Lectures 1-8 Flashcards
gases at room temperature
HEFONC & noble gases
1 L
1 dm^3
1 Pa
1 N/m^2
1 bar
1 x 10^5 Pa
1 kPa
1000 Pa
equal volumes of gas at constant T and p contain
equal number of particles
volumes of all gases extrapolate to zero at
0 K
R
8.314 J K^-1 mol^-1
V is proportional to
1/p
V is proportional to
T
V is proportional to
n
density
pM/RT
to find partial pressure
n(a) x (RT/V)
to find total pressure
(n(a) + n(b) + n(c)) x (RT/V)
to find mole fraction
n(a)/n(total)
to find mole fraction
p(a)/p(total)
to find partial pressure
x(a)/p(total)
kinetic molecular theory assumptions
negligible particle size, elastic collisions, no interaction
average kinetic energy of particles
3/2kT where k is R/N(A)
RMS speeds related to
temperature and molar mass
all gases at same temperature have same
kinetic energy, but not same average speed
effusion
gas escapes through a hole
diffusion
different gases mix
diffusion occurs from regions of
high to low concentration
rate of effusion is inversely proportional to
square root of molar mass
rate of effusion
number of molecules passing through a hole per second
particles attract each other
p decreases
particles repel each other
p increases
wavelength
distance from maximum to maximum
frequency
how many cycles a second
wavelength and frequency are
anti-proportional
wave number
inverse of wavelength; number of wavelengths per unit distance
light intensity is related to
amplitude
light colour is related to
wavelength
constructive interference
when two waves in phase interfere
destructive interference
when two waves out of phase interfere (amplitude = 0)
wavelength and energy content are
anti-proportional
same temperature
same kinetic energy
to calculate RMS, molar mass must be in
kg/mol
RMS
(3RT/M)^1/2
rate of effusion of gas 1/rate of effusion of gas 2
SQUARE ROOT OF: molar mass gas 2/molar mass gas 1
p1V1/T1 =
p2V2/T2
frequency =
c/wavelength
photons
energy packets of light
energy of a single photon (E)
hv
absorption spectroscopy
input light, analyse what was absorbed
in absorption spectroscopy, the sample transitions from a
lower to higher energy state
emission spectroscopy
input heat, analyse what was emitted
in emission spectroscopy, sample transitions from
higher to lower energy state
deltaE
E2-E1
predicting positions of lines in emission spectra
RH(1/n^2final - 1/n^2initial)
energy of emitted light
-hv or -hRydberg equation
quantum numbers
n(initial) and n(final)
emission quantum numbers
n(final) < n(initial) and deltaE is negative
absorption quantum numbers
n(final) > n(initial) and deltaE is positive
the Bohr model does not work because
emission spectra of many-electron atoms cannot be described, does not explain intensity of spectral lines, does not take into account particles as waves
photoelectric effect
electromagnetic radiation hits a metal surface and electrons are emitted
electrons are only ejected if light reaches
critical/threshold frequency
intensity increase causes
higher number of electrons to be ejected
photons must overcome both
binding energy and threshold frequency
kinetic energy of electron
hv(photon) - Ebind
kinetic energy of electron
hv(photon) - h x threshold frequency
Hz
1/s
de Broglie wavelength of matter
wavelength = h/p = h/mv
wavelength and mass are
anti-proportional
fast-moving particles have
shorter wavelengths
slow-moving particles have
longer wavelengths