LeetCode

Question 1

capitalize only the first letter of the string

Answer 1

capitalize()

Question 2

Operator checks if the item is in the container

Answer 2

in

Question 3

removes the key-value pair from dictionary and returns the key-value pair

Answer 3

popitem()

Question 4

retrieve values of the dictionary

Answer 4

values()

Question 5

retrieve keys of the dictionary

Answer 5

keys()

Question 6

returns the stored key-value pairs in a dictionary

Answer 6

items()

Question 7

returns a new set with items present in one set but not in another

Answer 7

difference()

Question 8

returns a new set with only common items

Answer 8

intersection()

Question 9

returns a new set with items from both sets

Answer 9

union()

Question 10

removes an item from the set

Answer 10

remove()

Question 11

inserts a new item to a set

Answer 11

add()

Question 12

counts the amount of a certain item in a list

Answer 12

count()

Question 13

deletes a specific item from a list

Answer 13

remove()

Question 14

adds new item to a list

Answer 14

append()

Question 15

Dictionary

Answer 15

a collection of key-value pairs where keys are unique and immutable; key has a unique correspondence to its value, but not the other way around

Question 16

Set

Answer 16

an unordered collection with no duplicate items (numbers, strings, etc.); unordered means there is no indexing

Question 17

Tuple

Answer 17

an ordered immutable sequence of items (numbers, strings, etc.); immutable means we cannot modify the items in the tuple

Question 18

List

Answer 18

an ordered mutable sequence of items (ex: numbers, strings, etc.)

Question 19

Iterate over several iterables in parallel, producing tuples with an item from each one.

Answer 19

zip(*iterables, strict=False)
strict: if set to True, checks that the lengths of iterables are identical

ex:

for item in zip([1, 2, 3], [‘sugar’, ‘spice’, ‘everything nice’]):
… print(item)
…
(1, ‘sugar’)
(2, ‘spice’)
(3, ‘everything nice’)

Question 20

return True if any element of the iterable is true. If the iterable is empty, return False.

Answer 20

any(iterable)

Question 21

returns the absolute value of a number

Answer 21

abs(x)
x can be an integer, float

Question 22

returns length (number of items) of an object

Answer 22

len()

Question 23

removes the item at the given index from the list and returns the removed item

Answer 23

pop(index=-1)

Question 24

returns True if all items in an iterable are true, otherwise it returns False

Answer 24

all(iterable)

Question 25

computes the reverse of a given sequence object and returns it in the form of a list

Answer 25

reversed(sequence_object)

Question 26

returns an object that contains a counter as a key for each value within an object

Answer 26

enumerate(iterable, start=0)

Question 27

string concatenation operator

Answer 27

+

Question 28

capitalize only the first letter of the string

Answer 28

capitalize()

Question 29

transform all characters in a string into lower case

Answer 29

lower()

Question 30

transform all characters in a string into upper case

Answer 30

upper()

Question 31

replace substring where it substitutes all occurrences of a specific character sequence in a string with another sequence

Answer 31

replace(string to replace, string to replace with)

Question 32

returns the index of the first instance of a character in the string

Answer 32

index()

Question 33

join a list of strings together with a defined delimiter

Answer 33

join()
ex: ‘ ‘.join(list)

Question 34

split a string into a list of strings with a defined delimiter

Answer 34

split()
ex: string.split(‘ ‘)

Question 35

when working data frames columns with a string type, the syntax to access the string methods for the column is

Answer 35

df[‘column’].str.<string></string>

Question 36

condition used such that we can apply a method on every other index in an iterable

Answer 36

if index%2 == 0