Lecture 11: Bacterial Transcription Flashcards

Monday 21st October

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1
Q

What is the central dogma?

A

The idea that we go from the DNA to RNA to proteins

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2
Q

At which levels can gene expression be regulated?

A

At the level of transcription, at the level of translation, or both

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3
Q

Why is the mRNA called the sense strand?

A

Because it’s produced from the sense strand of DNA

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4
Q

What is the non-template strand called?

A

The sense strand

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5
Q

What is the template strand called?

A

The ‘antisense’ strand

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6
Q

In an RNA strand, what is the Thymine replaced with?

A

Uracil

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7
Q

What does what we call the sense strand depend on?

A

The context and the direction in which the gene is expressed

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8
Q

How can cytosine produce uracil?

A

Cytosine can undergo spontaneous deamination to produce uracil.

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9
Q

What happens when cytosine undergoes spontaneous deamination to produce uracil?

A

Mutations are introduced

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10
Q

How is the issue of cytosine undergoing sponatneous deamination to produce uracil corrected?

A

In DNA any Uracil will be removed by the enzyme uracil-DNA glycosylase, generating an abasic site, which is removed and repaired by DNA polymerase

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11
Q

What are the 3 main types of bacterial RNA?

A

mRNA

rRNA

tRNA

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12
Q

What does mRNA do in bacteria?

A

It encodes proteins

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13
Q

What are the 3 types of bacterial RNA syntheisised by in E coli?

A

single RNA Polymerase (In eukaryotes, there is a separate RNA polymerase for each class).

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14
Q

What does the operator control?

A

Whether the 5’ promoter is seen or not

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15
Q

What does the 5’ promoter do ?

A

It attracts and binds RNA polymerase

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16
Q

What does the 3’ terminator do?

A

it signals the stop point for transcription

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17
Q

Why can transcription and nucleus occur simultaneously in bacteria?

A

Because bacteria have no nucleus

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18
Q

What can the bacterial RNA polymerase be described as?

A
  • A multi sub unit protein complex, containing an α - alpha subunit, a β - beta subunit. an ω - omega subunit, and a σ - sigma subunit.
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19
Q

Describe the sigma subunit of RNA polymerase

A

It provides specificity and converts the core enzyme into a holoenzyme. It recognises specific promoters and initiates transcription.

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20
Q

Where does the RNA polymerase bind to DNA?

A

At promoter sequences

21
Q

Is it true that the core RNA polymerase binds to DNA non-specifically and can slide?

A

Yes

22
Q

What happens when the sigma subunit binds to the core RNA polymerase?

A

The RNA polymerase holoenzyme is directed to a gene promoter.

23
Q

What is recognised as a promoter?

A

The specific sequence of bases

24
Q
A
  • Purify DNA
  • Add holoenzyme

-Allow it to bind to a promoter

  • Add DNase
  • DNase will then digest all the accessible DNA
  • The DNA inside the holoenzyme is inacessbible to the DNase.
  • This protection provides us with a footprint that can help us identify promoters
25
Q

Is the aim of DNA footprinting partial degradation to generate a ladder of nicked intermediates?

A

Yes

26
Q

How do use DNA footprinting to work out what a promoter is and what it looks like?

A
  • Label one end of DNA with a radioactive phosphate (32P)
  • Add a very small amount of DNAse
  • The DNAse should create nicks and this will cause partial degradation and a ladder of nicked intermediates will be generated.

-You can then undergo electropheresis, which will cause large fragments to go to the top of the gel and small fragments at the bottom of the gel.

  • Add the holoenzyme RNA polymerase
  • The RNA polymerase will bind to the promoter
  • Add small amount of DNAse
  • The RNA polymerase will mean that the DNA is inacessible to the DNase
  • Where there’s no bands will tell you where the polymerase binds to the DNA
  • This is representative of the places where the polymerase binds to the promoter
27
Q

The stronger the promoter is to the concensus sequence…

A

… the stronger that promoter is

28
Q

What are the 2 promoter sequences?

A

TTGACA (-35)
TATAAT (-10)

29
Q

WHat is +1 usually?

A

An A or a G

30
Q

Which 2 regions are protected from DNAse by RNA polymerase (promoter binding sites)?

