Lecture 2 & 3: Water, pH & buffers Flashcards

1
Q

Reversible Ionization

A

Results from nucleophilic attack by oxygen on a proton of an adjacent water molecule
H2O H+ + OH-

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2
Q

Keq: Equilibrium Constant

A
Ratio of [product] to [reactant]; water: ([H+][OH-])/[H2O]
Keq=1 : [product] = [reactant]
      >1: [product] > [reactant]
      <1: [product] < [reactant]
Keq of water: 1.8 x10^-16
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3
Q

Kw: Ion product of water

A

Kw = 1x 10^-14 = [H+][OH-]

If [H+] increases, then [OH-] decreases

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4
Q

pH: -log [H+]

A

Acid: release/donates protons
Base: accept protons

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5
Q

Acid-Base Disorders (Pathological)

A

Metabolic acidosis
Increase production of acid: lactic acidosis (overproduction of lactic acid), ketoacidosis (overproduction of ketone bodies), complications of drugs or other exposures
Loss of bicarbonate: diarrhea, altered kidney function

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6
Q

Small Changes in pH as a Signaling Mechanism

A

pH increase of 0.2 to 0.3 promotes cell proliferation, migration, assembly of actin filaments
High intracellular pH = cancer
Low intracellular pH = several neurodegenerative diseases

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7
Q

Strong acid vs. Weak Acid

A

Strong acid ionizes completely; one way arrow

Weak acid does not ionize completely; equilibrium arrow

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8
Q

Ka: A constant for any given acid

A

HA A- + H+

Ka= [H+][A-] / [HA]
If Ka is large, indicates a strong acid
Small pKa indicates a strong acid

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9
Q

Henderson-Hasselbalch Equation: pH & pKa relationship

A

pH = pKa + log [A-]/[HA]
Applies to weak acids & bases
Bases want to keep their protons

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10
Q

Henderson-Hasselbalch

A

When [HA]=[A-], the acid is 50% dissociated & undissociated; pH=pKa it is the pI (inflection point); point of max buffering capacity

Points on curve: different ratios of dissociated to undissociated weak acid

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11
Q

How is pKa useful?

Example: Aspirin

A

Aspirin is a weak acid with a pKa of 3.5
Absorbed through the cells lining the stomach (pH:1.5) & SI (pH:6)
Absorption requires passage through the pm; rate of absorption determined by the polarity of the molecule: charged and highly polar passes slowly & neutral hydrophobic ones pass rapidly
Aspirin more absorbed in stomach b/c more acidic & H+ in environment

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12
Q

Normal vs. Cancer Cells

A

Normal:
Intracellular pH: ~7.2
Extracellular pH: ~7.4

Cancer:
Intracellular pH: >/= 7.4
Extracellular pH: ~6.7-7.1

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13
Q

Selective Advantages for Cancer Cells

A
Favors:
  Proliferation
  Avoid apoptosis
  Migration and invasion
  Avoid immune detection
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14
Q

Consequences of Reverse pH Gradient in Cancer Cells

Example: Doxorubicin

A

pKa = 8.2; has an ionizable primary amine
Will have a higher percentage of the drug at pH<8.2 in the ionized form
Normal cells will take up a greater percentage of doxorubicin : more acidic in a normal cell than cancer cell (7.2<7.4)

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15
Q

How does the body compensate for the generation of acid due to metabolic activity?

A

Buffers

NOTE: Metabolism results in 13-22 moles of acid produced/day. If dissolved in water, pH would be <1.

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16
Q

pH Homestasis

A

Blood pH must be maintained within a narrow range (7.36-7.44)
Intracellular pH: 7.1 (range 6.9-7.4)

17
Q

Buffers

A

A mixture of an undissociated acid & its conjugate base (ex. Acetic acid and acetate ion)

Consequence: It causes solution to resist changes in pH when either H+ or OH- is added

18
Q

Buffer Systems of Physiological Importance

A

Phosphate Buffer: H2PO4- HPO4 2- + H+ (pKa: 7.2)
Intracellular fluid

Carbonic Acid/Bicarbonate: CO2(dissolved) +H2O HCO3- + H+
Carbonic acid/bicarbonate system works b/c of high [CO2] dissolved in body fluids & equilibrium b/w dissolved CO2 & CO2 in lungs

Proteins (amino acids)

19
Q

How Do Buffers Function?

A

Simple: Combines with H+ or OH- & converts them to non-ionized form

Complex: Involves 2 reversible equilibria; one involving water

20
Q

What Determines Effectiveness of a Buffer?

A

pKa relative to the pH of the solution

Concentration