Brainscape's Knowledge GenomeTM

Browse over 1 million classes created by top students, professors, publishers, and experts.


See full index

A&P GENERAL 2023 TEST GUIDE > Mathematics > Flashcards

Mathematics Flashcards

1
Q
  1. What power of 10 is equal to 1,000,000,000?
    A— 10 to the sixth power.
    B— 10 to the tenth power.
    C— 10 to the ninth power.
A

C— 10 to the ninth power.

An easy way to tell the power of 10 to which a number has been raised is to count the number of places the decimal would have to be moved to leave a number between 1 and 10.
In this problem, the decimal would have to be moved nine places to the left.
1,000,000,000 is 1 × 10 9

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

8379-1.
What is defined as a group of bits representing a complete piece of information?
A— Byte.
B— Bit.
C— Word.

A

A— Byte.

A byte is composed of a group of 8 bits and represents a complete piece of information in a binary system.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

8379-2.
Convert the binary number 00001111 to a whole number.
A— 31
B— 15
C— 8

A

B— 15

The binary number 00001111 is converted bit by bit into whole number: 1000 = 8; 0100 = 4; 0010 = 2; and 0001=1; thus the entire binary number equals 8 + 4 + 2 + 1 = 15 as a whole number.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q
  1. Find the square root of 1,746.
    A— 41.7852
    B — 41.7752
    C — 40.7742
A

A— 41.7852

The square root of a number is the number that, when multiplied by itself, gives the number.
By using an electronic calculator, we find that the square root of 1,746 is 41.785165.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q
  1. (Refer to Figure 52.) Solve the equation.
    A — 115
    B— 4.472
    C— 5
A

To solve this equation, follow these steps: clear all of the parentheses, perform the multiplication, then the addition. Finally take the square root of the number you have just obtained.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q
  1. Find the square root of 3722.1835.
    A— 61.00971
    B — 61.00
    C— 61.0097
A

C— 61.0097

The square root of a number is the number that, when multiplied by itself, gives the number.
By using an electronic calculator, we find that the square root of 3,722.1835 is 61.00970005.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q
  1. Which of the following is equal to the square root of (-1776) ÷ (-2) – 632?
    A— 128
    B— 256
    C— 16
A

C— 16

Solve this problem in three steps:
1. Divide -1776 by -2: -1776 ÷ -2 = 888
2. Subtract 632 from 888: 888 – 632 = 256
3. Find the square root of 256:

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

8383-1.
(Refer to Figure 69.) Solve the equation.
A— 12
B— 60
C— 76

A

A— 12

The square root of 100 is 10.
The square root of 36 is 6.
The square root of 16 is 4. 10 + 6 – 4 = 12

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q
  1. 64 cubed equals
    A— 4
    B— 192
    C— 262,144
A

C— 262,144

The cube of a number is found by multiplying the number by itself three times.
64 3 = 64 × 64 × 64 = 262,144

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q
  1. Find the value of 10 raised to the negative sixth power. A— 0.000001
    B— 0.000010
    C— 0.0001
A

A— 0.000001

Ten raised to the negative sixth power (10-6 ) is equal to 0.000 001.
This negative number is the reciprocal of the positive sixth power of ten. It is found by dividing the number 1 by the sixth power of 10 (1,000,000).

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q
  1. What is the square root of 4 raised to the fifth power?
    A— 32
    B— 64
    C— 20
A

A— 32

The square root of four is two.
Two raised to the fifth power is 32.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q
  1. The number 3.47 × 10 to the negative fourth power is equal to
    A— .00347
    B— 34,700
    C— .000347
A

C— .000347

The value of 3.47 × 10-4 is found by multiplying 3.47 by 1 divided by 10,000 (1 × 10 4 ).
3.47 × 10-4 = 0.000347

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q
  1. Which alternative answer is equal to 16,300?
    A— 1.63 × 10 to the fourth power.
    B— 1.63 × 10 to the negative third power.
    C— 163 × 10 to the negative second power.
A

A— 1.63 × 10 to the fourth power.

