Lecture 5 - projectile motion Flashcards

1
Q

What is projectile

A

Any object in free fall and affected only by gravity and air resistance

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2
Q

Trajectory is

A

Flight path of projectile (the arch)(predicable motion)

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3
Q

Release is when

A

Objects begins projectile motion

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4
Q

Apex is

A

The highest point in trajectory

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5
Q

Projectiles have…?

A

Velocity

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6
Q

Horizontal component for projectile from when we release it until it stops will be changing or constant?

A

Constant

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7
Q

The vertical component will be constant or changing

A

Change

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8
Q

What affects the vertical displacement/apex/ depends on

A

Vertical velocity

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9
Q

What depends on projection angle

A

Magnitude of projectile motion

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10
Q

The x component and y component of projectile motion are dependent or independent?

A

Independent of each other (separate)

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11
Q

Airborne motion is always these 3 rules

A
  1. Parabolic path of CoM
  2. Constant horizontal velocity
  3. Constant vertical acceleration
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12
Q

Gravity influences Vx or Vy

A

Vy

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13
Q

As the object is moving up, Vy is

A

Decreasing

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14
Q

When the object is at apex the Vy is going to be

A

Zero

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15
Q

When object is moving down, the Vy is going to be

A

Increasing

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16
Q

When object is going up the gravitational force is going to be

A

-9.81 m/s^2

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17
Q

When object is going down the gravitational force is going to be

A

9.81 m.s^2

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18
Q

Trajectory of centre of mass (CoM) of projectile is always

A

Parabolic regardless of motion of body seamen’s

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19
Q

Trajectory of centre of mass (CoM) of projectile is always

A

Parabolic regardless of motion of body segments

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20
Q

What are the 3 different factors that can change projectile motion and how far the object moves

A
  • projectile height of release (relative height)
  • projection angle (angle of release)
  • projectile velocity (velocity of release)
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21
Q

Anything that is being thrown at a higher place, the object will have. A longer or shorter time in the air

A

Longer flight time

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22
Q

If we have a constant projectile velocity and a constant angle but we alter projectile height, what will happen?

A

Increase flight time = increase horizontal displacement

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23
Q

Horizontal displacement is dependent on how long

A

You spend in the air (flight time) ex. At longer period of time but same velocity will result in a longer distance

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24
Q

If release height is the same as landing height will foes it mean? Add pic

A

Time to apex= time to land

Vy release = Vy landing

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25
Q

Release height > landing height ad pic

A

Time of apex < time to land

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26
Q

Release height < landing height add pic

A

Time to apex > time to land

Vy release > Vy landing

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27
Q

If the projection angle is 90 (shot straight up) all the velocity would be on

A

Vy and Vx=0

28
Q

Projection angle influences shape of ______

A

Projectile’s trajectory

29
Q

If projection angle is between 0 and 90 it will create

A

Parabolic trajectory will have every things listed for projectile motion

30
Q

If projection angle = 0, if the release height is> landing height will have

A

1/2 parabola trajectory and Vy initial = 0

31
Q

If you had the same weight of bricks and feather which will drop first? Why?

A

Both fall the same time because air resistance is zero, gravity will affect the same way since they are falling from the same height

32
Q

If you want to maximize your vertical displacement you want to make your angle as?

A

Steep as you can closer to 90 degree

33
Q

Maximize horizontal displacement you want to make your angle depend on

A

Optimal angle (height of release)

34
Q

For projection height

Release height = landing height —> optimal angle is

Release heighT>landing height —> optimal angle is

Release heighT < landing height —> optimal angle is

A

45

<45

> 45

35
Q

Why is 45 the optimal angle

A

By having the same release height and landing height and the angle is 45 it will maximize flight time and horizontal velocity

36
Q

Projectile velocity determines

A

Magnitude of vertical and horizontal displacement

37
Q

What is the most important factor in changing projectile motion

A

Projectile velocity

38
Q

A potato cannon has a fixed angle of 50 degree relative to the ground. How can we alter the firing distance (displacement over time) if the angle is fixed?

