Lecture 2 Flashcards

1
Q

In a weak acid equilibrium, describe what the “weak acid” and “conjugate base” serve as. Also describe what the dissociation constant tells you about a particular weak acid equilibrium.

A

The weak acid (HA) serves as the proton donor

The conjugate base (A-) serves as the proton acceptor

The dissociation constant (Ka) describes how easily the weak acid will dissociate into the conjugate base and H+ ions

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2
Q

In a weak base equilibrium, describe what the “weak base” and “conjugate acid” serve as. Also describe what the dissociation constant tells you about a particular weak base equilibrium.

A

The weak base (B) serves as the proton acceptor

The conjugate acid (BH+) serves as the proton donor

The dissociation constant (Ka) describes how easily the weak base will accept protons from water
(still called the dissociation constant for bases even though acids are what actually dissociates, and bases do not)

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3
Q

Compare the Ka, pKa, and energy of interaction between strong and weak acids

A

Ka: Larger in strong acids

pKa: smaller in strong acids (opposite of Ka value)

Energy of Interaction: smaller in Strong acids (it takes less energy input to make strong acids dissociate compared to weak acids)

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4
Q

Compare the Ka, pKa, and energy of interaction between strong and weak bases

A

Ka: Larger in strong bases

pKa: smaller in strong bases (opposite of Ka value)

Energy of Interaction: larger in Strong bases (larger means more negative, and the more negative the energy of interaction is for a base, the more likely water is to give the base a proton)

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5
Q

Describe why the pH scale is 0 to 14

A

This is bc the equilibrium constant of water is 10^-14 M

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6
Q

What is the physiological pH of the human body?

A

7.4

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7
Q

Define the term Buffer (give both examples of a buffer)

A

Buffers are weak acids or bases that can stabilize pH

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8
Q

Describe what it means in terms of the protonation/deprotonation of the molecules of a solution when the following conditions occur

pH < pKa

pH > pKa

pH = pKa

A

pH < pKa: most of the molecules are protonated (since the [HA] > [A-])

pH > pKa: most of the molecules are deprotonated (since the [HA] < [A-])

pH = pKa: the molecules are just as likely to be protonated as they are to be deprotonated

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9
Q

Define Isoelectric point

A

the pH where all of the molecules of a given species in solution have an OVERALL charge of 0

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10
Q

Describe what it means in terms of the charge of a molecule when the following conditions occur

pH < pI

pH > pI

pH = pI

A

pH < pI: the molecule has a positive charge

pH > pI: the molecule has a negative charge

pH = pI: the molecule has no net charge

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11
Q

What do you need to use in order to find the isoelectric point of a molecule?

A

the +1 and -1 pKa’s

(any pKa values beyond these is meaningless to the calculation of the isoelectric point bc we want to find when the species has a net charge of zero)

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12
Q

explain what isoelectric focusing is and how it works

A

isoelectric focusing is a form of electrophoresis where you establish a pH gradient into the gel, and then add proteins and supply charge

the proteins will migrate the to pH that represents their pI (isoelectric point) bc they will have no charge there and therefor will not migrate due to the current running through the gel

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13
Q

beginning with pH > pI of a protein, then moving to pH = pI, and finally pH < pI, explain the levels of protein solubility will occur throughout this range and why

A

at pH > pI: at high pH, proteins are deprotonated and VERY soluble because of their negative charges repelling one another

at pH = pI: at it’s isoelectric point pH, protein aggregates because it has no net charge, which allows the + and - regions of the molecule to interact with one another

at pH < pI: at low pH proteins are protonated and soluble because of repulsions due to their positive charge

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14
Q

State the first law of thermodynamics

A

Energy is neither created or destroyed in a closed system

everything will always have some kinetic (motion, performing work) and potential energy (chemical energy is potential energy in chemical bonds)

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15
Q

True or False:

a cell can gain or lose energy and it will not violate the first law of thermodynamics. explain.

A

True

a cell is not a closed system, so its all good

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16
Q

State the 2nd law of thermodynamics

A

Disorder is increasing

17
Q

State what the variables represent in the Gibbs Free Energy Equation represent

DeltaG = DeltaH - TDeltaS

A

DeltaG: change in available/useable energy (Gibbs free energy)

DeltaH: change in total energy (Enthalpy) in the system

T: Temperature in Kelvin (degrees Celsius +273)

DeltaS: change in disorder (Entropy)

18
Q

All of the “Delta” values in the Gibbs Free Energy Equation are “state functions”. What does this mean?

A

it means that we dont care about the pathway or number of value changes that occur during a reaction.

We only care about the difference between the initial value to the final value

19
Q

What State what is occurring when DeltaH is positive, negative, and zero

A

negative DeltaH means energy is released from the system (Exergonic)

positive DeltaH means energy is added to the system (Endergonic)

no DeltaH value means energy is not added or released (Closed system ; 1st law)

20
Q

Compare exergonic and endergonic reactions in terms of energy needed, is if favorable, and is it spontaneous.

A

Exergonic:
does not need energy added (spontaneous)
Favorable reaction

Endergonic:
requires energy input (Driven reaction (not spont.))
unfavorable reaction

21
Q

State the Equation for the Gibb’s Free Energy Equation

A

DeltaG = DeltaH - TDeltaS