Materials 2 Flashcards
1
Q
How to translate the design requirements into properties and constraints?
A
- Function?
- Constraints.
- Objectives.
- Free variables.
2
Q
FCC
A
Face- centred cubic.
{111} are close packed.
<110> directions are close packed.
3
Q
HCP
A
Hexagonal Close Packed.
{0001} planes are close packed.
<1120} directions are close packed.
Is most brittle as it has only 3 or 6 slip systems.
4
Q
BCC
A
Body centred cubic.
No close packed planes.
<111> directions are close packed.
So, has it has no close packed planes, it is less ductile.
5
Q
Define a slip system
A
The set of symmetrically identical slip planes (and associated family of slip directions) for which dislocation motion can easily occur and lead to plastic deformation.
6
Q
Define polymorphism.
A
Any material that can exist in more than one form or structures.
7
Q
What are the types of solid solutions?
A
Substitutional solid solution.
Interstitial solid solution.
8
Q
Explain the types of substitutional solid substitution.
A
- Random
- Ordered (where B atoms prefer A atoms)
- Clustered (where B atoms prefer B atoms)
9
Q
How much solute can we dissolve?
A
If you add too much solute, you may exceed the solubility limit and the solute will precipitate as a new solution.
This could be 2 random solutions (where nothing has an order at all)
or perhaps 1 ordered and 1 random.
10
Q
Define a phase
A
A region of material with uniform physical and chemical properties. Phases have their own grains.
11
Q
Define a grain-boundary
A
A grain is a region with the same crystal orientation, but has an eenrgy associated with them.
12
Q
Define phase boundary
A
For 2-phase materials, these have an energy associated with them to join them together.
13
Q
Boundaries in metals.
A
- Coherent (has the least energy)
- Coherency-strain
- Semi-coherent (has gaps)
- Incoherent (has the most energy)
14
Q
Interfacial energy
A
E = GB * A
Grain boundary energy * interfacial area.
If the GB is isotropic, then the lowest E is for the shape with the lowest interfacial area.
15
Q
For isotropic shapes, what is the best interfacial area? in two phase materials?
A
A sphere.
Because the grains want to grow in the direction of the lowest energy - and mathematically, the best shape in this case is a sphere.
16
Q
For non-isotropic shapes, what is the best interfacial area? in two phase materials?
A
A plate. - it has the lowest gb energy.
17
Q
What happens if the E(gb) = E(ab)
A
The beta can form their own grains adjacent to the alpha grains. This is the shape that minimises energy.
18
Q
Define an alloy
A
The result of taking a pure metal and
adding other elements (Or “mixture of
elements”)
19
Q
Define an Alloy System
A
All the alloys that can be made from the
components
20
Q
Define a component
A
The elements that make up an alloy.
21
Q
Define a composition
A
Usually measured in weight % (mass%)
22
Q
Define constitution
A
A combination of:
The overall composition (e.g. Al-4Cu)
The number of phases present
The composition of each phase
The percentage by weight of each phase
23
Q
What does the alloy constitution base on?
A
The number of phases present
The volume fraction of phases
The composition of each phase
These depend on:
- overall composition
- temperature.
24
Q
What happens about the liquidus line
A
All is liquid.
25
How to say
'18 wt% Nickel in Copper'
Cu-18wt% Ni
26
How to calculate the proportion by weight of each phase inside the L+α shape?
This is a 2 phase area.
1.Draw a horizontal line at the point, until it meets the liquidus and solidus line.
2. Read the weight % at those points.
The one meeting the Liquidus line is Cl, and the other is Cα.
Know that by conservation of mass, Cα + CL = 100%,
and C0 = fL(CL) + fα(Cα)
Can create an equatoin to calculate fα and
27
Melting point and alloys
They don't have a specific melting point, but have a range instead.
28
Define a eutectic phase diagram
It is the phase diagram for a limited solubility limit.
29
A Eutectic Phase Diagram: Single phase alloys
This is the far left/ right side of the diagram. It results in all alpha or beta grains being formed.
30
A Eutectic Phase Diagram: Two phase alloys
Starts with a liquid, ends with the beta phases forming on the alpha grain boundaries. This is not a good way to store them, because it reduces the strength of the material, allows man more dislocations to form.
31
A Eutectic Phase Diagram: The eutectic composition
The liquid transforms from Liquid into solid alpha+ solid beta at one temperature - called the Eutectic temperature, at the eutectic point.
It forms sort of stripes of alpha and beta alternating, in a laminar structure, called the eutectic phase.
