Magnetism Flashcards
force on a charged particle due to a magnetic field
F = q (v x B)
q: charge
v: velocity
B: magnetic field
x: cross product
Lorentz force equation
F = q[ E + (v x B) ]
q: charge
E: E-field
B: magnetic field
v: velocity
x: cross product
prove that magnetic fields never do any work on charged particles
W = ∫ F⋅dl
F = q (v x B) and dl = vdt
hence W = ∫q (v x B) ⋅ v dt
v x B is perpendicular to v.
∴(v x B) ⋅ v = 0
so W = 0
force on a current carrying wire equation
F = L (I x B)
L: wire length in B-field
B: magnetic field
I: current
x: cross product
Biot-Savart law equation
dB = µ₀/4π * (𝑰dl x 1/r² r̂)
dB: magnetic field
𝑰: Current
r: distance from the wire
dl: direction of current flow
r̂: radial direction
Gauss’s law for magnetic fields
since magnetic field lines form closed loops, the flux entering an leaving any Gaussian surface will be the same
hence: ∮B ⋅ dA = 0
Ampere’s law (aka B-field circulation)
∮B⋅dl =µ₀*I = µ₀∫ j⋅dA
dl: length element of a closed loop (Amperian loop)
I: the current enclosed within the loop
j: current density vector
dA: area element of the area bound by the curve dl
important solenoid facts
B inside is uniform
B outside is 0
magnetic moment equation
µ = AI
µ: magnetic moment
A: loop area
I: current
this is for a loop of current
equations about a magnetic dipole inside a uniform magnetic field
T =µ x B
T: torque (tau symbol)
µ: magnetic moment
B: field strength of the uniform field
U = -µ⋅B
U: potential energy
µ: magnetic moment
B: field strength of the uniform field