1.63 × 10 4 = 16,300
1.63 × 10-3 = 0.00163
163 × 10-2 = 1.63

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q
  1. Find the square root of 124.9924.
    A— 111.8 × 10 to the third power.
    B— .1118 × 10 to the negative second power.
    C— 1,118 × 10 to the negative second power.
A

C— 1,118 × 10 to the negative second power.

The square root of 124.9924 is 11.18.
111.8 × 10 3 = 111,800
.1118 × 10-2 = 0.001118
1,118 × 10-2 = 11.18

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q
  1. What is the square root of 16 raised to the fourth power?
    A— 1,024
    B— 4,096
    C— 256
A

C— 256

The square root of 16 is 4.
4 raised to the fourth power is 256.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q
  1. (Refer to Figure 53.) Solve the equation.
    A— .0297
    B— .1680
    C — .0419
A

C — .0419

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
17
Q
  1. The result of 7 raised to the third power plus the square root of 39 is equal to
    A— 349.24
    B— .34924
    C— 343.24
A

A— 349.24

7 raised to the third power is 343.
The square root of 39 is 6.245.
The sum of these two numbers is 349.245.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
18
Q
  1. Find the square root of 1,824.
    A— 42.708 × 10 to the negative second power.
    B— .42708.
    C— .42708 × 10 to the second power.
A

C— .42708 × 10 to the second power.

The square root of 1,824 is
42.708. 42.708 × 10-2 = 0.42708
.42708 × 10 2 = 42.708

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
19
Q

8393-1.
(Refer to Figure 65.) Which of the figures is using scientific notation?
A— 1.
B— 2.
C— both 1 and 2.

A

A— 1.

Equation 1 uses scientific notation, equation 2 does not. Scientific notation requires 10 to be raised to a power. Four raised to the tenth power does not qualify as scientific notation.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
20
Q

8393-2.
(Refer to Figure 70.) Which alternative answer is equal to 5.59?
A— 1.
B— 2.
C— 3.

A

A— 1.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
21
Q

8393-3.
(Refer to Figure 67). Solve the equation.
A— 5.58.
B— 12.16.
C— 0.042.

A

C— 0.042.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
22
Q

8393-4.
(Refer to Figure 68.) Which results in the largest number?
A— 1.
B— 2.
C— 3.

A

B— 2.

  1. 4.631 5 = 2129.97205201
  2. 4.631 × 10 5 = 4.631 × 1000 = 463,100
  3. 4.631 × 10-5 = 4.631 × 0.00001 = .00004631
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
23
Q
  1. The total piston displacement in a reciprocating engine is
    A— the volume displaced by only one piston during one-half revolution of the crankshaft.
    B— the volume displaced by all the pistons during one revolution of the crankshaft.
    C— the volume displaced by all the pistons during two revolutions of the crankshaft.
A

B— the volume displaced by all the pistons during one revolution of the crankshaft.

The piston displacement of an engine is the total volume swept by the pistons in one revolution of the crankshaft.
The piston displacement is found by multiplying the area of the piston head by the length of the stroke (this gives the displacement of one cylinder).
Multiply the displacement of one cylinder by the number of cylinders in the engine.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
24
Q

8394-1.
What is the surface area of a cube where a side (edge) measures 7.25 inches?
A— 381.078 cubic inches.
B— 315.375 square inches.
C— 52.5625 square inches.

A

B— 315.375 square inches

Each surface of the cube is 7.252 = 52.5625 square inches.
A cube has six surfaces so the total surface area is:
52.5625 × 6 = 315.375 square inches.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
25
Q
  1. (Refer to Figure 54.) Compute the area of the trapezoid.
    A— 52.5 square feet.
    B— 60 square feet.
    C— 76.5 square feet.
A

A— 52.5 square feet

The area of a trapezoid is found by multiplying its altitude (5 feet in this problem) by the average length of the two bases (the average of 9 feet and 12 feet is 10.5 feet).
The area of this trapezoid is 5 × 10.5 = 52.5 square feet.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
26
Q

8395-1.
(Refer to Figure 71.) What is the volume of a sphere with a radius of 4.5 inches?
A— 47.71 cubic inches.
B— 381.7 square inches.
C— 381.7 cubic inches.