32
A Eutectic Phase Diagram: Off-eutectic alloys
It is all liquid at first, then above the eutectic temperature, solid grains start to form in the liquid. To calculate the fα(T) = (C0 - CL)/(Cα - CL)
At the eutectic temperature, the remaining liquid undergoes eutectic solidification. To calculate the fEUT(T) = (C0 - C(EUT))/(Cα - C(EUT))
33
Define Eutectoid
alpha -> beta + gamma.
34
Define Peritectic
L + alpha -> beta.
35
Define internal energy (U)
The sum of the kinetic potential and electrical energy of the atoms in the material.
36
Gibbs Energy
At equilibrium - the Gibbs Energy will be the lowest. If ∆G is negative, then it means there is a driving force for things to change.
37
Equation for Gibbs Energy
G = H -TS.
G = U +PV -TS
38
Change in gibbs energy when a solid becomes a liquid.
There is no change in gibbs energy, this is a neutral equilibrium.
39
Change in gibbs energy when a liquid becomes a solid.
There is a reduction in Gibbs energy if the liquid becomes a solid.
This is an unstable situation and a driving force for change.
The G(s) < G(L) for pure water at T
40
Coarsening (basic explanation)
If you have fine grains, and you increase the temperature, the size of the grains will increase. Therefore, the gibbs energy decreases, same with the driving force. So, if we have particles of phase Beta within a matric of phase Beta, there will be a change in the GE if the shape of the particles change.
41
Coarsening (the magnitude of the driving force)
If we decrease the size of the phase boundary, then we can minimise the precipitate growth.
42
Linking the driving force to an undercooling - what happens at a small departure from the melting point?
For a small departure from the melting point, the values of H and S can be considered to be independent of T.
43
Define undercooling and what happens in it? - Equation for it.
Cooling the liquid past the point of it melting. The bigger the undercooling, the bigger the driving force.
Undercooling = Tm - T.
44
Relation between the driving force and the kinetic energy (the change in transformation rate with temperature)
The driving force for transformation DeltaG increases as the temperature decreases below the melting point. This increases the undercooling; decreasing the kinetic energy. So the probability that an atom will jump from the liquid to the solid decreases.
45
Define diffusion
Mass transport by atomic motion.
46
What are structure sensitive properties
They are influenced significantly by changes to the microstructure. Density and Young's Modulus.
47
What are structure insensitive properties
Aren't influenced significantly by changes to the microstructure.
Yield strength, tensile strength, ductility, fracture toughness.
48
What happens if the alpha-beta Phase boundary is less than 1/2 the Grain boundary?
Then, cos theta = 1, so theta = 0.
This means that the beta phase will spread out along all the alpha grain boundaries.
49
Define an equilibrium constitution
At a given constant T and pressure p, there is no further tendency for the constitution to change with time.
50
What happens at the eutectic point?
L - > alpha + beta.
51
What happens at the eutectoid point?
alpha -> beta + gamma.
Upon cooling, the solid phase transforms isothermally and reversibly into 2 new solid phases that are intimately mixed.
52
Explain diffusion controlled phase transformation
Eutectoid growth is this way.
An element diffuses out of one phase and into another phase.
beta -> alpha + gamma.
alpha has little B, and gamma has a lot of B.
53
Explain why we need rcrit?
Once a nucleus has nucleated, it will not simply just start to grow immediately.
It will only grow if growing means it'll have less energy.
All atoms that have radius above rcrit will nucleate.
54
Diffusive Transform.
Generally, as T is far from Tm, we expect more nuclei as the temperature decreases below the equilibrium temperature. But not too much, then the atoms don't have enough thermal energy to form the second phase.
55
What is displacive transformation?
We quench and miss the nose of the TTT curve. Small lenses of BCC-Fe form at the grain boundaries and propagate across the grains at the speed of sound. There is a switch zone in front of the lenses where the FCC_Fe is broken and BCC_Fe is made instead.
56
How does FCC turn into BCC in displacive transformation?
Inside 2 FCC is a BCC, but it's slightly strained. The growth of the lenses enforces this strain back to a normal BCC. There must be enough Delta_G to be converted to the strain energy and allow the displacive transformation to happen.
57
Phases in steel:
gamma - Austenite. - FCC.
alpha - Ferrite - BCC.
Fe3C - Iron carbide or cementite.
58
What is pearlite.
alpha-Fe and Fe3C eutectoid is called pearlite.
At the eutectoid transformation, the pearlite nodules grow.
59
Explain the diffusive transformation in hypo-eutectoid steels.
1. There are gamma grains.
2. Primary alpha nucleates.
3. Alpha continues to grow.
4. At the eutectoid composition, the gamma transforms into pearlite.
5. Then there are grains of primary alpha + nodules of pearlite in the mixture.
60
Explain the diffusive transformation in hyper-eutectoid steels
1. There are gamma grains.
2. Then, Fe3C nucleates.
3. Fe3C grows.
4. At the eutectoid composition, the gamma becomes pearlite, and grow to consume the remaining gamma. And the alpha-Fe continue to nucleate.
