Lecture 7: Retrieval from STS and Levels of processing Flashcards
What is the sternberg scanning task?
- Quest: how much time does it take to make one mental comparison in STM?
- Task: memory searching (scanning). The question simply was does the probe item match one of the numbers that was shown in the memory set?
- On half the items it matched and on the other half it didn’t match.
- DV= how quickly the person could answer yes or no to the probe item (pressed a button)
- Size of memory set varied, whether probe matched varied through a series of trials. At the end, they took the average of the trials overall and the average for the varying sizes of memory set
What is the assumption that guides how retrieval from STS is modelled?
- time between a probe stimulus and a response is occupied by a series of discrete stages (Probe digit –> encoding stage –> memory comparison stage –> response stage)
What is the encoding stage?
probe item gets encoded into stm, which takes time.
What is the memory comparison stage?
The next stage is does this item match something in our meomry set? Memory comparison stage. Comparing probe item to the numbers that were encoded during the memory set
What is the response output stage?
Finally you give a response or an output based on the comparison
What are the three hypotheses regarding search in STS?
1) Parallel
2) Serial exhaustive
3) Serial self terminating
What is the parallel hypothesis?
- According to this item, you can compare the probe item to each of the items in the memory set all at once (encoding stage and comparison stage happen simultaneously). Thus, it would not matter how many items are in the memory set because it happens all at once.
- Efficient
- if this hypothesis is correct, the results would be a straight line
What is the serial exhaustive hypothesis?
- Comparing each item to the probe, one after the other. You go through each item in the memory set to search for the probe item, even once you find the probe item in the memory set you continue to the end of the list (hence the word exhaustive - don’t terminate when you find something).
- Not very efficient
- Response time will always be dependent on the set size (not on yes vs. no)
- Shorter reaction time when there are less items.
- Upwards slope
What is the serial self terminating hypothesis?
- No trials = no termination because there is no match, on the yes trials once you get a match you terminate.
- No responses, the bigger the set the longer it takes you to get through everything because you always have to go through the entire set
- The yes responses will be faster when the memory set is small, and slower when the set size is large. Sometimes you terminate early, but sometimes you terminate late. The average will be somewhere in the middle.
- This difference becomes even more pronounced when the probe is early in the memory set (rather than later or last).
- When there is only one item, the yes and no trials are the same speed
- Self terminating assumption predicts that the no trials should be slower as the items increase, and the yes trials will get slower but not as much. This is called an interaction (memory set size had a different effect on yes as compared to no trials)
Which of the hypotheses was supported by the result
- Found a serial exhaustive scanning mechanism
- Could be because maybe its so fast to make a comparison that it would take more energy to stop it than to just go through an exhaustive list
- Turns out it is pretty fast
- 397.2 ms is where the line interacts with the y axis, this is the speed it takes If you weren’t doing a comparison, everything but the comparison.
- Once you add in one mental comparison you add in time to make the comparison happen which is 37.9 ms (time it takes to make a single mental comparison. For every item that’s added in the reaction increases by a unit of 37.9 ms
How does changing the nature of the probe effect the task?
- Same task (adding in the quality of the probe stimulus)
- Clear vs. degraded probe digit (i.e., quality of the probe stimulus)
- How does our system deal with a degraded stimulus?
- Encoding stage or memory comparison stage?
- First option: encoding stage, sees degraded stimulus and decides not to pass it on before it fixes it up. Fixing it takes time. Does it matter how many items are in the memory set? Does the extra time interact with the number of items in the memory set?
- No it will take longer initially (during the encoding stage, i.e., longer than 397.2) but it will still take the same amount of time to compare the items in the comparison stage (37.9 ms). The slope remains the same, it just moves higher.
- Option 2: the encoding stage just passes on the degraded stimulus without fixing it. This adds time onto the comparison stage (12.1 is just an example). For example each mental comparison is now taking 50 seconds (i.e., 37.9 + 12.1).
- This is an interaction now between the number of items and stimulus quality. They have their impact in the same stage of processing (the comparison stage)
What does the encoding stage locus predict?
Encoding stage locus predicts additivity
What does the memory stage locus predict?
Memory stage locus predicts interaction
What were the actual results of the degraded/clear probe task?
The actual results were additive (which indicates that the fixing of the degraded stimulus happened in the encoding stage)
What are the advantages of additive factors logic?
Simple logic used to isolate stages in a serial process.