A

C— 381.7 cubic inches.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
27
Q
  1. What size sheet of metal is required to fabricate a cylinder 20 inches long and 8 inches in diameter? (Note: C = π × D)
    A— 20 inches × 25-5/32 inches.
    B— 20 inches × 24-9/64 inches.
    C— 20 inches × 25-9/64 inches.
A

C— 20 inches × 25-9/64 inches.

The sheet metal needed to fabricate a cylinder 20 inches long and 8 inches in diameter is 20 inches long and 25- 9/64 inches wide.
8 × π (3.1416) = 25.1328
25.1328 is slightly less than 9/64.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
28
Q
  1. (Refer to Figure 55.) Find the area of the triangle shown.
    A— 12 square inches.
    B— 6 square inches.
    C— 15 square inches.
A

B— 6 square inches.

The area of a triangle is one half of the product of its base times its altitude.
The base of this triangle is 4 inches and the altitude is 3 inches. The area is (4 × 3) ÷ 2 = 6 square inches.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
29
Q
  1. What force is exerted on the piston in a hydraulic cylinder if the area of the piston is 1.2 square inches and the fluid pressure is 850 PSI?
    A— 1,020 pounds.
    B— 960 pounds.
    C— 850 pounds.
A

A— 1,020 pounds.

The force exerted on a piston by hydraulic fluid is found by multiplying the area of the piston by the amount of pressure acting on each square inch of the piston.
In this problem the area is 1.2 square inches and a pressure of 850 pounds acts on each square inch. The force is 1,020 pounds.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
30
Q
  1. A rectangular-shaped fuel tank measures 60 inches in length, 30 inches in width, and 12 inches in depth. How many cubic feet are within the tank?
    A— 12.5
    B— 15.0
    C— 21.0
A

A— 12.5

The volume of a rectangular solid figure (such as this fuel tank) is found by multiplying its length, width, and depth together.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
31
Q
  1. Select the container size that will be equal in volume to 60 gallons of fuel. (7.5 gal = 1 cu ft)
    A— 7.5 cubic feet.
    B— 8.0 cubic feet.
    C— 8.5 cubic feet.
A

B— 8.0 cubic feet.

32
Q
  1. (Refer to Figure 56.) Compute the area of the trapezoid. A— 24 square feet.
    B— 48 square feet.
    C— 10 square feet.
A

C— 10 square feet.

The area of a trapezoid is found by multiplying its altitude (2 feet in this problem) by the average length of the two bases (the average of 4 feet and 6 feet is 5 feet). The area of this trapezoid is 10 square feet.

33
Q
  1. (Refer to Figure 57.) Determine the area of the triangle formed by points A, B, and C. A to B = 7.5 inches A to D = 16.8 inches
    A— 42 square inches.
    B— 63 square inches.
    C— 126 square inches.
A

B— 63 square inches.

34
Q
  1. What is the piston displacement of a master cylinder with a 1.5-inch diameter bore and a piston stroke of 4 inches?
    A— 9.4247 cubic inches.
    B— 7.0686 cubic inches.
    C— 6.1541 cubic inches.
A

The piston displacement of a master cylinder is found by multiplying the area of the piston head by its stroke.
The area of the piston is found by squaring its diameter (1.5 inch in this problem) and multiplying this by the constant 0.7854 (one-fourth of π).
When the area of 1.767 square inches is multiplied by the stroke of 4.0 inches, we find that the displacement of the master cylinder to be 7.0686 cubic inches.

35
Q
  1. How many gallons of fuel will be contained in a rectangular-shaped tank which measures 2 feet in width, 3 feet in length, and 1 foot 8 inches in depth? (7.5 gal = 1 cu ft)
    A— 66.6
    B— 75
    C— 45
A

B— 75

36
Q
  1. A rectangular shaped fuel tank measures 27-1/2 inches in length, 3/4 foot in width, and 8-1/4 inches in depth. How many gallons will the tank contain?
    (231 cu in = 1 gal)
    A — 7. 3 6 6
    B— 8.83
    C — 170.156
A

B— 8.83

37
Q
  1. A four-cylinder aircraft engine has a cylinder bore of 3.78 inches and is 8.5 inches deep. With the piston on bottom center, the top of the piston measures 4.0 inches from the bottom of the cylinder. What is the approximate piston displacement of this engine?
    A— 200 cubic inches.
    B— 360 cubic inches.
    C— 235 cubic inches.
A