61
What are the mechanical properties for carbon steels
Fraction of Fe3C increases with increasing C.
The yield strength and UTS increases with C content because Fe3C is a hard phase.
Ductility decreases with C content because alpha-Fe-Fe3C interfaces are good at nucleating cracks.
62
What happens when you add Carbon to gamma-Fe through a dispacive transformation?
Well BCC_Fe can only dissolve 0.035 wt% C. But usually, we add more than that. So, upon quenching this, a new shape, called a Body Centred Tetragonal structure forms.
The hardness of Martensite increases with Carbon content, because the carbon distorts the BCT Lattice more. The lattic distortion gives great hardness but is a very brittle material.
63
Explain tempering steel
If we reheat the steel to 300-600 degrees C, the carbon atoms have enough thermal energy to leave the supersaturated BCT-martensite and will react with Fe to form Fe3C.
This causes numerous, small closely packed particles of Fe3C. And the BCT Structure relaxes back to BCC.
This means that the ductility increases while the small Fe3C particles maintain a good strength/ hardness. (Don't hold it there for too long though, or else the Fe3C will coarsen. which is rlly bad to retarding dislocation motion.)
64
Stabilisers and solution strengtheners for steel.
Mn - stabilises the gamma Austenite phase.
Cr - stabilises the alpha Ferrite phase.
65
Improving hardenability in steel.
Essentially, as martensite is quite hard, we want to form this easily and all the way to the centre of a thick component.
You can add Mo, Mn, Cr and Ni additions- these displace the TTT curves to longer times, enabling the martensite to form even at slow cooling rates.
66
Carbide forming additions in steel.
Certain elements in steel can form carbides - which are more thermodynamically stable than cementite. At high enough concentrations, these will be formed, and not cementite.
Ex: Cr, Mo, V, W and Ti.
67
What is homogenisation in Al alloys?
1. Solution is solidified first.
2. The alloy is heated to a temperature below the eutectic temperature and held for a long time.
This removes the laminar structure that was caused due to the eutectic phase.
68
What is the need for the precipitation sequence in Al2Cu?
When the solution has been quenched, there is a large driving force (because the undercooling is large). But there is very little thermal energy available for diffusion. And all the interfaces between Al2Cu and alpha would be incoherent so the nucleation of Al2Cu is difficult.
69
Precipitation sequence in Al-Cu
1. Initial supersaturated solution of Cu in alpha.
2. Cu atoms cluster to form Guinier-Preston Zones. They are disc shaped, the disc faces are fully coherent with alpha and the disc edges have coherency strain.
3. GP zones act as nucleation sites for unstable beta''. It is a tetragonal crystal. Disc faces are fully coherent, disc edges have coherency strain.
4. Another unstable phase beta' forms, nucleating at dislocations and grows at the expense of beta''. Disc faces are fully coherent, but disc edges are incoherent.
5. Eventually, beta-AlCu2 forms. It is a crystal with very different lattice parameters to alpha, and all interfaces are incoherent. Therefore, beta-AlCu2 grows are rounded particles.
70
When is the peak strength reached during the precipitation sequence?
At beta''. This gives numerous, closely space particles throughout the alpha phase.
71
What to optimise for the upper wing?
Compressive strength
Stiffness.
72
What to optimise for the lower wing?
Tensile strength
Fatigue resistance.
73
Al alloy selection for wings of subsonic aircraft?
7xxx - upper.
2xxx - lower.
74
What to optimise for the fuselage?
- Axial tensile stress.
- Circumferential tensile stress.
- Fatigue critical.
75
What is the temperature limit for Al alloys?
Mach 1.8
76
Advantages of using Magnesium?
- Light structural metal.
- Precipitation hardenable
- Can have a good creep resistance.
77
Disadvantages of Magnesium?
- Low melting point (compared to Ti or Ni)
- Low stiffness
- HCP crystal structure (Dislocation slip only on (0001) planes at Room temp)
- Corrosion properties are okay.
78
Specific stiffness for struts?
Maximise E/rho.
79
Specific stiffness for beams?
Maximise E^0.5/rho
80
Specific stiffness for panels?
Maximise E^1/3 / rho.
81
Mg alloys : Mg-Al-Zn alloys
Solution heat treatment at 400degrees.
Quench
SSSS -> to Mg17Al12 directly.
82
Mg alloys : Mg - Y - Nd - Zr
Zr addition:
- Zr promotes nucleation of Mg grains of a mcuh smaller grain size. Good for grain boundary strengthening and retarding crack growth.
Creep resistance:
- Numerous, small B/ B' precipitates are distributed evenly - which obstructs dislocation motion at elevated T.
