Logarithmic Flashcards
Derive
ex
ex
Analyze the following function
y = ln (x2-1)
Include: domain, intercepts, increase and decrease interval, P.O.I and curvature, and sketch.
Domain: x > 1, x<-1
Intercepts: no y, x = √2; x = -√2
Write the 2 equations that describes e.
x~>0lim (1+x)1/x
x~>∞lim (1+1/n)n
Rewrite in term of e
n~>∞lim (1+1/(n+100))n
e
Rewrite as p = x - 100
Rewrite in term of e:
limx~>0(1+x/5)1/x
e1/5
Substitute x as 5t, and then rewrite as e.
Derive
y = x2ex2
2xex2(1+x2)
Derive:
y = (ex- e-x)/(ex+ e-x)
(e2x- 1)/(e2x+ 1)
Discuss
y = ln(x2- 1)
Domain: x∈(-∞,-1)U(1,∞)
Intercepts: no y-intercepts, roots: ±√2
Assymptote: VASM at ± 1
Increase: x∈(-∞,-1)
Decrease: x∈(1,∞)
Concave down: x∈(-∞,-1)U(1,∞)
Derive
y = esin(x2)
2xesin(x2)cos(x2)
Evaluate
limx~>0+ln(x)
-∞
Evaluate
limx~>0-ln(x)
D.N.E
Find value of K that creates real solution:
e2x + ln K = 0
0 < K < e9/4
Treat it like a quadratic equation and employs the determinant equation.
Discuss:
y = ln(cos x)
Domain: (4n-1)π/2 < x < (4n+1)π/2; where n is real
Intercepts: y-intercepts: 0, roots: 2nπ
Assymptote: about the y-axis, period 2π
Increase: x∈((4n-1)π/2,2nπ)
Decrease: x∈(2nπ, (4n+1)π/2)
Max: (0, 2nπ)
Concave down: x∈((4n-1)π/2,(4n+1)π/2)
Examine only 1 intervals, and do it.
Derive
y = xx
xx(lnx+1)
Find dy/dx
y = (5x+1)6(5x3)1/2(2x+27)1/3/[(2x3+9)e-2x+2(x+1)1/5]
y[(30/5x-6)+(15x2/10x3+81)+(2/6x+81)-(6x2/2x3+9)+(1/5x+5)]