Maths Flashcards
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putting every number in the first 4 blanks
then there is a chance the addition might be in the form of 3n;2n+1,3n+2
then we can put the last number accordingly to make it divisible by 3
which turns out to be three in every case
there fore there are 3 chances to put nay number in the last blank
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here the venn diagram approach would be much more easier
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https://youtu.be/3ztEBbO1vjs?t=30342
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