- Ppts at grain boundaries, relatively stable at 250 - 300.
Inhibits grain boundary sliding at elevated T.
83
Advantages of WE alloys
- Best properties of all Mg alloys.
- Service temperature of up to 250-300 degrees.
- Superior strength to Al alloys at 250 - 300 degrees.
84
Disadvantages of WE alloys
- Expensive.
- Yttrium is difficult to handle in molten Mg alloys.
85
Advantages of Titanium
Excellent corrosion resistance.
High specific strength.
Good compatibility with CFRP.
Excellent properties at elevated temperatures.
86
Disadvantages of Titanium
Expensive.
Low wear resistance
Difficult to form.
Pick up of oxygen and nitrogen above 500 degrees.
87
Explain the near alpha alloys in titanium
alpha forms between beta upon cooling.
giving it good creep properties and poor fatigure resistance. This is because diffusion is faster in beta-Ti, so a high fraction of alpha-Ti is good for creep resistance.
Or, a basket weave structure of alpha next to beta is formed.
There are OK creep properties, but it has really goo fatigue resistance. The entanglement slows down the crack movement and increases the crack deflection.
In both, you can use solid solution or grain boundary strengthening.
Used as the blades in a gas turbine engine, operating at high temperatures.
88
Explain alpha-beta alloys in Titanium
Good balance of creep and fatigue properties.
Used in fan blades, - good strength and superplastic formable.
89
Explain near beta alloys in Titanium
Has very good strength at low T.
Used in landing gear, helicopter rotor hub.
90
Explain beta alloys in Titanium
Very good strength at low T.
Highest strength Ti allows.
Poor properties at higher T.
91
Explain the low cycle fatigue
1. Plastic deformation roughens the surface in a small number of cycles.
2. Slip planes cause extrusions and intrusions at the surface.
3. The cracks then initiate along the slip paths.
4. The cracks then change their direction to grow perpendicular to the tensile axis.
92
Explain high cycle fatigue
There is some local plasticity in regions where a notch or scratch or change in section concentrate the stress. Cracks eventually form here.
93
Explain fatigue fracture surfaces
1. Initiation region: surface.
2. Propagation: beach marks.
3. Fast fracture - when the crack length is greater than the af.
94
Predicting fatigue lifetime - Fail safe design
Comparing endurance limit or fatigue limit to the delta Kth value (below this value, the crack will not advance any further)
95
Predicting fatigue lifetime - Limited lifetime design
With pre-existing cracks, use the Paris law.
It is also useful for determining necessary inspection intervals.
96
How to design for creep - design against dislocation creep
- Choose a materials with a high melting point (decrease T/Tm)
- Maximise obstacles that are stable at the chosen T.
- Choose an alloy where the majority phase has a high lattice resistance. (covalent bonding for example)
97
How to design for creep - design against diffusion creep
- Choose a material with a high melting point (decrease T/Tm)
- Maximise the grain size to give long diffusion distances and little gb diffusion. (aka single crystals)
- Choose an alloy with precipitates at gb to impede gb sliding.
98
Advantages of single crystals?
No grain boundaries.
Superior creep
Superior thermal fatigue resistance.
99
Creep damage and failure
- Voids can form at the grain boundaries lying perpendicular to the stress.
- Atoms must diffuse to these gb for diffusion to occur, but creep can occur by the growth of voids.
- Voids decrease the load-bearing area- thus increasing the stress.
100
Alloy requirements
- Creep resistance.
- Resistance to high temperature oxidation.
- Toughness.
- Thermal fatigue resistance
- Thermal stability
- Low density.
101
Define Creep
Slow, continuous deformation with time at elevated temperature.
102
Explain the 4 types of diffusion mechanisms
1. Interstitial - needs to overcome the energy barrier.
2. Substitutional - needs to overcome the energy barrier and also a vacancy.
3. Grain-boundary diffusion - Useful when the grain size is very small.
4. Dislocation-core diffusion - Can act as fast diffusion wires. If there is a high dislocation density, this can be good.
103
Explain Creep Mechanisms - Dislocation Creep
Slide : Slides on slip planes if the stress is high enough for the dislocations to overcome the lattice resistance.
Glide : Whenever the dislocation meets a ppt, it meets it a glide force. There will be a reaction force, with some component acting perpendicular to the glide direction. The dislocation can't just glide upwards, but it can move up if atoms at the bottom of the half-plane can diffuse away. Bc it requires diffusion - it is temperature dependent. Higher the stress, the higher the climb force - more dislocation glides - higher strain rate.
104
Explain diffusion creep
At lower temperature - diffusion occurs across the grain boundaries - Coble Creep.
At higher temperatures - diffusion occurs across the bulk of the material (Nebarro-Herring Creep).
