Logical Laws and Valid Inferences Flashcards
Law of Non-Contradiction
No sentence is both true and false, or for no A, A and ¬A. In symbols: |= ¬(A ∧ ¬A).
The Law of Non-Contradiction specifies what is wrong with contradictions: they cannot be true. The Law of Non-Contradiction entails that no sentence is both, true and false.
Law of Excluded Middle.
(tertium non datur) For every proposition A, either A or ¬A. In
symbols: |= A ∨ ¬A.
There is no third option.
Law of Double Negation
The double negation of A, ¬¬A, is logically equivalent to A: ¬¬A≡A.
Law of Identity
Every sentence is logically equivalent to itself, or for any sentence A, A is logically equivalent to A, or |= A ≡ A.
De Morgan’s Laws
(i) A negated disjunction is logically equivalent to the conjunction of its negated disjuncts. In symbols: |= ¬(A ∨ B) ≡ (¬A ∧ ¬B).
(ii) A negated conjunction is logically equivalent to the disjunction of its negated conjuncts. In symbols: |= ¬(A ∧ B) ≡ (¬A ∨ ¬B).
Modus (ponendo) ponens
+example
A is true and so is if A then B. Therefore: B is true. In symbols: A,A → B |= B
Example. Tormenting the cat is wrong. If tormenting the cat is wrong, then getting your little brother to torment the cat is wrong. Therefore: getting your little brother to torment the cat is wrong.
Modus (tollendo) tollens. (+ example)
If A then B is true, but B is false. Therefore: A is false. In symbols: A → B, ¬B|= ¬A
Example. If Mary did it, then she was in Berlin at the time of the murder. Mary was not in Berlin at the time of the murder. Therefore: Mary didn’t do it.
Rejecting a conditional. (+ example)
A is true, but B is false. Therefore: if A then B is false. In symbols: A, ¬B |= ¬(A → B).
Example. The sample contained traces of arsenic. Fred did not die. Therefore: it is not true that if the sample contained traces of arsenic, then Fred died.
Conditional proof. (+example)
If there is a valid argument of the conclusion B from A (together with premises Γ), then there is a valid argument for the conclusion A → B (from premises Γ).
Example: If John wins the lottery, then Mary is happy. If Mary is happy, then John is happy. John wins the lottery. Therefore (by two applications of modus ponens): John is happy. Therefore the following argument is valid: If John wins the lottery, then Mary is happy. If Mary is happy, then John is happy. Therefore: If John wins the lottery, then John is happy.
Transitivity of Implication. (+example)
If A then B, and if B then C. Therefore: if A thenC. Insymbols: A→B,B→C|= A→C.
Example. If John wins the lottery, then Mary is happy. If Mary if happy, then John is happy. Therefore: if John wins the lottery, then John is happy.
Modus tollendo ponens or Disjunctive Syllogism. (+example)
A or B is true, but A is false. Therefore: B is true. In symbols: A ∨ B, ¬A|= B.
Example. Alice drinks the potion or Alice eats the cake. Alice does not eat the cake. Therefore: Alice drinks the potion.
Alternation. (+example)
A is true. Therefore: A or B is true. B is true. Therefore: A
or B is true In symbols: A|= A ∨ B and B|= A ∨ B
Example. I’m having tea. Therefore: I’m having either tea or I’m having
coffee.
Proof by Cases. (+example)
Whatever follows from each disjunct, follows from their disjunction: A or B is true, and so are if A then C and if B then C: therefore C is true. More generally, if there is a valid argument of C from A (together with premises Γ) and a valid argument for C from B (together with premises Σ), then there is a valid argument for C from A ∨ B (together with premises Γ and Σ). In symbols: If Γ,A|=C and Σ,B |=C, then Γ, Σ, A ∨ B|= C.
Example. We lost the map. We have no idea where we are and where to go to. We can either search for the map or we continue without it. If we continue without the map, we’ll never find our way back. If we look for the map, we’ll lose time and resources, so we won’t concentrate. If we don’t concentrate, we’ll never find our way back. So either way, we’ll never find our way back.
Simplification (+example)
A and B is true. Therefore A is true (and so is B). In symbols: A∧B |=A and A∧B|= B.
Example. John Lee had one Bourbon, one Scotch and one beer. There- fore: John Lee had one beer.
Adjunction
A and B are both true. Therefore A and B is true. In symbols: A, B|= A ∧ B.