The piston displacement of one cylinder of a reciprocating engine is found by multiplying the area of the piston head by the length of the stroke.
The area of the piston is found by squaring the bore (3.78 inches in this problem) and multiplying this by the constant 0.7854 (one-fourth of π).
When the area of 11.22 square inches is multiplied by the stroke of 4.5 inches (the depth of the cylinder minus the distance from the top of the piston at BDC to the bottom of the cylinder), we find that the displacement of one cylinder is 50.49 cubic inches.
This is a four-cylinder engine, so the total displacement is four times that of a single cylinder. The total displacement is 201.96 cubic inches.

Stroke = 8.5 – 4 = 4.5 inches
PD = Area × Stroke × Number of cylinders
= 11.22 × 4.5 × 4 = 201.96 cubic inches

38
Q
  1. A rectangular-shaped fuel tank measures 37-1/2 inches in length, 14 inches in width, and 8-1/4 inches in depth. How many cubic inches are within the tank?
    A— 59.75
    B — 433.125
    C— 4,331.25
A

C— 4,331.25

39
Q
  1. A six-cylinder engine with a bore of 3.5 inches, a cylinder height of 7 inches and a stroke of 4.5 inches will have a total piston displacement of
    A— 256.88 cubic inches.
    B— 259.77 cubic inches.
    C— 43.3 cubic inches.
A

The piston displacement of one cylinder of a reciprocating engine is found by multiplying the area of the piston head by the length of the stroke.
The area of the piston is found by squaring the bore (3.5 inches in this problem) and multiplying this by the constant 0.7854 (one fourth of π).
When the area of 9.621 square inches is multiplied by the stroke of 4.5 inches, we find that the displacement of one cylinder is 43.295 cubic inches.
This is a six-cylinder engine, so the total displacement is six times that of a single cylinder. The total displacement is 259.77 cubic inches.

40
Q
  1. Select the fraction which is equal to 0.0250.
    A— 1/4
    B— 1/40
    C— 1/400 1/40 is equal to 0.025. 1/4 is equal to 0.25. 1/400 is equal to 0.0025.
A

B— 1/40

1/40 is equal to 0.025.
1/4 is equal to 0.25.
1/400 is equal to 0.0025.

41
Q
  1. 1.21875 is equal to
    A— 83/64
    B— 19/16
    C— 39/32
A

C— 39/32

Divide the decimal fractional part of this mixed number by the decimal equivalent of 1/64.
.21875 ÷ 0.015625 = 14
The common fraction equivalent to 1.21875 is 1-14/64. This is the same as 78/64 or 39/32.

42
Q
  1. If the volume of a cylinder with the piston at bottom center is 84 cubic inches and the piston displacement is 70 cubic inches, then the compression ratio is
    A— 7:1
    B — 1.2:1
    C— 6:1
A

C— 6:1

43
Q
  1. Express 7/8 as a percent.
    A— 8.75 percent.
    B— .875 percent.
    C— 87.5 percent.
A

C— 87.5 percent.

44
Q
  1. What is the speed of a spur gear with 42 teeth driven by a pinion gear with 14 teeth turning 420 RPM?
    A— 588 RPM.
    B— 160 RPM.
    C— 140 RPM.
A

C— 140 RPM.

The speed ratio is the reciprocal of gear ratio.
The spur gear with 42 teeth is driven by a pinion gear with 14 teeth. This is a gear ratio of 3:1. The spur gear will turn at 1/3 the speed of the pinion gear.
If the pinion gear turns at a speed of 420 RPM, the spur gear will turn at a speed of
420 ÷ 3 = 140 RPM.

45
Q
  1. An engine develops 108 horsepower at 87 percent power. What horsepower would be developed at 65 percent power?
    A— 81
    B— 70
    C— 61
A

A— 81

If an engine develops 108 horsepower at 87 percent power, its 100 percent power is 108 ÷ 0.87 = 124.13 horsepower.
Its horsepower at 65 percent power is found by multiplying 124.13 by 0.65, or 80.68 horsepower.