To ensure continuity within the material, the grain arrange themselves by grain boundary sliding.
105
Factors affecting diffusion creep
Strain rate is proportional to D and the stress applied. And proportional to 1/d^2 - the larger the diameter, the more the atoms have to diffuse.
106
Which materials will oxidise?
If their energy change is negative, they will oxidise and are called oxide stable.
107
When does linear corrosion loss happen
If the oxide is volatile.
108
When does linear corrosion growth happen
When the oxide breaks up.
If the volume of the oxide is less than the metal, the oxide splits open from the metal.
If the volume of the oxide is greater than the metal, the oxide shrinks from the metal.
109
How to improve the oxidation resistance?
1. Coating with alumnium.
2. Heating in a furnace. (forms either AlNi and the rest oxidises to form a Al2O3 layer)
110
Disadvantages of oxide films
- Brittle and can crack - especially when T changes.
- Oxide layers act as initiation sites for thermal fatigue cracks - spreading into the alloy.
111
Define amorphous solids
They are made up of randomly orientated atoms, ions or molecules. They don't have a defined pattern or lattice structure.
112
Define hardness
A measure of how easily dislocations can move through a material.
113
Dislocation motion in covalent ceramics
Dislocation motion is very difficult because the interatomic bonds must be broke and then reformed.
114
Dislocation motion in ionic ceramics
Dislocation motion is easier in some planes but harder on others.
115
Define thermal shock resistance
The maximum temperature change a material can withstand upon quenching. (Usually in Kelvin)
116
How does chain length distribution affect number average molar mass, or weight average molar mass or z-average molar mass?
Mn - The number of entanglements per chain is proportional to the number of chain ends.
Mw - melt viscosity - higher viscosity due to more entanglements.
Mz - melt elasticity - highest molecular weight fraction determines the melt elasticity.
117
Define isotactic chain regularity?
All the side groups are on the same side.
118
Define sindiotactic chain regularity?
Alternate in a regular manner
119
Define atactic chain regularity
The side groups are in random positions.
120
Why does a rubber become stiffer once heated?
When you stretch the polymer, you have reduced its entropy (less disorder because you have correctly oriented the chains). So, when we heat it up, the system will go back and get stiffer.
121
What material processes are used in the rubber region?
Vaccuum forming
Bottle blowing.
122
What material process are used in the liquid form?
Extrusion
Injection mouldering
Rotor moulding.
123
Polymers - Rubber Compounding
Literally to create rubber.
It's created into thin sheet strips by using a two-roll mill shear mixing.
They are then allowed to cool down.
124
Polymers - Extrusion
Plastic pellets are put into the feeder.
These are heat up and a turning screw pushes it out by spinning.
Produces pipes, tubing, window railings, plastic films, sheets, wire insulation.
125
Polymers - Use of twin screw compounding
Plasticizing (PVC)
Dispersing of fillers and fibres (composites)
Alloying and blending (polymer blends)
Colouring and additives
126
Polymers - Explain die swell
At high shear rates, the non-Newtonian behaviour is good.
Die swell happens because of elastic spring back.
Controlled by Mz.
127
Polymers - Explain melt fracture
When the flow rate in increased a lot, the extrudate can break. Usually happens when stretching and cooling occur too fast and cause micro tears. Occurs due to too low temperature of the melt, high molecular weight or poor die design.
128
Polymers - Co-extrusion
Extrusion of multiple layers at the same time.
2 or more extruders are used to deliver the output into an extrusion head. The layer thickness is controlled by relative speeds and sizes of the extruders delivering the material.
129
Polymers - Sheet extrusion
Die is used and cooled through a set of cooling rolls. They cool and also determine sheet thickness.
130
Polymers - Blow film extrusion
Extrusion and then air is blown into the output.
Guide rolls and pinch rolls are used.
131
Polymers - Melt Fibre spinning
Hot melt is extruded through a series of small holes in a plate (spinnerets) into air or
water (or another fluid). The fibres are wound up at high speed on a rotating drum (godet)
132
Polymers - Solution Fibre Spinning
A diluted polymer solution is spun from a spinnernet. Ultra high molecular weight polyethylene is dissolved in a solvent. Gives a very low enthanglement density, extremely high strength and gives it a nearly 100% crystalline structure and a high orientation. But rather hard to process.
133
Polymers - Aramid fibre spinning
They have aromatic chains. after you spin it, they become very orientated.
134
Polymers - Injection moulding
The screw here both spins and also pushes back.
Injects material into a mould.
135
Polymers - Rotational moulding
involves a heated hollow mould which is filled with a charge or shot weight of
material. It is then slowly rotated (usually around two perpendicular axes) causing the softened material
to disperse and stick to the walls of the mould.
