Lecture 3: Genetic Variation in Populations Flashcards

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1
Q

What is p and how is is calculated?

A

frequency of normal allele in a population

p = number of normal alleles/total number of alleles

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2
Q

What is q and how is it calculated?

A

frequency of disease allele in a population

q = number of disease alleles/total number of alleles

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3
Q

What is the Hardy-Weinberg equation?

A

p^2 + 2pq + q^2 = 1

where p^2 = AA
2pq = Aa
q^2 = aa

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4
Q

What are the assumptions made when using the Hardy-Weinberg equation?

A
  1. mating is random
  2. population is stable (allele frequencies remain constant across generations)
  3. no inbreeding
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5
Q

What is the carrier frequency of an autosomal recessive disease?

A

2pq (frequency Aa heterozygote)

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6
Q

How would you calculate the probability of you having a child with autosomal recessive disease when both you and unrelated partner have no history of the disease?

A

(2pq)^2 x 0.25

0.25 = the probability of two carriers (Aa) having an affected child (aa)

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7
Q

How would you calculate the probability of you having a child with autosomal recessive disease when both you have a sibling with the disease but you are unaffected and your partner has no history of the disease?

A

Sibling with the disease = both parents must be carriers
but since you are unaffected (not aa) so your chance of being a carrier (Aa) is 2/3 and chance of not being carrier (AA) is 1/3.

Therefore
2pq (carrier frequency for partner) x 2/3 (carrier frequency for you) x 0.25 (for chance of having affected child)
2pq x 2/3 x 0.25

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8
Q

What is the coefficient of relationship (R) and how is it calculated?

A

The proportion of alleles shared by two people by having common ancestors (identity by descent - identical at same locus by inheriting same allele from ancestor)

Calculated by: (1/2)^n
1/2 = chance of inheriting an allele from a parent
n = number of links through common ancestor between two individualsW

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9
Q

What is the coefficient of inbreeding (F) and how is it calculated?

A

The proportion of loci at which an individual is expected to be homozygous due to inbreeding

calculated by: 1/2R (1/2 coefficient of relationship)

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10
Q

If the chance of one person being a carrier is 2pq, what is the chance that their first cousin is also a carrier at that locus?

A

1/8 (the coefficient of relationship, R, for cousins)

cousin - parent - grandparent - parent - cousin = 4 paths = 1/2^4 = 1/8

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11
Q

What is relative risk and how is it calculated?

A

Relative risk is the risk of having an affected child for a particular couple (E.g. first cousin marriage) compared to the risk of having an affected child for unrelated parents in general population.

Calculated by:
risk of particular couple having affected child/risk of general population having an affected child

E.g. is risk of affected child for first cousin marriage is 1 in 744 and the risk of affected child in general population is 1 in 2160, then 2160/744 = RR ~ 3

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12
Q

True or false: relative risk of having an affected individual is lower for inbreeding couples?

A

False: RR is higher (although the actual risk may still be quite low, it is just much higher compared to general population)

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13
Q

What does the persistence of a mutation within a population depend on?

A
  • type of mutation (dominant, recessive, X-linked)
  • selection (positive, neutral, negative effect of mutation)
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14
Q

How does persistence of deleterious/harmful mutations in a population vary for:
1. Dominant lethal
2. Dominant affecting fertility
3. Late onset dominant
4. X-linked lethal
5. Autosomal recessive

A
  1. Dominant lethal: persist for single generation
  2. Dominant affecting fertility: persist for one to a few generations
  3. Late onset dominant: persist for many generations
  4. X-linked recessive: 1/3 lost per generation
  5. Autosomal recessive: persists for many generations but mostly eventually lost
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15
Q

What balances the persistence of deleterious mutations?

A

de novo mutations ??????????????????????????????????

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16
Q

How does heterozygote advantage allow persistence of mutant allele in a population?
give an example

A

Heterozygote may confer a selective advantage that increases survival in those individuals

E.g. for Sickle cell anaemia autosomal recessive disorder, aa = SCA, AA = susceptible to malaria, but Aa heterozygotes do not have SCA and are resistant to malaria so increased survival of heterozygotes that pass on the mutant allele.

17
Q

What is the founder effect?

A

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18
Q

What is heritability?

A

how much of the observed variation in a trait is caused by genetics

19
Q

What is the theoretical heritability of highly penetrant single gene disorders?

A

should have a heritability of 0 (i.e. no variation) - but some variability comes from modifier genes and environmental influences

20
Q

Multifactorial traits?

A

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21
Q

True or false: complex genetic diseases are inherited in a mendelian fashion?

A

False, not single gene
but they do tend to run in families

22
Q

How is heritability estimated traditionally?

A

plot trait for offsprings and parents and determine the slope of the line to see correlation.
Slope of 1 = 100% of variation due to genetic

23
Q

What does a slope of 0.84 mean in terms of heritability?

A

84% of variation in the trait can be accounted for by genetic variation (84% heritability)

24
Q

What does an odds ratio of 1 mean?

A

there is no effect of a given factor on the development of a disease

25
Q

Other than slope of line, how else can heritability be estimated (more commonly)?

A

Heritability is commonly estimated using risk to 1st degree relative of an affected individual compared to the rest of the population (λs) - relative risk

26
Q

What is λs?

A

the fold greater chance of having a disease if sibling is affected (Relative risk)

27
Q

PAGE 9-11 watch recording when added to moodle!

A

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