Lecture 5 Flashcards
What are the kinetics of Step polymerization?
Two cases:
Case one: ignoring the elimination of product
Case two: without ignoring the condensation product
Check written notes pt.1
Analysis:
Equations 1 and 2 have been derived assuming that the reverse reaction (i.e. depolymerisation) is negligible. This is satisfactory for many polyadditions, but for reversible polycondensation, it requires the elimination product to be removed continuously as it is formed. The equations have been verified experimentally using step polymerizations that satisfy this requirement, as is shown by the polyesterification data plotted in Figure 3.2 (shown in digital notes). These results further substantiate the validity of the principle of equal reactivity of functional groups.
Ring formation
A complication not yet considered is the intramolecular reaction of terminal functional groups on the same molecule. This results in the formation of cyclic molecules (i.e. rings), e.g. in the preparation of a polyester.
What does ring formation depend on
The ease of ring formation depends strongly upon the number of atoms linked together in the ring. For example, 5-, 6- and, to a lesser extent, 7-membered rings are stable and often form in preference to linear polymer. For the self-condensation of ω-hydroxy carboxylic acids HO—(CH2)i—CO2H when i=3 only the monomeric lactone is produced. When i=4, some polymer is produced in addition to the corresponding monomeric lactone, and
when i=5, the product is a mixture of polymer with some of the monomeric lactone.
Normally, 3- and 4-membered rings and 8- to 11-membered rings are unstable due to bond-angle strain and steric repulsions between atoms crowded into the centre of the ring, respectively, and usually are not formed. Whilst 12-membered and larger rings are more stable and can form, their probability of formation decreases as the ring size increases. This is because the probability of the two ends of a single
chain meeting decreases as their separation (i.e. the chain length) increases. Thus large rings rarely form.
What is the problem of ring formation and molar mass distribution?
Ring formation disturbs the form of the molar mass distribution and reduces the ultimate molar mass. However, since linear polymerization is a bimolecular process and ring formation is a unimolecular process, it is possible to greatly promote the former process relative to the latter by using high monomer concentrations. This is why many step polymerizations are performed in bulk (i.e. using only monomer(s) plus catalysts in the absence of a solvent).
What are the limitations that arise when using solvents in step polymerisations
Although step polymerizations can be carried out in a solvent that dissolves the monomers and the polymer to be produced, finding suitable solvents can be difficult because the polymers often are
semi-crystalline and of low solubility. The isolation of the polymer from the solvent also can prove difficult. Hence, most step polymerizations are performed by reacting liquid monomers together in the absence of a solvent.
Linear step polymerization process
The preceding Flash cards highlight the many constraints upon the formation of high molar mass polymers by linear step polymerization.
Special polymerization systems often have to be developed to overcome these constraints and are exemplified below by systems developed for the preparation of polyesters and polyamides.
The process of ester esterification
Ester interchange (or transesterification) reactions commonly are employed in the production of polyesters, the most important example being the preparation of poly(ethylene terephthalate). The
direct polyesterification reaction of terephthalic acid with ethylene glycol indicated is complicated by the high melting point of terephthalic acid (in fact it sublimes at 300 °C before melting) and its low solubility. Thus poly(ethylene terephthalate) is prepared in a two-stage process.
The first stage involves the formation of bis(2-hydroxyethyl)terephthalate either by
i) the reaction of dimethylterephthalate with an excess of ethylene glycol (i.e. via ester interchange): Shown in digital notes
ii) direct esterification of terephthalic acid with an excess of ethylene glycol (more common nowadays): Shown in digital notes.
The methanol or water produced during these first-stage reactions is removed as it is formed.
On completion of the first stage, the reaction temperature is raised to about 277 °C so that the excess ethylene glycol and the ethylene glycol produced by further ester interchange reactions can be removed, and so that the polymer is formed above its melting temperature (265 °C): Shown in written notes
The process of preparing aliphatic polyamides from diamines and diacids?
The preferred method for preparing aliphatic polyamides from diamines and diacids is melt polymerization of the corresponding nylon salt. For example, in the preparation of nylon 6.6, hexamethylene diamine and adipic acid are first reacted together at low temperature to form hexamethylene diammonium adipate (nylon 6.6 salt) which then is purified by recrystallization. The salt is heated gradually up to about 277 °C to effect melt polymerization and maintained at this temperature whilst removing the water produced as steam.
This is shown in the digital notes!
A major advantage of melt polymerization by salt dehydration is that the use of pure salt guarantees exact 1:1 stoichiometry.
The process for preparation of polyesters and polyamides?
A convenient method for preparation of polyesters and polyamides in the laboratory is the reaction of diacid chlorides with diols and diamines, respectively (i.e. Schotten–Baumann reactions).
These reactions proceed rapidly at low temperatures and often are performed as interfacial polymerizations in which the two reactants are dissolved separately in immiscible solvents which are then
brought into contact.
The best-known example of this is the ‘nylon rope trick’ where a continuous film of nylon is drawn from the interface as illustrated in Figure 3.3 (shown in digital notes). For example, the preparation of nylon 6.10 would proceed by the following reaction (Shown in digital notes).
The reaction takes place at the organic solvent side of the interface and, because it usually is diffusion-controlled, there is no need for strict control of stoichiometry
The other process
The schematics he showed in the lecture slides for the processes already described are shown below.
What is gel point? (network polymers)
The inclusion of a monomer with a functionality greater than two has a dramatic effect on the structure and molar mass of the polymer formed. In the early stages of such reactions, the polymer has a branched structure and, consequently, increases in molar mass much more rapidly with the extent of reaction than for a linear step polymerization. As the reaction proceeds, further branching
reactions lead to hyper-branching which lead ultimately to the formation of complex network structures which have properties. that are quite different from those of the corresponding linear polymer.
The point at which the first network molecule is formed is known as the gel point because it is manifested by gelation, that is, an abrupt change of the reacting mixture from a viscous liquid to a solid gel which shows no tendency to flow.
Network polymerization
Network polymers produced by step polymerizations were amongst the first types of synthetic polymers to be commercialized and often are termed resins. The polymers are completely intractable and so at the stage when the network chains are generated, the polymerizations must be carried out
within a mould to produce the required artefact.
What are formaldeyde-based resins?
Formaldehyde-based resins were the first network polymers prepared by step polymerization to be commercialized. They are prepared in two stages. The first involves the formation of a prepolymer of low molar mass which may either be a liquid or a solid. In the second stage,
the prepolymer is forced to flow under pressure to fill a heated mould in which further reaction takes place to yield a highly crosslinked, rigid polymer in the shape of the mould. Since formaldehyde is difunctional, in order to form a network polymer the co-reactants must have a
functionality f greater than two; those most commonly employed are phenol (f = 3) to form phenol-formaldehyde, urea (f = 4) to form urea-formaldehyde and melamine (f = 6) to form melamine-formaldehyde
Phenol-formaldehyde?
The hydroxyl group in phenol activates the benzene ring towards substitution in the 2-, 4- and 6-positions. Upon reaction of phenol with formaldehyde, methylol substituent groups are formed (this is shwon in digital notes).
Further reaction leads principally to the formation of methylene bridges but also to dimethylene ether links (this is shown digtal notes)
What are two types of phenol-formaldehyde?
- resoles
- Novolaks