136
Polymers - Vacuum forming (or thermoforming)
Use a heater to place the sheet of material over the object. Then use a vacuum to suck all the air out.
137
Pros of composites
Weight reduction (high specific stiffness & strength)
Design flexibility & integrated parts – ability to create
novel shapes tailored to integrated part function.
Environmentally friendly? – low energy consumption in manufacture.
Safety – crush structures.
Low maintenance cost (corrosion resistance)
138
Cons of composites
Costs of materials and processing still high
Absence of mass production technology for highperformance composites
Recycling of composites is very difficult
Lack of knowledge in designing with anisotropic materials
Uncertainties in predicting failure and life-time
139
Types of reinforcements
Particulate
Flake
Fibre reinforced
Laminated
140
Types of composites
Uniaxial
Angle-ply
Cross-ply
Random-in-the-plane
Random in 3d.
141
Why does the random in 3d composite have the least mechanical property?
It has random directions. And also has discontinuities because the fibres are shorter, which means less strength.
142
Polyethylene
Cheap, easy to mould and fabricate.
Plastic bottles, tupperware.
143
PTFE
Non stick cooking utensils, Rain gear.
Expensive
Water repellents
Stable.
144
PS - Polystyrene
Uses : pens, foams, cups, CD cases.
In its simplest form, it is brittle.
145
PVC - Polyvinylchloride
Rigid, brittle, cheap.
CDs, swimming fins, pipes.
146
PMMA
Transparent - acrylic.
Most resembles glass in transparency and durability.
147
PC - Polycarbonate
Used in:
- safety goggles, fire alarm buttons, helmets.
148
PET
Thermoplastic polyester
Food packaging, bottles etc.
149
PEEK
High performance thermoplastic.
High stiffness, strength, resistance to heat.
Expensive.
Nuts, bolts etc.
150
Epoxy
Resistant to heat and chemical attack.
Adhesives
Surface coatings, filled with other materials.
Expensive and brittle.
151
Unsaturated polyesters
Thermosets.
Poor corrosion resistance.
Cheaper than epoxies.
152
Natural rubber
Elastomer.
Low hysteresis and high tear resistance.
Tyres, tubes, shoes etc.
153
Composite Architecture
Unidirectional prepreg/tapes.
Non crimp fabrics/ uniweave.
Non-woven mat.
Woven - plain weave - good stability, but difficult to drape.
Twill weave - Good drape, good stability too. Smoother and slightly higher mechanical properties.
Satin weave - Very flat and have best degree of drape.
Braided.
Through thickness reinforcement - stitching, tufting and z-pinning.
154
Composites - Hand lay up
Simplest way:
Resins are impregnated by hand into fibres which are in the form of woven, knitted, stitched or bonded
fabrics. This is usually accomplished by rollers or brushes, with an increasing use of nip-roller type
impregnators for forcing resin into the fabrics by means of rotating rollers and a bath of resin
155
Composites - Hand lay up - Advantages
- Cheap
- Used for many years.
- Wide choice of suppliers and materials.
- High fibre contents and longer fibres than spray lay-up.
156
Composites - Hand lay up - Disadvantages
- Dependent on the skills of the laminators.
- Health and safety factors.
157
Composites - Hand lay up - Typical applications
Standard wind turbine blade.
Production boats.
Architectural mouldings.
158
Composites - Spray up
Fibre (glass roving) is chopped in a hand-held gun and fed into a spray of catalysed polyester resin directed at the mould. The deposited materials are left to cure under standard atmospheric conditions
159
Composites - Spray up - Advantages
- Used for many years.
- Low cost.
- Low cost tools.
160
Composites - Spray up - Disadvantages
- Laminates tend to be very resin-rich - so heavy.
- Only short fibres which limits the properties.
- Resins need to be low in viscosity to be sprayable.
- Problems with legislation.
161
Composites - Spray up - Applications
Simple enclosures, caravan bodies, bathtubs, shower trays, small dinghies.
162
Composites - Filament winding
The rotationing mandrel is a oval sectioned component, such as pipes or tanks. Fibre tows are passed through a resin bath and then wound onto the mandrel in many different orientations.
163
Composites - Filament winding - Advantages
- Fast, and economic.
- Resin content can be controlled.
- Fibre cost is minimised bc no secondary processes to convert fibre into fabrics is needed.
- Good properties - straight fibres can be applied in complex patterns to match the applied loads.
164
Composites - Filament winding - Disadvantages
* Process limited to convex shaped components.
* Fibre cannot easily be laid along the length of a
component.
* Mandrel costs for large components can be
high.
* External surface of the component is
unmoulded, and therefore cosmetically unattractive.