A

One is centred around -10 bp (-10 sequence) from the start of transcription and the other centred around -35 bp (-35 sequence) from the start of transcription (+1).

31
Q

What does the asymmetry of the promoter sequence provide?

A

Directionality

32
Q

Which strand of DNA can the -10, -35 and +1 consensus sequences be found on?

A

The sense strand

33
Q

In which direction is RNA built?

A

he 5’ → 3’ direction: new nucleotides are added at the 3’ end, using the ANTISENSE strand as a template

34
Q

What are the 3 stages of transcription in bacteria?

A

Initiation, where RNA polymerase holoenzyme binds to the promoter (with the help of the sigma factor), opens the DNA double helix and starts to transcribe.

Elongation, where the σ subunit disengages from the holoenzyme, and the core enzyme continues to make new RNA, with the help of RNA polymerase, by adding nucleotides in the 5’ to 3’ direction.

Termination, where the RNA polymerase core enzyme dissociates from the DNA, and transcription halts. This will either be through the intrinsic or rho-dependant process.

35
Q

Describe initiation

A
  • The core RNA polymerase binds to DNA non-specifically and can slide.
  • A σ subunit binds to the core polymerase and directs the polymerase holoenzyme to a promoter. The RNA polymerase will then bind to the -10 and -35 regions of the promoter.
  • The polymerase tries to unwind the DNA strands by pulling downstream DNA towards itself.
  • This is called the scrunching the DNA and the DNA actually ends up becoming tighter and harder to unwind. (abortive initiation)
  • Eventually there is sucess and the -10 region is opened, converting the CLOSED promoter complex to an OPEN promoter complex. Unlike the action of DNA helicase, this step does not involve the energy of ATP hydrolysis.
  • 12 to 15 bp are unwound, from within the -10 region to position +2 or +3. The transcriptional start site is now exposed.
  • RNA polymerase now makes an RNA copy from the template strand, using base pairing rules (G with C, A with U). Unlike DNA Pol, RNA polymerase does not require a primer.
  • After about 10 nucleotides of RNA synthesis, the σ factor is exposed and disengages. The core RNA polymerase can now elongate the new RNA.
36
Q

Describe elongation

A
  • During elongation, RNA polymerase is highly processive and adds nucleotides in the 5’ to 3’ prime direction
  • The RNA polymerase unwinds the DNA ahead of it and rewinds it behind as it progresses
37
Q

Is the proofreading of RNA polymerase as good as in DNA polymerase?

A

No

38
Q

Do we tolerate a high level of errors with RNA polymerase?

A

Yes

39
Q

Why is such a high error rate tolerated with RNA polymerase?

A

DNA errors are transmitted to progeny cells: they are stringently repaired.
RNA errors mean that some transcripts may be mutated, but the majority are not.

If the transcript encodes a protein, them most of that protein will be fine, but a small subpopulation may be mutant – and can probably be tolerated.

40
Q

What are the 2 mechanisms of terminateing bacterial trasncription?

A

Rho (ρ)-independent

ρ -dependent

(In both cases, the functioning signals are recognised not in the DNA template, but in the newly synthesised RNA.
)

41
Q

Describe Rho (ρ)-independent

A
  • A terminator sequence in the RNA is recognised. This sequence will end with a series of Uracils.
  • This causes the RNA polymerase to pause, destabilizing its interaction with the DNA, leading to the release of the newly synthesized RNA and the dissociation of the RNA polymerase from the DNA.
42
Q

Describe ρ -dependent

A

requires ρ protein to break the RNA:DNA duplex in the transcription bubble

43
Q

What is Rifampicin?

A

an inhibitor of prokaryotic transcription

44
Q

How does Rifampicin inhibit prokaryotic transcription?

A

Rifampicin inhibits RNA Pol by binding tightly to the RNA exit channel.

It therefore affects initiation (but does not affect RNA Pol that is already at the elongation stage).

45
Q

Why does RNA polymerase bend the DNA duplex?

A

Because bending allows the DNA duplex to be opened more easily.

46
Q

After bacterial transcription, does further processing, like splicing, need to occur?

A

No

47
Q

Are the -35 and -10 promoter regions located upstream of the transcription site?

A

Yes, they are located before the transcription site and are recognised by RNA polymerase.

48
Q
A