lec2 glycolysis Flashcards

1
Q

the only metabolite that begins its digestion from the mouth is…….

A

CHO

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2
Q

the CHO is digested in the mouth via………. enzyme

A

a-amylase enzyme

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3
Q

the a-amylase enzyme breaks …………. resulting in a mixture of ……….. and ………

A

a(1>4)bonds of starch

short branched and unbranched oligosaccharides (dextrin)

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4
Q

Humans can not digest cellulose. Why?

A

Salivary β-amylase that breaks β glycosidic
bonds are not found in humans, therefore humans
cannot digest cellulose.

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5
Q

there is No digestion of carbohydrates In the stomach why?

A

because high acidity inactivates salivary amylase.

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6
Q

……..it is an enzyme continues the digestion of CHO

A

Pancreatic α-amylase

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7
Q

The final digestive processes occur at………….

A

jejunum

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8
Q

write a short note about lactose intolerance.

A

 due to genetic lactase deficiency.
Any deficiency in disaccharides activity of intestinal mucosa causes passage of undigested CHO into large intestine causing osmotic diarrhea→ bacterial fermentation of CHO to 2 or 3-carbon compounds + CO2 + H2 gas→ abdominal cramps and flatulence.
 Treatment: remove lactose and give lactase pills, Eating yoghurts, cheeses and green vegetables to ensure adequate calcium intake.

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9
Q

Glycolysis means…………….

A

oxidation of glucose to give pyruvate (in the presence of oxygen) or lactate (in the absence of oxygen)

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10
Q

the glycolysis occurs in …….

A

cytosol

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11
Q

the end product of the 1st step in glycolysis is……

A

glucose 6-phosphate

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12
Q

the 1st step in glycolysis is a reversible state

T or F?

A

F

irreversible

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13
Q

the initial substrate in 1st step is…….

A

glucose

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14
Q

the enzyme used in 1st step is ………

A

kinase enzyme (hexokinase or glucokinase)

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15
Q

write a short note about 1st step

A

Phosphorylation of glucose into glucose 6-phosphate, using an ATP and a kinase enzyme (glucokinase or hexokinase),
(Irreversible step).

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16
Q

the 2nd step is the irreversible step

T or F?

A

F reversible

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17
Q

the initial substrate in the 2nd step is…….

A

glucose 6-phosphate

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18
Q

the enzyme used in the 2nd step is………

A

phosphohexose isomerase

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19
Q

the product in the 2nd step is……

A

fructose 6-phosphate

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20
Q

write a short note about the 2nd step

A

Isomerization of glucose 6-phosphate into fructose 6-

phosphate by phosphohexose isomerase (reversible step).

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21
Q

the 3rd step is the irreversible step

T or F?

22
Q

the initial substrate in the 3rd step is…….

A

fructose 6-phosphate

23
Q

the product in the 3rd step is……

A

fructose1,6 -bisphosphate

24
Q

the enzyme used in the 3rd step is………

A

phosphofructokinase-1

25
write a short note about the 3rd step
Phosphorylation of fructose 6-phosphate into fructose 1,6-bisphosphate with phosphofructokinase-1 (PFK-1), (Irreversible step, rate limiting step).
26
what is the name of the process that occurs in step 4?
cleavage
27
the initial substrate in the 4th step is.......
fructose1,6-bisphosphate
28
the product in the 4th step is......
dihydroxyacetone phosphate + glyceraldehyde-3 -phosphate
29
the 4th step is the irreversible step | T or F?
F reversible
30
the enzyme used in the 4th step is.........
aldolase
31
.............it is an enzyme used in the cleavage
aldolase
32
write a short note about the 4th step
Cleavage of fructose 1,6-bisphosphate by aldolase to dihydroxyacetone phosphate and glyceraldehyde-3-phosphate, (reversible step).
33
the enzyme used in the 5th step is.........
triosephosphate isomerase
34
the product in the 5th step is......
2 molecules of glyceraldehyde 3-phosphate
35
the initial substrate in the 5th step is.......
dihydroxyacetone phosphate
36
write a short note about the 5th step
Isomerization of dihydroxyacetone phosphate into another glyceraldehyde 3-phosphate by triose phosphate isomerase. So, the result is 2 molecules of glyceraldehyde-3-phosphate.
37
the enzyme used in the 6th step is.........
glyceraldehyde 3-phosphate dehydrogenase
38
write a short note about the 6th step
Oxidation of glyceraldehyde-3-phosphate to 1,3 bisphosphoglycerate (1,3 BPG) by glyceraldehyde-3-phosphate dehydrogenase.
39
the product in the 6th step is......
2 MOLECULES OF 1,3-bisphosphoglycerate
40
the initial substrate in the 7th step is.......
2 MOLECULES OF 1,3 bisphposphoglycerate +ADP
41
the product in the 7th step is......
2 MOLECULES OF 3-phosphoglycerat + 2ATP
42
write a short note about the 7th step
Dephosphorylation; formation of 3-phosphoglycerate and ATP from 1,3 BPG and ADP. • 1,3 BPG is a high energy phosphate compound used in the synthesis of ATP in a reaction catalyzed by phosphoglycerate kinase. • This reaction gives 2 ATP and 2 compounds of 3-PG. (substrate-level phosphorylation). Unlike most other kinases, the reaction is reversible.
43
the 4th step is the irreversible step | T or F?
F | UNLIKE most other kinases, the reaction in step 7 is reversible.
44
write a short note about the 8th step
The shift of the phosphate group from C-3 to C-2 to form 2-PG by Phosphoglycerate mutase, (reversible step).
45
the enzyme used in the 8th step is.........
Phosphoglycerate mutase
46
what dose the enolase enzyme responsible for?
dehydration of 2PG to form phosphoenolpyruvate
47
the enzyme used in the 9th step is.........
enolase
48
.......... is a high energy phosphate compound
phosphoenolpyruvate
49
the enzyme used in the 10th step is.........
Pyruvate kinase
50
the 10th step is the rreversible step | T or F?
F irrreversible
51
the product in the 10th step is......
2 molecules of pyruvate | and 2 ATP