Lecture 2 & 3: Water, pH & buffers Flashcards
Reversible Ionization
Results from nucleophilic attack by oxygen on a proton of an adjacent water molecule
H2O H+ + OH-
Keq: Equilibrium Constant
Ratio of [product] to [reactant]; water: ([H+][OH-])/[H2O] Keq=1 : [product] = [reactant] >1: [product] > [reactant] <1: [product] < [reactant] Keq of water: 1.8 x10^-16
Kw: Ion product of water
Kw = 1x 10^-14 = [H+][OH-]
If [H+] increases, then [OH-] decreases
pH: -log [H+]
Acid: release/donates protons
Base: accept protons
Acid-Base Disorders (Pathological)
Metabolic acidosis
Increase production of acid: lactic acidosis (overproduction of lactic acid), ketoacidosis (overproduction of ketone bodies), complications of drugs or other exposures
Loss of bicarbonate: diarrhea, altered kidney function
Small Changes in pH as a Signaling Mechanism
pH increase of 0.2 to 0.3 promotes cell proliferation, migration, assembly of actin filaments
High intracellular pH = cancer
Low intracellular pH = several neurodegenerative diseases
Strong acid vs. Weak Acid
Strong acid ionizes completely; one way arrow
Weak acid does not ionize completely; equilibrium arrow
Ka: A constant for any given acid
HA A- + H+
Ka= [H+][A-] / [HA]
If Ka is large, indicates a strong acid
Small pKa indicates a strong acid
Henderson-Hasselbalch Equation: pH & pKa relationship
pH = pKa + log [A-]/[HA]
Applies to weak acids & bases
Bases want to keep their protons
Henderson-Hasselbalch
When [HA]=[A-], the acid is 50% dissociated & undissociated; pH=pKa it is the pI (inflection point); point of max buffering capacity
Points on curve: different ratios of dissociated to undissociated weak acid
How is pKa useful?
Example: Aspirin
Aspirin is a weak acid with a pKa of 3.5
Absorbed through the cells lining the stomach (pH:1.5) & SI (pH:6)
Absorption requires passage through the pm; rate of absorption determined by the polarity of the molecule: charged and highly polar passes slowly & neutral hydrophobic ones pass rapidly
Aspirin more absorbed in stomach b/c more acidic & H+ in environment
Normal vs. Cancer Cells
Normal:
Intracellular pH: ~7.2
Extracellular pH: ~7.4
Cancer:
Intracellular pH: >/= 7.4
Extracellular pH: ~6.7-7.1
Selective Advantages for Cancer Cells
Favors: Proliferation Avoid apoptosis Migration and invasion Avoid immune detection
Consequences of Reverse pH Gradient in Cancer Cells
Example: Doxorubicin
pKa = 8.2; has an ionizable primary amine
Will have a higher percentage of the drug at pH<8.2 in the ionized form
Normal cells will take up a greater percentage of doxorubicin : more acidic in a normal cell than cancer cell (7.2<7.4)
How does the body compensate for the generation of acid due to metabolic activity?
Buffers
NOTE: Metabolism results in 13-22 moles of acid produced/day. If dissolved in water, pH would be <1.