Maths Ext 2. Rearranging equations Flashcards
Calculate the value of A.
5A = 10
5 x A = 10
so A = 10 / 5
so A = 2
Calculate the value of A.
3A = 12
3 x A = 12
so A = 12 / 3
so A = 4
Calculate the value of A.
6A + 4 = 46
6A + 4 = 46
so 6A = 46 - 4 = 42
so A = 42 / 6
so A = 7
Calculate the value of A.
8A - 7 = 57
8A - 7 = 57
so 8A = 57 + 7 = 64
so A = 64 / 8
so A = 8
Calculate the value of A.
25A + 3 = 103
25A + 3 = 103
so 25A = 103 - 3 = 100
so A = 100 / 25
so A = 4
Calculate the value of N.
(3+4) + 17N = 41
(3+4) + 17N = 41
so 7 + 17N = 41
so 17N = 41 - 7 = 34
so N = 34 / 17
so N = 2
Calculate the value of N.
(3 x 4) + 12N = 156
(3 x 4) + 12N = 156
so 12 + 12N = 156
so 12N = 156 - 12 = 144
so N = 144 / 12
so N = 12
Calculate the value of N.
3N + 4N + 5N = 36
3N + 4N + 5N = 36
So 12N = 36
so N = 36 / 12
so N = 3
Calculate the value of N.
12N x 2 + 4 = 28
Remember we need to do the multiplication first.
12N x 2 + 4 = 28
so 24N + 4 = 28
so 24N = 28 - 4 = 24
so N = 24 / 24
so N = 1
Calculate the value of N.
3N + (4N x 2) + 2 = 123
3N + (4N x 2) + 2 = 123
so 3N + 8N + 2 = 123
so 11N + 2 = 123
so 11N = 123 - 2 = 121
so N = 121 / 11
so N = 11
If A = 3, calculate the value of B.
B = 3A + 7
Swap A for the actual value 3:
B = 3A + 7
B = (3 x 3) + 7
so B = 9 + 7
so B = 16
If A = 12, calculate the value of B.
B = 3A + 7
Swap A for the actual value 12:
B = 3A + 7
B = (3 x 12) + 7
so B = 36 + 7
so B = 43
If A = 15, calculate the value of B.
B = 4A - 12
Swap A for the actual value 15:
B = 4A - 12
B = (4 x 15) - 12
so B = 60 - 12
so B = 48
If A = 21, calculate the value of B.
B = 100 - 3A
B = 100 - 3A
so B = 100 - (3 x 21) = 100 - 63
so B = 37
If A = 9, calculate the value of B.
B = 22 x 2A
B = 22 x 2A
so B = 4 x 2A
so B = 8A
so B = 8 x 9
so B = 72
Rearrange this equation in terms of B.
A = B + 6
A = B + 6
so A - 6 = B
or B = A - 6
Rearrange this equation in terms of B.
A = 4B
A = 4B
so A / 4 = B
or B = A / 4
Rearrange this equation in terms of B.
A = 4B + 3
A = 4B + 3
so A - 3 = 4B
so (A - 3) / 4 = B
or B = (A - 3) / 4
Rearrange this equation in terms of B.
9A = 3B - 9
9A = 3B - 9
so 9A + 9 = 3B
so (9A + 9) / 3 = B
so 3A + 3 = B
or B = 3A + 3
Rearrange this equation in terms of B.
2A = 8B - 9 + 2B + 7
2A = 8B - 9 + 2B + 7
so 2A = 10B -2
so 2A - 2 = 10B
so (2A -2) / 10 = B
or B = (2A -2) / 10