46
Q
  1. A certain aircraft bolt has an overall length of 1-1/2 inches, with a shank length of 1-3/16 inches, and a threaded portion length of 5/8 inch. What is the grip length?
    A— .5625 inch.
    B— .8750 inch.
    C— .3125 inch.
A

A— .5625 inch.

The grip length of a bolt is the length of the unthreaded portion of the shank. If the shank is 1-3/16 (1.1875) inches long, and the threaded portion is 5/8 (0.625) inch, the grip length is 1.1875 – 0.625 = 0.5625 inch.

47
Q
  1. Select the fractional equivalent for a 0.0625 inch thick sheet of aluminum.
    A— 1/16
    B— 3/64
    C— 1/32
A

A— 1/16

48
Q

8416-1.
Examples of units used in the conventional (U.S. or English) measurement include
A— inch, meter, and gram.
B— inch, kilo, and liter.
C— inch, ounce, and pound.

A

C— inch, ounce, and pound.

Some of the conventional U.S. or English units of measure are: inches, feet, yards, miles, ounces, pints, gallons, and pounds.

49
Q
  1. Express 5/8 as a percent.
    A— .625 percent.
    B— 6.25 percent.
    C— 62.5 percent.
A

C— 62.5 percent.

49
Q
  1. Express 5/8 as a percent.
    A— .625 percent.
    B— 6.25 percent.
    C— 62.5 percent.
A

C— 62.5 percent.

50
Q
  1. Select the decimal which is most nearly equal to 77/64. A — 0.08311
    B — 0.8311
    C— 1.2031
A

C— 1.2031

To convert a common fraction into a decimal fraction, divide the numerator by the denominator.

77 ÷ 64 = 1.203125

51
Q
  1. An airplane flying a distance of 750 miles used 60 gallons of gasoline. How many gallons will it need to travel 2,500 miles?
    A— 31,250
    B— 9,375
    C— 200
A

C— 200

If the airplane uses 60 gallons of gasoline while flying 750 miles, it is getting 750 ÷ 60 or 12.5 miles per gallon of fuel burned.
At this rate of fuel consumption, it will require 2,500 ÷ 12.5 = 200 gallons of fuel to fly 2,500 miles.

52
Q
  1. What is the speed ratio of an input gear with 36 teeth meshed to a gear with 20 teeth?
    A— 9:5
    B — 1:0.56
    C — 1:1.8
A

C — 1:1.8

The speed ratio is the reciprocal of the gear ratio.
The large gear has 36 teeth and the small gear has 20 teeth. This is a gear ratio of 1.8:1, or a speed ratio of 1:1.8.

53
Q
  1. A pinion gear with 14 teeth is driving a spur gear with 42 teeth at 140 RPM. Determine the speed of the pinion gear.
    A— 588 RPM.
    B— 420 RPM.
    C— 126 RPM.
A

B— 420 RPM.

The speed ratio is the reciprocal of the gear ratio.
The spur gear with 42 teeth is driven by a pinion gear of 14 teeth. This is a gear ratio of 3:1. The spur gear will turn at 1/3 the speed of the pinion gear.
If the spur gear turns at a speed of 140 RPM, the pinion gear will have to turn at a speed of 420 RPM.

54
Q
  1. The parts department’s profit is 12 percent on a new part. How much does the part cost if the selling price is $145.60?
    A — $128.13
    B— $125.60
    C— $130.00
A

C— $130.00

In this problem, the cost of the magneto is equal to 100 percent. Since a 12 percent profit is specified, the selling price must be 112 percent.
If the selling price (112%) is equal to $145.60, the cost (100%) can be found by dividing the selling price by 1.12.

$145.60 ÷ 1.12 = $130.00

55
Q
  1. If an engine is turning 1,965 rpm at 65 percent power, what is its maximum rpm?
    A— 2,653
    B— 3,023
    C— 3,242
A

B— 3,023

1,965 RPM is 65% of 3,023 RPM.
1,965 ÷ 0.65 = 3,023

56
Q
  1. An engine of 98 horsepower maximum is running at 75 percent power. What is the horsepower being developed?
    A— 87.00
    B— 33.30
    C— 73.50
A

C— 73.50

Seventy-five percent of 98 horsepower is equal to
98 × 0.75 = 73.50 horsepower.