* Low viscosity resins needed and hence lower
mechanical properties with health and safety
165
Composites - Filament winding - Applications
Chemical storage tanks and
pipelines, gas cylinders, fire-fighters' breathing tanks.
166
Composites - Pultrusion
Fibres into a resin bath, and then a heated die. The die completes the impregnation of the fibre, and cures into the final shape. Cured profile is then cute to length.
167
Composites - Pultrusion - Advantages
* This can be a very fast automated method.
* Resin content can be controlled.
* Fibre cost minimised since it is taken from a creel.
* Structural properties of laminates can be very good since profiles can have very straight fibres and high
fibre contents.
* Resin impregnation area can be enclosed thus limiting volatile emissions.
168
Composites - Pultrusion - Disadvantages
* Limited to constant or near constant cross-section components
* Heated die costs can be high.
169
Composites - Pultrusion - Typical applications
Beams and girders used in roof structures,
bridges, ladders, frameworks.
170
Composites - Resin Transfer moulding
Fabrics are laid up as a dry stack of materials. These fabrics are sometimes pre-pressed to the mould shape (preforms), and held together by a binder. A second mould tool is then clamped over the first, and resin is injected into the cavity. Vacuum can also be applied to the mould cavity to assist resin in being drawn into the fabrics. This is known as Vacuum Assisted Resin Transfer Moulding (VARTM). Once the fabric is wet out, the resin inlets are closed and the laminate is allowed to cure. Both injection and cure can take place at either ambient or elevated temperature.
171
Composites - Resin Transfer moulding - Advantages
* High fibre volume laminates can be
obtained with very low void contents.
* Good health and safety, and
environmental control due to closed
mould process.
* Possible labour reductions.
* Both sides of the component have
a (smooth) moulded surface.
172
Composites - Resin Transfer moulding - Disadvantages
* Matched tooling is expensive, and
heavy in order to withstand
pressures.
* Generally limited to smaller
components.
* Problems to inject highly viscous
toughened resins
173
Composites - Resin Transfer moulding - Typical Applications
Small complex aircraft and automotive
components, train seats.
174
Composites - Vacuum infusion
Same as resin transfer moulding but with a vacuum used as well.
Uses:
Semi-production small yachts, train
and truck body panels.
175
Composites - Bladder Moulding
1. Preform is inserted in.
2. Draping occurs where air pushes the material to the mould. from the inside.
3. Component is removed.
4. Component is injected (by RTM), heated and cured.
176
Composites - Bladder Moulding - typical applications
Tennis rackets and bicycles, pipes,
177
Composites - Autoclave Moulding - typical Applications
Aircraft structural
components (e.g. wings and tail sections), F1
racing cars, sporting goods such as
professional tennis racquets and skis.
178
What is the heat treatment for Nickel - Aluminium
1. Solutionise in Ni to dissolve the Al into solution.
2. Quench to create SSSS.
3. Age at 800 degrees C for 8 hours to control the precipitation of Ni3Al throughout Ni grains.
179
Which is better - to have coherent or incoherent interfaces between the alpha and the precipitates?
We want incoherent interfaces. Incoherent interfaces have a greater strain, and they produce a greater resistance on dislocation motion.
180
What is the interface between Ni3Al and Ni?
It is a coherent interface, both phases are cubic and have a similar lattice parameter.
181
Explain why Ni-Ni3Al is good despite having coherent interfaces?
Dislocations find it hard to move because the Ni3Al is ordered. The passage of a dislocation disrupts this order, the dislocation must pass through in pairs, one which disrupts and the other restores, leading to strengthening.
Also, it is thermally stable, so it minimises coarsening.
182
Explain some Ni superalloy compositions
1. Solid Solution Strengtheners - Co,W, Cr.
2. Precipitate formers - Al, Ti, Mo, Ta, C.
3. Oxidation protection - Cr.
183
Designing for creep : Turbines blades .
1. Equiaxed - Having ppts at grain boundaries.
2. Use columnar ppts - maximise the grain boundaries to give long diffusion distances and little gb diffusion.
3. Single crystals have no gb, no voids.
184
Nickel based Turbine blade cooling
The temperatures in the turbine are often greater than the nickel melting temperature.
Cooling air from the compressor is fed through channels. A film of cool air then envelopes the blade, allowing the blade to cool down.
185
Nickel based Turbine blade - Thermal barrier coating
Add cooling.
But also add a coating of ceramic and a bond coat (zirconium oxide), giving:
- protection from oxidation.
- thermal shielding (oxides are poor conductors of heat, so they provide insulation).
186
Composites - Metal Matrix + Ceramic Fibres - Foil diffusion boding (solid state)
Put a film down, and then insert the fibres inside. Then add a new film.
Layer them all up and then put inside a vacuum. Heat to fabrication temperature and apply pressure. The matrix flows around the fibres.