A

Cannot move or change height,

We can increase the projectile velocity or

39
Q

A cannon with a fixed to the ground fires with a velocity of 1000m/s. How do we alter this cannon’s firing distance?

A

We have a fixed height and velocity

Alter the projection angle to optimal angle

40
Q

Example needing maximize vertical displacement?

A

High jump, pole vault (steep projection angle)

41
Q

Maximize horizontal displacement?

A

Long jump, triple jump (small projection angle)

42
Q

Example for when release ht=landing ht —> optimal projection = 45

A

Kick.a soccer ball for max horizontal displacement

43
Q

Example for when release ht>landing ht —> optimal projection < 45

A

Throwing a baseball for max horizontal displacement

44
Q

Example for when release ht optimal projection > 45

A

Chip into an elevated green (golf)

45
Q

A cannon fires with a fixed angle of 50 and fixed velocity of 1000m/s. How do we alter the cannon’s firing distance?

A

Alter projectile height and increase it = increase horizontal displacement

46
Q

Changing projectile height (increasing it) will only affect

A

Time of object going down

47
Q

Total time can help figure out your

A

Horizontal displacement

48
Q

Time total is

A

Time up + time down

49
Q

Flight time is influenced by

A

Vy intital and projectile height

50
Q

Horizontal displacement is influenced by

A

Vx time in air

51
Q

Vertical displacement is influenced by

A

Vy initial, projectile height

52
Q

Trajectory is influenced by

A

Initial velocity (magnitude), projection angle and projectile height

53
Q

When analyzing horizontal components the Acceleration is 0

A
  1. Vf=Vi+at —> vf=vi
  2. D=Vit +1/2 a^2 -> d=Vit
  3. Vf^2 = Vi^2 +2ad —> Vf2=Vi2
54
Q

Anazlying when dropping a ball from a given height its a=-9.81 m/s^2

A

Vi=0

  1. Vf=Vi+at —> vf=at
  2. D=Vit +1/2 a^2 -> d=1/2at^2
  3. Vf^2 = Vi^2 +2ad —> Vf2=2ad
55
Q

Analyzing vertical components when at apex

A
  1. Vf=Vi+at —> 0=Vi+at

3. Vf^2 = Vi^2 +2ad —> 0=.Vi2+2ad

56
Q

Time up Vy=Vf is

A

Zero

57
Q

When time down, Vy=Vi is

A

Zero

58
Q

A ball is thrown in the air with an initial velocity of 30 m/s and a horizontal velocity of 5 m/s. What was the maximal height reached by the ball? Vertical displacement

A

Add pic

59
Q

A football is kicked with the initial horizontal velocity of 18 m/s and a flight time of 2s. How far will the ball travel?

A

Add pic

60
Q

A ball is kicked with the initial horizontal velocity of 35 m/s and a vertical velocity of 10 m/s. how far will the ball travel

A

Add pic

61
Q

A soccer player kicks a ball. The ball leaves the foot at a 23° angle relative to the horizontal, with a velocity of 58 m/s. The ball is in the air for 0.83 seconds.
A) What is the ball’s vertical and horizontal velocity immediately after release?
B) What is the ball’s max horizontal displacement?
C) What is the ball’s vertical velocity at max vertical displacement?
D) What is the ball’s max vertical displacement?
E) What is the ball’s horizontal velocity just prior to contact time?
F) What is the ball’s vertical velocity just prior to contact time?

A

Add pic

62
Q

You hit a golf ball. The ball leaves the ground at
25 m/s at an angle of 60° from the ground.
A) What is the maximum height the ball reaches?
B) How much time does it spend in the air?
C) How far does the ball travel?

A

Add pic

63
Q

You hit onto an elevated green, which has a rise of 3m.
You hit the ball at 45 m/s at an angle of 55°. A) How high does the ball travel?
B) How much time does it spend in the air?
C) How far does the ball travel?

A

Add pic

64
Q

When the optimal angle is > 45 what happens

A

Release height < landing height

65
Q

Optimal angle is < 45

A

Release height > landing height

66
Q

When optimal angle is 45 what happens

A

Release height = landing height