57
Q
  1. A blueprint shows a hole of 0.17187 to be drilled. Which fraction size drill bit is most nearly equal?
    A — 11/64
    B— 9/32
    C — 11/32
A

A — 11/64

The hole specified on the blueprint has a diameter of 0.17187 inch. It could be drilled with a 11/64 drill.
11/64 is equal to 0.171875.
9/32 is equal to 0.28125.
11/32 is equal to 0.34375.

58
Q
  1. Which decimal is most nearly equal to a bend radius of 31/64?
    A— 0.2065
    B— 0.4844
    C— 0.3164
A

B— 0.4844

To convert the common fraction 31/64 into a decimal fraction, divide the numerator, 31, by the denominator,
64. 31 ÷ 64 = 0.484375

59
Q
  1. Sixty-five engines are what percent of 80 engines?
    A— 81 percent.
    B— 65 percent.
    C— 52 percent.
A

A— 81 percent.

To find the percentage of engines represented by 65 out of 80, we find the ratio of 65 to 80 by dividing 65 by 80.
65 ÷ 80 = 0.8125
Then we change this decimal fraction into a percentage by multiplying it by 100. Sixty-five engines is 81.25 percent of 80 engines.

60
Q
  1. The radius of a piece of round stock is 7/32. Select the decimal which is most nearly equal to the diameter.
    A— 0.2187
    B— 0.4375
    C— 0.3531
A

B— 0.4375

The diameter of the stock is two times the radius.
We need to find the decimal equivalent of 2 × 7/32, or 7/16 inch.
By dividing the numerator by the denominator, we find that we will need a piece of round stock with a diameter of 0.4375 inch.

61
Q
  1. Maximum life for a certain part is 1100 hours. Recently, 15 of these parts were removed from different aircraft with an average life of 835.3 hours. What percent of the maximum part life has been achieved?
    A— 75.9 percent.
    B— 76.9 percent.
    C— 75.0 percent.
A

A— 75.9 percent.

In this problem, 1100 hours represents 100 percent of the life of the part. The percentage represented by 835.3 hours can be found by dividing 835.3 by 1100, and multiplying this answer by 100.
835.3 ÷ 1100 = 0.759
0.759 × 100 = 75.9 percent

62
Q
  1. What is the ratio of 10 feet to 30 inches?
    A— 4:1
    B — 1:3
    C— 3:1
A

A— 4:1

Ten feet is equal to 120 inches. The ratio of 120 ÷ 30 is 4:1.

63
Q
  1. How much current does a 30-volt, 1/2 horsepower motor that is 85 percent efficient draw from the bus? (Note: 1 horsepower = 746 watts)
    A— 14.6 amperes.
    B— 12.4 amperes.
    C— 14.3 amperes.
A

A— 14.6 amperes.

64
Q
  1. Solve the equation. [(4 × -3)+(-9 × 2)] ÷ 2 =
    A— -30
    B — -15
    C— -5
A

B — -15

In a problem of this type, work from the inside outward:
1. First solve the parts of the problem inside the parentheses.

4 × -3 = -12 -9 × 2 = -18

  1. Now combine the two values just found.

-12 + -18 = -30

  1. Divide this answer by 2.

-30 ÷ 2 = -15

65
Q
  1. Solve the equation. (64 × 3/8) ÷ 3/4 =
    A— 18
    B— 24
    C— 32
A

C— 32

First work the part of the problem inside the parenthesis, and then do the division.

64 × 3/8 = 24
24 ÷ 3/4 = 32

66
Q
  1. Solve the equation.
    (32 × 3/8) ÷ 1/6 =
    A— 12
    B— 2
    C— 72
A

C— 72

  1. First, work the part of the problem inside the parenthesis:

(32 × 3/8) = 12

  1. Now divide 12 by 1/6. To divide by a fraction, invert the divisor (1/6) and multiply.

12 ÷ 1/6 = 12 × 6 = 72

67
Q
  1. What is the ratio of a gasoline fuel load of 200 gallons to one of 1,680 pounds?
    A— 5:7
    B— 2:3
    C— 5:42
A

A— 5:7

Gasoline has a nominal weight of 6 pounds per gallon. So, 200 gallons of gasoline will weigh 1,200 pounds. The ratio of a load of 1,200-pound load to one of 1,680 pounds is the ratio of:
1,200 ÷ 1,680 = 0.7142.
The ratio 5:7 is 0.7142.
The ratio of 2:3 is 0.6667.
The ratio of 5:42 is 0.1190.