187
Composites - Metal Matrix + Ceramic Fibres - Foil diffusion boding (spray deposition)
Spraying a liquid metal against the fibres.
188
Composites - Metal Matrix + Ceramic Fibres - Foil diffusion boding (plasma spray deposition)
A layer of fibres is laid up on a rotating mandrel, the metal is deposited on the fibres by plasma spraying, a second layer of fibres is put on, and the operations are repeated until the desired thickness and the number of layers is attained.
189
Explain the difference between a thermosetting and thermoplastic polymers
Thermoplastic polymers can melt under heat whilst curing, but thermoset polymers tend to hold their shape.
190
For thermoplastic polymers, explain 5 factors that promote brittle fracture
- Reduction in temperature.
- Increase in strain rate.
- Presence of a sharp notch.
- Increase specimen thickness
- Modifications of the polymer structure.
191
Does deformation by drawing increase or decrease the tensile modulus?
Increases it.
Upon drawing, the structure becomes a highly oriented structure, so there is a higher degree of interchain secondary bonding.
192
Common Environmental factors
Long-term environmental exposure, moisture.
Cost?
Temperature (-50 - high altitude cruise) to 100 degrees (taxi on runway)
Moisture ranges - dry to hail and lightning.
Impact threats - runway debris, birdstrike, maintenance, collision with ground vehicles.
Impact resistance.
Fatigue resistance.
Fire resistance.
Electrical conductivity - or electrical insulation?
Thermal conductivity?
193
Functions of the matrix phase
Bind the fibres together.
Distribute the stress between the fibres.
Protect the surface of the fibres from damage.
Separate the fibres and inhibit crack propagation.
Lateral support to the fibres against buckling.
194
Desired characteristics of the matrix and fibre phases
Matrix: Ductile, soft, bonds well to the fibres, low density, and cheap.
Fibre: Stiff and strong, good chemical and thermal compatibility with the matrix.
195
Explain why alloying with aluminium can improve the oxidation performance of a Ni Super-alloy?
- Al has a higher affinity for oxygen so, Al2O3 is formed on the surface.
- The parabolic growth law is still x^2 = kt, but k is much smaller. Diffusion through the Al oxide is slower, because the motion of electron is very slow.
196
CFRP Advantages
- Low weight
- Corrosion resistant.
- Formability/ shaping.
- Paintability.
- Aesthetics.
197
CFRP Disadvantages
- Rapid manufacture is difficult.
- High material cost.
- Electrical/ thermal conductivity could be an issue.
- Immature design knowledge.
- Joining dissimilar materials as issue.
198
Amorphous against crystalline?
Most materials - especially thermoset and thermoplastics are amorphous.
199
Define solid solution.
A solid state solution of one or more solutes in a solvent. Such a mixture is considered a solution (and not a compound) when the crystal structure of the solvent remains unchanged by the addition of solutions.
200
Loading types
Torsion
Aerodynamics Loads - in bending
Fatigue
Impact loads.
Penetration resistance.
201
Under what service condition can fatigue cause failure in steel?
They can fail at stresses below the tensile strength of the material if subjected to alternating stress of strain.
202
Explain beach marks
They can be observed. Each beach mark represents a period of time over which the crack growth occurred.
203
Describe the 3 stages of fatigue failure shown
Stage 1 - No observable fatigue crack growth. The cracks behave as non-propagating cracks.
Stage 2 - Paris law. There is a linear relationship between da/dN and log K.
Stage 3 - Accelerated crack growth.
204
What are the 4 grain refinement mechanisms
Precipitation strengthening - adding precipitates to decrease dislocation motion.
Solid solution - Adding atoms of other elements to the crystalline structure. This adds a stress and strain field - impeding dislocation motion.
Grain refinement - Adding more grain boundaries means the dislocations don't travel in a continuous slip plane - hinder dislocation motion.
Work hardening - Strengthening a metal by plastic deformation, because it increases the hardness.
205
Why do ceramics crack at an extreme temperature change?
There is a rapid change in volume due to the thermal expansion/ contraction between different layers of a solid. This can create a stress which is greater than the tensile strength, meaning the ceramic breaks.
206
Explain the modulus of rupture in ceramics
Basically, tension tests can't be done on ceramics - there are many problems, but especially with the clamping of the system.
If you do somehow manage to go through and do a tensile test, then the tensile stress you receive is quite low.
If you test it in bending instead, this gives a modulus of rupture of much greater values.
207
In ceramics - what can you do or change about the ceramic that would allow a greater tensile strength?
Increase the value of m - it will reduce the size of defects and distribution.
Choose a materials that is less defect sensitive.
Change the dimensions so it's smaller, because this has smaller cracks.
Or add a better surface finish.
