Lecture 9: Nucleosynthesis of Light Elements Flashcards

1
Q

When we talk about nucleosynthesis we mean

A

the formation of the light elements

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

the light elements

A

hydrogen
deuterium
helium-3
helium-4
lithium-7

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Heavier elements can be formed through

A

nuclear fusion in the centres of stars

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

the abundances of the light elements reflect the

A

primordial state of the universe
and the conditions that existed at that time.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

The theory of primordial nucleosynthesis is able to successfully predict

A

the abundances over about 9 orders of magnitude

this makes it one of the strongest pieces of evidence for the Hot Big Bang Theory

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

ratio of neutrons to protons - 4 important facts

A
  1. protons lighter than neutrons
  2. free neutrons decay into protons
  3. neutrons bound into stable isotopes of the light elements do not decay
  4. neutrinos decouple from the rest of the cosmic plasma at T=10^10K
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

which are lighter, protons or neutrons?

A

protons (938.3MeV to 939.6MeV)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

free neutrons decay into protons with a half life of

A

610s

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

Consider the period before nuclei form but late enough that protons and neutrons are non-relativistic.
This is equivalent to

A

kBT «mpc^2
or
T«10^13K

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Consider the period before nuclei form but late enough that protons and neutrons
are non-relativistic.
the number density N will be

A

in a maxwell boltzmann distribution

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Nn/Np is approx 1 when

A

kBT&raquo_space; (mn-mp)c^2

ie the typical thermal energy of photons significantly exceeds the rest-mass
energy of the proton-neutron mass difference

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

The relevant reactions involve neutrinos, mediated by the weak force:

A

n + ve <-> p + e-

n + e+ <-> p + anti ve

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

when kBT is approx 0.8MeV, neutrinos

A

decouple and the cosmic neutrino background is formed

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

what does neutrinos decoupling and the cosmic neutrino background forming mean?

A

the reactions can no longer occur and neutrons freeze out, though free neutrons can still decay

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

R=

A

Nn/Np

approx exp(-1.3MeV/0.8MeV)
approx 1/5

(numerator - mass difference, denominator - neutrino decoupling temp)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

If it were not possible to ‘lock away’ neutrons in stable nuclei eventually

A

all of the free neutrons would have decayed into protons.

We’d have a universe consisting only of hydrogen: we would not exist.

17
Q

why do we not have a universe consisting only of hydrogen

A

deuterium can be formed via

p+n –> d + gamma

18
Q

deuterium

A

one proton + one neutron

19
Q

deuterium formation: High-energy photons in the tail of the distribution cause

A

photo-disintegration
of the deuterium d until the temperature of the universe drops to about T=8x10^8K at t=300s

20
Q

deuterium formation: By the point of photo-disintegration, the ‘frozen-in’ value of R = Rf will have reduced because

A

of the decay of the free neutrons

model as a radioactive process

21
Q

R at freeze out

A

R=Rf=0.2 at freeze out

valid at t=300s

22
Q

light element abundances in the early universe - assume

A

that all the free neutrons end up as helium-4 nuclei.

23
Q

if all free neutrons end up as helium-4 nuceli, NHe=

24
Q

Y4 is the

A

mass abundance ratio
=mass of He4/total mass

25
Q

for R300=0.135, Y4=

A

0.24

ie helium-4 makes up around 1/4 of the universe

26
Q

As well as helium-4 we can predict the abundances of

A

deuterium (10−4) helium-3 (10−5),
and lithium-7 (10−10) as a function of the density of baryons.

27
Q

There is an agreement between theory and observed abundances over about

A

nine orders of
magnitude

28
Q

caveat of success of 9 order of magnitude

A

the baryon density be no
more than 4% or 5% of the critical density (for h = 0.7).

ie lots of other stuff (dark matter etc)

29
Q

the predicted abundances depend on

A

a number of different parameters

30
Q

if we tweak the neutron lifetime, we can see how

A

Y4 changes

31
Q

baryon to photon ratio, n also influences

A

the predicted abundances

32
Q

what other parameters affect the predicted abundances

A
  1. neutron half-life
  2. number of neutrino species
  3. baryon to photon ratio
  4. non-degeneracy of neutrinos
33
Q

neutron half-life: increasing the nurton half life…

A

increases Y4 because fewer neutrons will have decayed by t=300s which means more neutrons are available to be captured in deuterium nuclei to then form helium

neutrons freeze out earlier so there are even more neutrons available to form helium

34
Q

number of neutrino species - the standard model predicts 3 neutrino species Nv, increease Nv…

A

increases Y4 because it increases the relativistic energy density at nucleosynthesis. This means a higher value of H at that time so the neutron freeze out occurs at higher temperature and a higher R

35
Q

baryon to photon ratio, increasing n causes

A

an increase in Y4 because it means there are less high-energy photons in the tail of the distribution, resulting in a less severe deuterium bottleneck, thus the build-up of He-4 begins earlier and more of it will form

we expect a decrease in deuterium with an increase in n

36
Q

non degeneracy of neutrinos: neutrinos are fermions and obey the Pauli Exclusion Principle. At low temps, neutrinos…

A

fill up states to Fermi level, anti-neutrinos do the same but to different Fermi level. If there are many more neutrinos than anti-neutrinos a chemical potential results from the difference in Fermi levels

so n to p reactions occur more often than p to n so Y4 decreases

37
Q

comparison with CMBR constraints - there is a discrepancy between planck and observations called

A

the cosmological lithium problem

due to difficulty in making accurate observations of primordial Li-7