68
Q
  1. Solve the equation.
    1/2 (-30 + 34) 5 =
    A— 10
    B— 95
    C— 160
A

A— 10

First, solve the part of the problem inside the parenthesis, then multiply by 1/2 (divide by 2) and finally multiply by five.
(-30 + 34) = 4
4 ÷ 2 = 2
2 × 5 = 10

69
Q
  1. (Refer to Figure 58.) Solve the equation.
    A — 174.85
    B— 68.037
    C — 14.002
A

C — 14.002

  1. First, solve the parts of the problem inside parentheses:

(-35 + 25) = (-10)

  1. Combine the factors (the parts) of the first term (the part of the problem to the left of the plus sign).

(-10) × (-7) = 70

  1. Clear the parenthesis on the right of the plus sign by
    raising 16 to its -2 power.

16-2 = 1/16 2 = 1/256 = 0.003906

  1. Multiply the two factors of the second term.

(3.1416) × (0.003906) = 0.01227

  1. Add the two terms above the line.

70 + 0.0122 = 70.0122

  1. Divide this by the square root of 25, which is 5.

70.0122 ÷ 5 = 14.002

70
Q
  1. (Refer to Figure 59.) Solve the equation.
    A— +31.25
    B— -5.20
    C— -31.25
A

B— -5.20

This problem can be rewritten as 125 ÷ -4, divided by - 36 ÷ -6.
125 ÷ -4 = -31.25
-36 ÷ -6 = 6
-31.25 ÷ 6 = -5.208

71
Q
  1. Solve the equation.
    4 – 3[-6(2 + 3) + 4] =
    A— 82
    B— -25
    C— -71
A

A— 82

  1. Begin this problem by working the inside parentheses, and then work outward.
                (2 + 3) = 5 
            (-6 × 5) = -30 
            (-30 + 4) = -26
  2. Next, the multiplication is done.
                3 × -26 = -78
  3. Now, perform the subtraction.
                4 – (-78) = 82
72
Q
  1. Solve the equation.
    -6[-9(-8 + 4) – 2(7 + 3)] =
    A— -332
    B— 216
    C— -96
A

C— -96

  1. Begin the problem by working the inside parentheses in the first term.

(-8 + 4) = -4

  1. Combine the factors in the first term.

-9 × -4 = 36

  1. Clear the parenthesis in the second term.

(7 + 3) = 10

  1. Multiply this value by 2.

10 × 2 = 20

  1. Combine the two terms in the brackets.

36 – 20 = 16

  1. Multiply this by -6.

-6 × 16 = -96

73
Q
  1. Solve the equation.
    (-3 + 2)(-12 – 4) + (-4 + 6) × 3
    A— 20
    B— 22
    C— 28
A

B— 22

  1. Begin this problem by clearing the parentheses.
                 (-3 + 2) = -1   
             (-12 – 4) = -16   
             (-4 + 6) = 2
  2. Then perform the multiplication.
                -1 × -16 = 16   
             2 × 3 = 6
  3. And finally the addition.
                 16 + 6 = 22
74
Q
  1. (Refer to Figure 60.) Solve the equation.
    A — 11. 9
    B — 11.7
    C — 11.09
A

A — 11. 9

75
Q

8442-1.
(Refer to the Figure 66.) Solve the equation.
A— 35,998
B— 36,002
C— 62,208

A

B— 36,002

-4 + 6 + 10 3 ( √ 1 296 ) simplifies to: 2 + 1,000(36), which equals 36,002.

A&P GENERAL 2023 TEST GUIDE (12 decks)

Brainscape helps you reach your goals faster, through stronger study habits.
© 2024 Bold Learning Solutions. Terms and Conditions