 - A12A21

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3
Q

for an n by n matrix, we calculate the determinant using

A

the laplace expansion

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4
Q

laplace expansion: what is j

A

any value between 1 and n

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5
Q

laplace expansion: what is Cij

A

the cofactor of matrix element Aij

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6
Q

laplace expansion: what is Mij

A

the minor
(det of A after row i and column j are removed)

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7
Q

det(A^T)=

A

det(A)

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8
Q

det(lambda A)=

A

lambda^n det(A) for an nxn matrix

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9
Q

det(AB)=

A

det(BA)=det(A)det(B)

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10
Q

effect on determinant when two rows/columns are interchanged

A

changes sign of det

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11
Q

if two rows/columns are multiples of each other then det =

A

0

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12
Q

multiplying a row by a non-zero scalar does what to det?

A

multiplies by same scalar

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13
Q

a square matrix is singular if

A

det(A)=0

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14
Q

a non-singular square matrix A has inverse A^-1, defined by

A

A^-1A = AA^-1 = I

where I is the identity matrix

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15
Q

inverse can be calculated by

A

A^-1=C^T/det(A)

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16
Q

(A^-1)^-1=

A

A

17
Q

inverse of the transpose of A =

A

transpose of the inverse of A

18
Q

(AB)^-1=

A

B^-1A^-1

DOES NOT EQUAL A^-1B^-1

19
Q

det(A^-1(=

A

1/det(A)

20
Q

the hermitian conjugate of a matrix is found by taking

A

the complex conjugate and the transpose

21
Q

a matrix is hermitian if

A

it is equal to its hermitian conjugate

22
Q

diagonal matrix

A

all non-diagonal elements are zero

23
Q
A
24
Q

upper triangular matrix

A

if Aij=0 for i>j

25
Q

lower triangular matrix

A

if Aij=0 for i<j

26
Q

symmetric matrix

A

equal to its transpose

27
Q

normal matrix

A

if A^crossA=AA^cross

hermitian matrices are examples of these

28
Q

orthogonal matrix

A

transpose is equal to the inverse

29
Q

unitary matrix

A

A^cross = inverse

equivalent of orthogonal matrices for complex matrices

30
Q

if for a non-zero vector, Ax=lambda x then

A

x is an eigenvector of A and lambda is the corresponding eigenvalue

31
Q

any scalar multiple mu x of x is also

A

an eigenvector with the same eigenvalue

32
Q

due to scalar multiple, it is more convenient to use

A

normalised eigenvectors (abs value of 1)

33
Q

steps to calculate eigenvalues and eigenvectors

A
  1. rewrite eigenvalue equation in form (A-lambda I)x=0
  2. find characteristic equation det(A-lambda I)=0
  3. roots are eigenvalues
  4. sub eigenvalues back into first eqn for eigenvectors
  5. normalise eigenvectors if required
34
Q
A